Question

请详细说明这种情况

现在我有两个阵列，附近的地方有纬度和经度，也有用户位置latiude和longiude现在我想计算用户位置和附近地点之间的距离，并希望在列表视图中显示它们。

我知道有一种计算距离的方法

public static void distanceBetween (double startLatitude, double startLongitude, double endLatitude, double endLongitude, float[] results);

现在问题是如何在这个方法中传递这两个具有近纬度和长度的数组并得到距离数组。

Answer 1

http://developer.android.com/reference/android/location/Location.html

查看distanceTo或distanceBetween。您可以从纬度和经度创建位置对象：

Location locationA = new Location("point A");

locationA.setLatitude(latA);
locationA.setLongitude(lngA);

Location locationB = new Location("point B");

locationB.setLatitude(latB);
locationB.setLongitude(lngB);

float distance = locationA.distanceTo(locationB);

或

private double meterDistanceBetweenPoints(float lat_a, float lng_a, float lat_b, float lng_b) {
    float pk = (float) (180.f/Math.PI);

    float a1 = lat_a / pk;
    float a2 = lng_a / pk;
    float b1 = lat_b / pk;
    float b2 = lng_b / pk;

    double t1 = Math.cos(a1) * Math.cos(a2) * Math.cos(b1) * Math.cos(b2);
    double t2 = Math.cos(a1) * Math.sin(a2) * Math.cos(b1) * Math.sin(b2);
    double t3 = Math.sin(a1) * Math.sin(b1);
    double tt = Math.acos(t1 + t2 + t3);

    return 6366000 * tt;
}

Answer 2

试用此代码。这里我们有两个经度和纬度值和selected_location.distanceTo（near_locations）函数返回这些位置之间的距离（米）。

Location selected_location=new Location("locationA");
            selected_location.setLatitude(17.372102);
            selected_location.setLongitude(78.484196);
Location near_locations=new Location("locationB");
            near_locations.setLatitude(17.375775);
            near_locations.setLongitude(78.469218);
double distance=selected_location.distanceTo(near_locations);

这里“距离”是locationA＆amp; amp; locationB（米）（

）

Answer 3

只有一个用户位置，因此您可以迭代附近地方列表可以调用distanceTo()函数来获取距离，如果您愿意，可以存储在数组中。

根据我的理解，distanceBetween()适用于远处的地方，它的输出是WGS84椭圆体。

Answer 4

    private static Double _MilesToKilometers = 1.609344;
    private static Double _MilesToNautical = 0.8684;


    /// <summary>
    /// Calculates the distance between two points of latitude and longitude.
    /// Great Link - http://www.movable-type.co.uk/scripts/latlong.html
    /// </summary>
    /// <param name="coordinate1">First coordinate.</param>
    /// <param name="coordinate2">Second coordinate.</param>
    /// <param name="unitsOfLength">Sets the return value unit of length.</param>
    public static Double Distance(Coordinate coordinate1, Coordinate coordinate2, UnitsOfLength unitsOfLength)
    {

        double theta = coordinate1.getLongitude() - coordinate2.getLongitude();
        double distance = Math.sin(ToRadian(coordinate1.getLatitude())) * Math.sin(ToRadian(coordinate2.getLatitude())) +
                       Math.cos(ToRadian(coordinate1.getLatitude())) * Math.cos(ToRadian(coordinate2.getLatitude())) *
                       Math.cos(ToRadian(theta));

        distance = Math.acos(distance);
        distance = ToDegree(distance);
        distance = distance * 60 * 1.1515;

        if (unitsOfLength == UnitsOfLength.Kilometer)
            distance = distance * _MilesToKilometers;
        else if (unitsOfLength == UnitsOfLength.NauticalMiles)
            distance = distance * _MilesToNautical;

        return (distance);

    }

Answer 5

distanceTo将为您提供两个给定位置ej target.distanceTo（目的地）之间的距离。

distanceBetween也给你距离，但它会将距离存储在float数组中（results [0]）。 doc说如果结果长度为2或更大，则初始方位存储在结果[1]中。如果结果的长度为3或更大，则最终方位存储在结果[2]

中

希望这有助于

我已经使用distanceTo来获得从A点到B点的距离我觉得这是要走的路。

Answer 6

public double distance(Double latitude, Double longitude, double e, double f) {
        double d2r = Math.PI / 180;

        double dlong = (longitude - f) * d2r;
        double dlat = (latitude - e) * d2r;
        double a = Math.pow(Math.sin(dlat / 2.0), 2) + Math.cos(e * d2r)
                * Math.cos(latitude * d2r) * Math.pow(Math.sin(dlong / 2.0), 2)
        double c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1 - a));
        double d = 6367 * c;
                return d;

    }

Answer 7

我想自己实现这一点，我最终阅读了Great-circle distance formula上的Wikipedia页面，因为没有足够的可读性可供我用作基础。

C＃示例

    /// <summary>
    /// Calculates the distance between two locations using the Great Circle Distance algorithm
    /// <see cref="https://en.wikipedia.org/wiki/Great-circle_distance"/>
    /// </summary>
    /// <param name="first"></param>
    /// <param name="second"></param>
    /// <returns></returns>
    private static double DistanceBetween(GeoLocation first, GeoLocation second)
    {
        double longitudeDifferenceInRadians = Math.Abs(ToRadians(first.Longitude) - ToRadians(second.Longitude));

        double centralAngleBetweenLocationsInRadians = Math.Acos(
            Math.Sin(ToRadians(first.Latitude)) * Math.Sin(ToRadians(second.Latitude)) +
            Math.Cos(ToRadians(first.Latitude)) * Math.Cos(ToRadians(second.Latitude)) *
            Math.Cos(longitudeDifferenceInRadians));

        const double earthRadiusInMeters = 6357 * 1000;

        return earthRadiusInMeters * centralAngleBetweenLocationsInRadians;
    }

    private static double ToRadians(double degrees)
    {
        return degrees * Math.PI / 180;
    }

计算两个地理位置之间的距离

7 个答案: