Question

快速提问。我有一个jPanelSquareGrid，在一些正方形中有标签（图像标签，代表棋子）

现在，当我将一个棋子拖放到某个方格时，我想检查一下是否还有棋子。

有没有人知道我如何检查广场内现有物品的jPanelSquareGrid？

提前致谢！

这是我的鼠标事件

   public void mousePressed(MouseEvent e)
{
    chessPiece = null;
    Component c =  chessBoard.findComponentAt(e.getX(), e.getY());

    if (c instanceof JPanel) return;

    Point parentLocation = c.getParent().getLocation();
    xAdjustment = parentLocation.x - e.getX();
    yAdjustment = parentLocation.y - e.getY();
    chessPiece = (JLabel)c;
    chessPiece.setLocation(e.getX() + xAdjustment, e.getY() + yAdjustment);

    layeredPane.add(chessPiece, JLayeredPane.DRAG_LAYER);
    layeredPane.setCursor(Cursor.getPredefinedCursor(Cursor.MOVE_CURSOR));
}

/*
**  Move the chess piece around
*/
public void mouseDragged(MouseEvent me)
{
    if (chessPiece == null) return;

    //  The drag location should be within the bounds of the chess board

    int x = me.getX() + xAdjustment;
    int xMax = layeredPane.getWidth() - chessPiece.getWidth();
    x = Math.min(x, xMax);
    x = Math.max(x, 0);

    int y = me.getY() + yAdjustment;
    int yMax = layeredPane.getHeight() - chessPiece.getHeight();
    y = Math.min(y, yMax);
    y = Math.max(y, 0);

    chessPiece.setLocation(x, y);
 }

/*
**  Drop the chess piece back onto the chess board
*/
public void mouseReleased(MouseEvent e)
{
    layeredPane.setCursor(null);

    if (chessPiece == null) return;

    //  Make sure the chess piece is no longer painted on the layered pane

    chessPiece.setVisible(false);
    layeredPane.remove(chessPiece);
    chessPiece.setVisible(true);

    //  The drop location should be within the bounds of the chess board

    int xMax = layeredPane.getWidth() - chessPiece.getWidth();
    int x = Math.min(e.getX(), xMax);
    x = Math.max(x, 0);

    int yMax = layeredPane.getHeight() - chessPiece.getHeight();
    int y = Math.min(e.getY(), yMax);
    y = Math.max(y, 0);

    Component c =  chessBoard.findComponentAt(x, y);

    if (c instanceof JLabel)
    {
        Container parent = c.getParent();
        parent.remove(0);
        parent.add( chessPiece );
        parent.validate();
    }
    else
    {
        Container parent = (Container)c;
        parent.add( chessPiece );
        parent.validate();
    }
}

public void mouseClicked(MouseEvent e) {}
public void mouseMoved(MouseEvent e) {}
public void mouseEntered(MouseEvent e) {}
public void mouseExited(MouseEvent e) {}

jPanelSquare由这个类组成：

class JPanelSquare extends JPanel {
private int rank;
private int file;
private JLabel chessPiece = null;

public JPanelSquare(int rank, int file, Color bkgrnd) {
    this.rank = rank;
    this.file = file;
    setBackground(bkgrnd);
    setLayout(new GridBagLayout());
}

public int getRank() {
    return rank;
}
public int getFile() {
    return file;
}

@Override
public Component add(Component c) {
    chessPiece = (JLabel)c;
    return super.add(c);
}

@Override
public void remove(Component comp) {
    chessPiece = null;
    super.remove(comp);
}

public JLabel getChessPiece() {
    return chessPiece;
}

}

Answer 1

从stackoverflow的某个地方获得了这个类

在我看来，您正在组合来自两个不同来源的代码。

我从我发布的ChessBoard示例中识别出我的拖动代码。

在我的代码中，很容易判断一个棋子是否已经存在，因为代码已经在mouseReleased代码中执行了。方法结尾处的“if语句”是什么。

我不知道你从哪里得到其他代码所以我不能对此发表评论。

我建议你坚持使用一种解决方案。

检查jPanelSquare的项目

1 个答案: