Java递归插入排序?

时间:2011-11-08 22:20:15

标签: java sorting recursion insertion-sort

所以我试图将下面的代码变成递归方法,插入排序,但是尽管我尝试的却不能。任何人都可以帮助我吗?

public static void insertionSort(int[] array){
    for (int i = 1; i < array.length; i++){
        int j = i;
        int B = array[i];
        while ((j > 0) && (array[j-1] > B)){
            array[j] = array[j-1];
            j--;
        }
        array[j] = B;
    }
}

编辑: 我在考虑这样的事情,但对我来说看起来并不是很复杂......

public static void insertionSort(int[] array, int index){
    if(index < array.length){
        int j = index;
        int B = array[index];
        while ((j > 0) && (array[j-1] > B)){
            array[j] = array[j-1];
            j--;
        }
        array[j] = B;
        insertionSort(array, index + 1);
    }
}

7 个答案:

答案 0 :(得分:13)

试试这个:

public class RecursiveInsertionSort {
    static int[] arr = {5, 2, 4, 6, 1, 3};
    int maxIndex = arr.length;

    public static void main(String[] args) {
        print(arr);
        new RecursiveInsertionSort().sort(arr.length);
    }

    /*
      The sorting function uses 'index' instead of 'copying the array' in each    
      recursive call to conserve memory and improve efficiency.
    */
    private int sort(int maxIndex) {
        if (maxIndex <= 1) {
            // at this point maxIndex points to the second element in the array.
            return maxIndex;
        }

        maxIndex = sort(maxIndex - 1);  // recursive call

        // save a copy of the value in variable 'key'.
        // This value will be placed in the correct position
        // after the while loop below ends.
        int key = arr[maxIndex];  

        int i = maxIndex - 1;

        // compare value in 'key' with all the elements in array 
        // that come before the element key. 
        while ((i >= 0) && (arr[i] > key)) {
            arr[i+1] = arr[i];
            i--;
        }
        arr[i+1] = key;
        print(arr);
        return maxIndex + 1;
    }

    // code to print the array on the console.
    private static void print(int[] arr) {
        System.out.println();
        for (int i : arr) {
            System.out.print(i + ", ");
        }
    }
}

答案 1 :(得分:3)

public static void insertionSort(int[] array, int index) {
    if(array.length == index + 1) return;

    insertionSort(array, index + 1);

    // insert array[index] into the array

}

答案 2 :(得分:3)

您可以尝试使用此代码。它工作正常。

public static int[] InsertionSort(int[] dizi, int n) 
{
    int i;
    if (n < 1) {
        InsertionSort(dizi, n - 1);
    } 
    else {

        int key = dizi[n];
        i = n - 1;

        while (i >= 0 && dizi[i] > key) {
            dizi[i + 1] = dizi[i];
            i = i - 1;
        }

        dizi[i + 1] = key;
    }

    return dizi;
}

答案 3 :(得分:1)

对于递归算法,我们从整个数组A [1..n]开始,我们对A [1..n-1]进行排序,然后将A [n]插入正确的位置。

public int[] insertionSort(int[] array)
{
   //base case
   if(array.length==1) return new int[]{ array[0] };

   //get array[0..n-1] and sort it
   int[] arrayToSort = new int[array.length - 1]{ };
   System.arraycopy(array, 0, arrayToSort, 0, array.length -1);
   int[] B = insertionSort(arrayToSort);

   //now, insert array[n] into its correct position
   int[] C = merge(B, array[array.length - 1]);

   return C;
}

private int[] merge(int[] array, int n)
{ 
   int[] arrayToReturn = new int[array.length + 1] {};
   int j = array.length-1;
   while(j>=0 && n <= array[j])
   {
      arrayToReturn[j+1]=array[j;
      j--;
   }

   arrayToReturn[j] = 
}

答案 4 :(得分:0)

通过提供ele作为整数数组来尝试以下代码,sortedIndex =第一个元素的索引和index =第二个元素的索引:

public static void insertionSort(int[] ele, int sortedIndex, int index) {
    if (sortedIndex < ele.length) {
        if (index < ele.length) {
            if (ele[sortedIndex] > ele[index]) {
                ele[sortedIndex] += ele[index];
                ele[index] = ele[sortedIndex] - ele[index];
                ele[sortedIndex] = ele[sortedIndex] - ele[index];
            }
            insertionSort(ele, sortedIndex, index + 1);
            return;
        }
        if (index == ele.length) {
            sortedIndex++;
        }
        insertionSort(ele, sortedIndex, sortedIndex + 1);
    }
}

答案 5 :(得分:0)

var indexPath: IndexPath {
    get {
        // Return the internalIndexPath when we ask for the indexPath.
        return internalIndexPath
    }
    set {
        // Set the internalIndexPath to the value supplied to indexPath.
        internalIndexPath = newValue

        // Calculate the number of points on a post.
        let points = model.dataContent[self.indexPath.row]["upVotes"].intValue - model.dataContent[self.indexPath.row]["downVotes"].intValue
        pointsLabel.text = "\(points)"
        // Show the upload time of the post.
        let uploadTimeString = model.dataContent[self.indexPath.row]["timestamp"].stringValue

        let date = DateFormatter.formatter.date(from: uploadTimeString)
        let dateString = date?.relativeTime
        uploadTime.text = dateString

        if let type = MediaType(rawValue: model.dataContent[self.indexPath.row]["type"].stringValue) {
            self.type = type
        }

        /// Adjust up/down arrows
        if (model.dataContent[self.indexPath.row]["userVote"]["likeState"] != nil) {
            switch model.dataContent[self.indexPath.row]["userVote"]["likeState"].stringValue {
            case LikeState.Likes.rawValue:
                thumbsUpButton.isSelected = true
                thumbsDownButton.isSelected = false
            case LikeState.Dislikes.rawValue:
                thumbsUpButton.isSelected = false
                thumbsDownButton.isSelected = true
            case LikeState.Neither.rawValue:
                thumbsUpButton.isSelected = false
                thumbsDownButton.isSelected = false
            default:
                break
            }
        } else {
            thumbsUpButton.isSelected = false
            thumbsDownButton.isSelected = false
        }
    }
}

答案 6 :(得分:-1)

public class test
{
   public static void main(String[] args){
        test h = new test();

        int a[] = { 5, 8, 9, 13, 65, 74, 25, 44, 67, 2, 1 };

        h.ins_rec(a, a.length-1);

        for(int i=0; i<a.length; i++)
          log(a[i]);

    }



    void ins_rec(int a[], int j){
    if( j == 0 ) return;

    ins_rec(a, j - 1);
    int key = a[ j ];
    sort(a, key, j - 1);

    }



    void sort(int a[], int key, int i){
    if( (i < 0) || (a[i] < key) ) {
      a[ i + 1 ] = key;
      return;
    }

    a[ i + 1 ] = a[ i ];
    sort(a, key, i - 1);

    }



private static void log(int aMessage){
    System.out.println("\t\t"+aMessage);
  }
}