如何在Java代码/ Web服务中处理SocketTimeoutException

时间:2011-11-08 10:10:17

标签: java web-services cxf

这是我的方法代码,如下所示

实际上这是一种Web服务方法。

public Response getData(ServiceRequest request)
{
    try
    {
        final   boolean toProceedorNot = validate(legdata);
        if (!toProceedorNot) {
            status.setErrorText(errorText);
            return response;
        } 
        else {
            // Some Processing is done here
            response.setMessage(result);
        }                           
    }

    catch(Exception e)
    {
        errorText = e.getMessage().toString();
        status.setErrorText(errorText);
        response.setStatus(status);
    }

    return response;
}

如果执行Method需要更长的时间,Apache CXF Framework将抛出SocketTimeoutException

at java.lang.Thread.run(Thread.java:662)
    Caused by: java.net.SocketTimeoutException: Read timed out
    at java.net.SocketInputStream.socketRead0(Native Method)
    at java.net.SocketInputStream.read(SocketInputStream.java:129)
    at java.io.BufferedInputStream.fill(BufferedInputStream.java:218)
    at java.io.BufferedInputStream.read1(BufferedInputStream.java:258)
    at java.io.BufferedInputStream.read(BufferedInputStream.java:317)
    at sun.net.www.http.HttpClient.parseHTTPHeader(HttpClient.java:695)
    at sun.net.www.http.HttpClient.parseHTTP(HttpClient.java:640)
    at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1195)
    at java.net.HttpURLConnection.getResponseCode(HttpURLConnection.java:379)
    at org.apache.cxf.transport.http.HTTPConduit$WrappedOutputStream.handleResponseInternal(HTTPConduit.java:2034)
    at org.apache.cxf.transport.http.HTTPConduit$WrappedOutputStream.handleResponse(HTTPConduit.java:2013)
    at org.apache.cxf.transport.http.HTTPConduit$WrappedOutputStream.close(HTTPConduit.java:1938)
    at org.apache.cxf.transport.AbstractConduit.close(AbstractConduit.java:66)
    at org.apache.cxf.transport.http.HTTPConduit.close(HTTPConduit.java:626)
    at org.apache.cxf.interceptor.MessageSenderInterceptor$MessageSenderEndingInterceptor.handleMessage(MessageSenderInterceptor.java:62)

我的问题是,即使抛出了SocketTimeoutException,它也不会进入异常块。

我不确定是否应该由谁(客户端或Webservices实现方法内部)处理此异常

但作为Web服务提供商,请告诉我如何处理此异常?

0 个答案:

没有答案