Question

在我的注册表单中使用ajax + php。有2个验证：JS端前端和PHP端后端。在PHP方面创建了名为response的特殊函数：它将PHP端错误作为JSON数据发送。

问题是我无法从PHP方面得到任何回复。

分析firebug中的页面：收到错误消息responseData is null。（responseData = jQuery.parseJSON(data)）

JS部分看起来像

  //check the form is not currently submitting
  if ($(this).data('formstatus') !== 'submitting') {

 var form = $(this),
    formData = form.serialize() + '&formID=' + form.attr('id'),
    formUrl = form.attr('action'),
    formMethod = form.attr('method');



 //add status data to form
 form.data('formstatus', 'submitting');

 if (validate()) {
    //send data to server for validation
    $.ajax({
       url: formUrl,
       type: formMethod,
       data: formData,
       success: function (data) {

          //setup variables
          var responseData = jQuery.parseJSON(data),
             cl, text;

          //response conditional
          switch (responseData.status) {
          case 'error':
             cl = 'error';
             text = responseData.message;
             break;
          case 'success':
             cl = 'success';
             text = 'Qeydiyyat uğurla başa çatdı';
             break;
          }


          $.notifyBar({
             cls: cl,
             html: text
          });

       }
    });

 }
 form.data('formstatus', 'idle');


 }

这是PHP部分

    <?php
require '../common.php';

function checkIfEmailExists($email, $stmt)
{
        if ($stmt = $db->prepare("SELECT id FROM TABLE WHERE email=? LIMIT 1")) {
                $stmt->bind_param("s", $email);
                $stmt->execute();
                $stmt->bind_result($count);
                $stmt->close();
        }

        return ($count > 0 ? true : false);
}


if ($_POST['formID'] == 'signup_form') {
        // Setting vars
        $lname        = $_POST['lname'];
        $fname        = $_POST['fname'];
        $mname        = $_POST['mname'];
        $email        = $_POST['email'];
        $pass         = $_POST['pass'];
        $confirm_pass = $_POST['confirm_pass'];

        //===================== 
        //Server side validation >>


        //First name, middle name, last name check >>
        if (!$lname) {
                response('error', 'Familiyanı daxil edin');
        }
        if (!$fname) {
                response('error', 'Adı daxil edin');
        }
        if (!$mname) {
                response('error', 'Atanızın adını daxil edin');
        }
        //<<

        //Pass check >>
        if (strlen($pass) > 2) {
                if ($pass == $confirm_pass) {
                        return true;
                } else {
                        response('error', 'Şifrənin təkrarlanmasında səhv');
                }
        } else {
                response('error', 'Şifrədə simvolların sayı 4-dən çox olmalıdır');
        }

        //<<


        //email validation >>
        if (filter_var($email, FILTER_VALIDATE_EMAIL)) {
                if (!checkIfEmailExists($email, $stmt)) {
                        return true;
                } else {
                        response('error', 'Bu ünvanla qeydiyyata alınmış başqa istifadəçi var.');
                }
        } else {
                response('error', 'Email ünvanını düzgün daxil edin');
        }

        //<<

        // Create statement object
        $stmt = $db->stmt_init();

        // Create a prepared statement
        if ($stmt->prepare("INSERT INTO `users` (`fname`, `mname`, `lname`, `email`, `pass`, `reg_dt`) VALUES (?, ?, ?, ?, ?, NOW())")) {
                // Binding vars

                $rc = $stmt->bind_param('sssss', $fname, $lname, $mname, $email, $pass) or die('bind_param() failed: ' . htmlspecialchars($stmt->error));

                // Execute query
                $rc = $stmt->execute();
                if ($rc) {
                        response('success', 'Qeydiyyat uğurla başa çatdı');
                } else {
                        response('error', htmlspecialchars($stmt->error));
                }


                // Close statement object
                $stmt->close();

        } else {
                response('error', htmlspecialchars($dv->error));
        }



}
else {response('error', 'Qeydiyyatda problem');}

        //return json response
        function response($status, $message)
        {
                $data = array(
                        'status' => $status,
                        'message' => $message
                );
                echo json_encode($data);
                die();
        }
?>

Answer 1

您需要添加

dataType: "json",

在$ .Ajax方法中。

Ajax没有得到PHP方面的响应

1 个答案: