Question

需要帮助。基于此查询，我有2个问题。

SELECT cdd.FieldID,cdd.PlanTypeID,pt.IsFinancial            
FROM ClientDataDictionary cdd
    INNER JOIN #tblPlanTypes pt ON cdd.PlanTypeID = pt.PlanTypeID
    INNER JOIN ClientDataDictionaryFieldType cddftype
    ON cdd.FieldId = cddftype.FieldID AND cdd.PlanTypeId = cddftype.PlanTypeID
    WHERE cdd.ClientId = @ClientID AND cdd.IsHidden = 0
    AND cddftype.FieldTypeID = 4 
    AND cddftype.FieldID = cddftype.ParentFieldIDSectionTitle 
    AND  (SELECT COUNT(cddftype2.FieldID)
              FROM ClientDataDictionaryFieldType  cddftype2
              Where cddftype2.ParentFieldIDSectionTitle = cdd.FieldID
              AND cddftype2.PlanTypeID = cdd.PlanTypeID
              AND EXISTS(Select tbl.FieldID From #tblSelectedFields tbl
                          Where tbl.FieldID = cddftype2.FieldID AND tbl.PlantypeID =cdd.PlanTypeID COLLATE SQL_Latin1_General_CP1_CI_AS)
              ) != 0 COLLATE SQL_Latin1_General_CP1_CI_AS

我在哪里将COLLATE关键字放在此查询中？我知道临时表有不同的整理“类型”。
我尝试使用COLLATE DATABASE_DEFAULT，但错误仍然存在。这会解决问题吗？

请在这里帮助我。谢谢！

[更新1] ClientID设置为UNIQUEIDENTIFIER数据类型。

[更新2] 这是表格定义

#tblPlanTypes

PlanTypeId nvarchar(50),  
PlanType nvarchar(max),  
Prefix NVARCHAR(10),  
IsFinancial BIT,  
TotalCount BIGINT,  
PlanCount BIGINT

ClientDataDictonary

[ClientDataDictionaryId] [uniqueidentifier] NOT NULL ROWGUIDCOL CONSTRAINT      [DF_ClientDataDictionary_ClientDataDictionaryId] DEFAULT (newid()),
[ClientId] [uniqueidentifier] NOT NULL,
[PlanTypeId] [uniqueidentifier] NULL,
[FieldId] [nvarchar] (255) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
[FieldText] [nvarchar] (max) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
[FieldType] [nvarchar] (50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
[DefaultValue] [nvarchar] (255) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
[HelpText] [nvarchar] (512) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
[IsHidden] [bit] NULL CONSTRAINT [DF_ClientDataDictionary_IsHidden] DEFAULT ((0)),
[IsSummable] [bit] NULL,
[IsRequired] [bit] NULL,
[IsContractRenewal] [bit] NULL,
[HasAlert] [bit] NULL CONSTRAINT [DF_ClientDataDictionary_HasAlert] DEFAULT ((0)),
[AlertMessage] [nvarchar] (512) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
[CentralLanguageId] [uniqueidentifier] NOT NULL,
[LookupTypeName] [varchar] (500) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
[RowVersion] [timestamp] NULL,
[LastUpdated] [datetime] NULL CONSTRAINT [DF_ClientDataDictionary_LastUpdated] DEFAULT (getutcdate()),
[Sequence] [int] NULL

ClientDataDictionaryFieldType

[ClientDataDictionaryFieldTypeID] [uniqueidentifier] NOT NULL CONSTRAINT [DF_ClientDataDictionaryFieldType_ClientDataDictionaryFieldType] DEFAULT (newid()),
[PlanTypeID] [uniqueidentifier] NULL,
[FieldID] [nvarchar] (255) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
[FieldTypeID] [int] NULL,
[ParentFieldIDSectionTitle] [nvarchar] (255) COLLATE SQL_Latin1_General_CP1_CI_AS NULL

#tblSelectedFields

FieldID nvarchar(255),  
PlanTypeID UniqueIdentifier,  
FieldText nvarchar(MAX),  
sequence int,  
FieldType nvarchar(100),  
IsFinancial bit

[更新3]

尝试了@Mack的建议，但出现了一个新的错误。 Expression type uniqueidentifier is invalid for COLLATE clause.这是由具有uniqueidentifier数据类型的@ClientID引起的。有什么建议吗？

Answer 1

首先 - 如果您在示例中包含表格的描述，那么这里的人们将能够更快地为您提供帮助。

第二个调试此查询自己将其分解为逻辑部分（分隔任何子查询，一次删除一个表），然后从每个逻辑部分中删除where子句，直到查询工作，这将帮助您确定原因问题，请记住，join子句也可能是问题所在。

最后，下面的代码将允许您确定要查询的每个列的排序规则类型，它来自Pinal Dave的this article

USE yourdb
GO
SELECT name, collation_name
FROM sys.columns
WHERE OBJECT_ID IN ( SELECT OBJECT_ID
                     FROM sys.objects
                     WHERE type = 'U'
                     AND name = 'yourtable')
AND name IN('yourcolumn1','yourcolumn2',.....,'yourcolumnX')

感谢表格定义...... 乍一看，你的整理问题在于这个领域

PlanTypeId nvarchar（50）

此联接中使用的

：INNER JOIN #tblPlanTypes pt ON cdd.PlanTypeID = pt.PlanTypeID 如果您将COLLATE应用于联接，则应解决问题。

Answer 2

您需要在比较/连接运算符中的textual（char，nchar，varchar，nvarchar）字段名称之后放置COLLATE关键字 - 'alias1.txtfield1 COLLATE something = alias2.txtfield2 COLLATE something'。将COLLATE与整数字段一起使用是没有意义的（我希望你的ID是整数种？）。

在等于操作中无法解决“SQL_Latin1_General_CP1_CI_AS”和“Latin1_General_CI_AS”之间的排序规则冲突

2 个答案: