我正在做一些SQL选择查询,并希望将我的UTC日期时间列转换为本地时间,以便在我的查询结果中显示为本地时间。注意,我不希望通过代码进行这种转换,而是在我对我的数据库进行手动和随机SQL查询时。
答案 0 :(得分:275)
您可以在SQL Server 2008或更高版本上执行以下操作:
SELECT CONVERT(datetime,
SWITCHOFFSET(CONVERT(datetimeoffset,
MyTable.UtcColumn),
DATENAME(TzOffset, SYSDATETIMEOFFSET())))
AS ColumnInLocalTime
FROM MyTable
你也可以做一些不那么详细的事情:
SELECT DATEADD(mi, DATEDIFF(mi, GETUTCDATE(), GETDATE()), MyTable.UtcColumn)
AS ColumnInLocalTime
FROM MyTable
无论你做什么,不使用-
来减去日期,因为操作不是原子操作,并且由于系统日期时间和之间的竞争条件,您有时会获得不确定的结果在不同时间(即非原子地)检查本地日期时间。
请注意,此答案不会考虑DST。如果您想要包含DST调整,请参阅以下SO问题:
How to create Daylight Savings time Start and End function in SQL Server
答案 1 :(得分:32)
我没有发现这些示例中的任何一个有助于将日期时间存储为UTC到指定时区的日期时间(不是服务器的时区,因为Azure SQL数据库以UTC身份运行)。这就是我处理它的方式。它并不优雅,但它很简单,无需维护其他表格即可为您提供正确的答案:
select CONVERT(datetime, SWITCHOFFSET(dateTimeField, DATEPART(TZOFFSET,
dateTimeField AT TIME ZONE 'Eastern Standard Time')))
答案 2 :(得分:20)
如果您需要服务器位置以外的转换,则此功能允许您传递标准偏移量并记录美国夏令时:
-- =============================================
-- Author: Ron Smith
-- Create date: 2013-10-23
-- Description: Converts UTC to DST
-- based on passed Standard offset
-- =============================================
CREATE FUNCTION [dbo].[fn_UTC_to_DST]
(
@UTC datetime,
@StandardOffset int
)
RETURNS datetime
AS
BEGIN
declare
@DST datetime,
@SSM datetime, -- Second Sunday in March
@FSN datetime -- First Sunday in November
-- get DST Range
set @SSM = datename(year,@UTC) + '0314'
set @SSM = dateadd(hour,2,dateadd(day,datepart(dw,@SSM)*-1+1,@SSM))
set @FSN = datename(year,@UTC) + '1107'
set @FSN = dateadd(second,-1,dateadd(hour,2,dateadd(day,datepart(dw,@FSN)*-1+1,@FSN)))
-- add an hour to @StandardOffset if @UTC is in DST range
if @UTC between @SSM and @FSN
set @StandardOffset = @StandardOffset + 1
-- convert to DST
set @DST = dateadd(hour,@StandardOffset,@UTC)
-- return converted datetime
return @DST
END
GO
答案 3 :(得分:7)
使用新的SQL Server 2016机会:
CREATE FUNCTION ToLocalTime(@dtUtc datetime, @timezoneId nvarchar(256))
RETURNS datetime
AS BEGIN
return @dtUtc AT TIME ZONE 'UTC' AT TIME ZONE @timezoneId
/* -- second way, faster
return SWITCHOFFSET(@dtUtc , DATENAME(tz, @dtUtc AT TIME ZONE @timezoneId))
*/
/* -- third way
declare @dtLocal datetimeoffset
set @dtLocal = @dtUtc AT TIME ZONE @timezoneId
return dateadd(minute, DATEPART (TZoffset, @dtLocal), @dtUtc)
*/
END
GO
但clr程序的速度提高了5倍:' - (
注意一个TimeZone的偏移可以改为冬季或夏季。例如
select cast('2017-02-08 09:00:00.000' as datetime) AT TIME ZONE 'Eastern Standard Time'
select cast('2017-08-08 09:00:00.000' as datetime) AT TIME ZONE 'Eastern Standard Time'
结果:
2017-02-08 09:00:00.000 -05:00
2017-08-08 09:00:00.000 -04:00
您不能只添加常量偏移量。
答案 4 :(得分:5)
如果您的本地日期时间为Eastern Standard Time
,并且您想要从UTC转换为该时间,则在Azure SQL和SQL Server 2016及更高版本中,您可以执行以下操作:
select YourUtcColumn AT TIME ZONE 'UTC' AT TIME ZONE 'Eastern Standard Time' as LocalTime from YourTable
时区名称的完整列表可以在这篇文章中找到: List of Timezone ID's for use with FindTimeZoneById() in C#?
是的,时区命名错误-即使是Eastern Standard Time
,也要考虑夏令时。
答案 5 :(得分:4)
如果在数据库上启用CLR是一个选项,也可以使用sql server的时区,那么可以很容易地用.Net编写。
public partial class UserDefinedFunctions
{
[Microsoft.SqlServer.Server.SqlFunction]
public static SqlDateTime fn_GetLocalFromUTC(SqlDateTime UTC)
{
if (UTC.IsNull)
return UTC;
return new SqlDateTime(UTC.Value.ToLocalTime());
}
}
UTC日期时间值进入,并且相对于服务器的本地日期时间值出现。空值返回null。
答案 6 :(得分:4)
没有简单的方法以正确和通用的方式执行此操作。
首先必须明白,偏移取决于相关日期,时区和夏令时。
GetDate()-GetUTCDate
今天只为您提供服务器TZ的偏移量,这与您无关。
我只看到了两个有效的解决方案,我经常搜索。
1)一个自定义SQL函数,带有几个基本数据表,例如每个TZ的时区和DST规则。 工作但不是很优雅。我不能发布它,因为我没有代码。
编辑:以下是此方法的示例 https://gist.github.com/drumsta/16b79cee6bc195cd89c8
2)将.net程序集添加到数据库,.Net可以非常轻松地完成此任务。这很有效,但缺点是您需要在服务器级别配置多个参数,并且配置很容易被破坏,例如如果您还原数据库。 我使用这种方法,但我不能发布它,因为我没有代码。
答案 7 :(得分:3)
这是一个考虑夏令时,UTC偏移的版本,并且不会锁定在特定年份。
---------------------------------------------------------------------------------------------------
--Name: udfToLocalTime.sql
--Purpose: To convert UTC to local US time accounting for DST
--Author: Patrick Slesicki
--Date: 3/25/2014
--Notes: Works on SQL Server 2008R2 and later, maybe SQL Server 2008 as well.
-- Good only for US States observing the Energy Policy Act of 2005.
-- Function doesn't apply for years prior to 2007.
-- Function assumes that the 1st day of the week is Sunday.
--Tests:
-- SELECT dbo.udfToLocalTime('2014-03-09 9:00', DEFAULT)
-- SELECT dbo.udfToLocalTime('2014-03-09 10:00', DEFAULT)
-- SELECT dbo.udfToLocalTime('2014-11-02 8:00', DEFAULT)
-- SELECT dbo.udfToLocalTime('2014-11-02 9:00', DEFAULT)
---------------------------------------------------------------------------------------------------
ALTER FUNCTION udfToLocalTime
(
@UtcDateTime AS DATETIME
,@UtcOffset AS INT = -8 --PST
)
RETURNS DATETIME
AS
BEGIN
DECLARE
@PstDateTime AS DATETIME
,@Year AS CHAR(4)
,@DstStart AS DATETIME
,@DstEnd AS DATETIME
,@Mar1 AS DATETIME
,@Nov1 AS DATETIME
,@MarTime AS TIME
,@NovTime AS TIME
,@Mar1Day AS INT
,@Nov1Day AS INT
,@MarDiff AS INT
,@NovDiff AS INT
SELECT
@Year = YEAR(@UtcDateTime)
,@MarTime = CONVERT(TIME, DATEADD(HOUR, -@UtcOffset, '1900-01-01 02:00'))
,@NovTime = CONVERT(TIME, DATEADD(HOUR, -@UtcOffset - 1, '1900-01-01 02:00'))
,@Mar1 = CONVERT(CHAR(16), @Year + '-03-01 ' + CONVERT(CHAR(5), @MarTime), 126)
,@Nov1 = CONVERT(CHAR(16), @Year + '-11-01 ' + CONVERT(CHAR(5), @NovTime), 126)
,@Mar1Day = DATEPART(WEEKDAY, @Mar1)
,@Nov1Day = DATEPART(WEEKDAY, @Nov1)
--Get number of days between Mar 1 and DST start date
IF @Mar1Day = 1 SET @MarDiff = 7
ELSE SET @MarDiff = 15 - @Mar1Day
--Get number of days between Nov 1 and DST end date
IF @Nov1Day = 1 SET @NovDiff = 0
ELSE SET @NovDiff = 8 - @Nov1Day
--Get DST start and end dates
SELECT
@DstStart = DATEADD(DAY, @MarDiff, @Mar1)
,@DstEnd = DATEADD(DAY, @NovDiff, @Nov1)
--Change UTC offset if @UtcDateTime is in DST Range
IF @UtcDateTime >= @DstStart AND @UtcDateTime < @DstEnd SET @UtcOffset = @UtcOffset + 1
--Get Conversion
SET @PstDateTime = DATEADD(HOUR, @UtcOffset, @UtcDateTime)
RETURN @PstDateTime
END
GO
答案 8 :(得分:3)
当有大量数据时,我发现一次性功能方式太慢了。所以我通过加入一个允许计算小时差异的表函数来做到这一点。它基本上是具有小时偏移的日期时间段。一年将是4行。所以表函数
dbo.fn_getTimeZoneOffsets('3/1/2007 7:00am', '11/5/2007 9:00am', 'EPT')
将返回此表:
startTime endTime offset isHr2
3/1/07 7:00 3/11/07 6:59 -5 0
3/11/07 7:00 11/4/07 6:59 -4 0
11/4/07 7:00 11/4/07 7:59 -5 1
11/4/07 8:00 11/5/07 9:00 -5 0
它确实解释了夏令时。下面是一个如何使用的示例,完整的博客文章是here。
select mt.startTime as startUTC,
dateadd(hh, tzStart.offset, mt.startTime) as startLocal,
tzStart.isHr2
from MyTable mt
inner join dbo.fn_getTimeZoneOffsets(@startViewUTC, @endViewUTC, @timeZone) tzStart
on mt.startTime between tzStart.startTime and tzStart.endTime
答案 9 :(得分:2)
最简单的答案并不总是在底部,但这次是,并且可以在隐藏在上面评论中的某个地方看到。 使用您自己的“AT TIME ZONE”来捕获列/数据字段的 TzOffset,而不是当前的 SYSDATETIME。 在下面的数据中,有 2 个查询,一个关于 feb 数据(DST 关闭,阿姆斯特丹的冬天)+1 diff 以及对阿姆斯特丹四月数据的第二次查询,因此 +2 小时差异。
select top 2 month(receiveTimeUTC) as MonthInWinterOrSpring
, receiveTimeUTC
, CONVERT(datetime, SWITCHOFFSET(CONVERT(datetimeoffset, receiveTimeUTC), DATENAME(TzOffset, SYSDATETIMEOFFSET()))) as LocalTimeWrongNoDST
, CONVERT(datetime, SWITCHOFFSET(CONVERT(datetimeoffset, receiveTimeUTC), DATENAME(TzOffset, receiveTimeUTC AT TIME ZONE 'Central European Standard Time' ))) as LocalTimeWithDST
from sensordetails order by id
select top 2 month(receiveTimeUTC) as MonthInWinterOrSpring, receiveTimeUTC
, CONVERT(datetime, SWITCHOFFSET(CONVERT(datetimeoffset, receiveTimeUTC), DATENAME(TzOffset, SYSDATETIMEOFFSET()))) as LocalTimeWrongNoDST
, CONVERT(datetime, SWITCHOFFSET(CONVERT(datetimeoffset, receiveTimeUTC), DATENAME(TzOffset, receiveTimeUTC AT TIME ZONE 'Central European Standard Time' ))) as LocalTimeWithDST
from sensordetails order by id desc
所以这是一个 T-SQL(SQL Server 答案),不需要函数的存储过程。
答案 10 :(得分:2)
这些都不适合我,但下面的工作100%。希望这可以帮助其他人试图像我一样转换它。
CREATE FUNCTION [dbo].[fn_UTC_to_EST]
(
@UTC datetime,
@StandardOffset int
)
RETURNS datetime
AS
BEGIN
declare
@DST datetime,
@SSM datetime, -- Second Sunday in March
@FSN datetime -- First Sunday in November
-- get DST Range
set @SSM = DATEADD(dd,7 + (6-(DATEDIFF(dd,0,DATEADD(mm,(YEAR(GETDATE())-1900) * 12 + 2,0))%7)),DATEADD(mm,(YEAR(GETDATE())-1900) * 12 + 2,0))+'02:00:00'
set @FSN = DATEADD(dd, (6-(DATEDIFF(dd,0,DATEADD(mm,(YEAR(GETDATE())-1900) * 12 + 10,0))%7)),DATEADD(mm,(YEAR(GETDATE())-1900) * 12 + 10,0)) +'02:00:00'
-- add an hour to @StandardOffset if @UTC is in DST range
if @UTC between @SSM and @FSN
set @StandardOffset = @StandardOffset + 1
-- convert to DST
set @DST = dateadd(hour,@StandardOffset,@UTC)
-- return converted datetime
return @DST
END
答案 11 :(得分:2)
declare @mydate2 datetime
set @mydate2=Getdate()
select @mydate2 as mydate,
dateadd(minute, datediff(minute,getdate(),@mydate2),getutcdate())
答案 12 :(得分:1)
Ron的回答包含错误。它使用当地时间凌晨2:00,需要UTC等效值。我没有足够的声望点来评论Ron的答案,因此下面会出现更正的版本:
-- =============================================
-- Author: Ron Smith
-- Create date: 2013-10-23
-- Description: Converts UTC to DST
-- based on passed Standard offset
-- =============================================
CREATE FUNCTION [dbo].[fn_UTC_to_DST]
(
@UTC datetime,
@StandardOffset int
)
RETURNS datetime
AS
BEGIN
declare
@DST datetime,
@SSM datetime, -- Second Sunday in March
@FSN datetime -- First Sunday in November
-- get DST Range
set @SSM = datename(year,@UTC) + '0314'
set @SSM = dateadd(hour,2 - @StandardOffset,dateadd(day,datepart(dw,@SSM)*-1+1,@SSM))
set @FSN = datename(year,@UTC) + '1107'
set @FSN = dateadd(second,-1,dateadd(hour,2 - (@StandardOffset + 1),dateadd(day,datepart(dw,@FSN)*-1+1,@FSN)))
-- add an hour to @StandardOffset if @UTC is in DST range
if @UTC between @SSM and @FSN
set @StandardOffset = @StandardOffset + 1
-- convert to DST
set @DST = dateadd(hour,@StandardOffset,@UTC)
-- return converted datetime
return @DST
END
答案 13 :(得分:1)
UNIX时间戳只是特定日期和Unix纪元之间的秒数,
SELECT DATEDIFF(SECOND,{d'1970-01-01'},GETDATE()) //这将返回SQL服务器中的UNIX时间戳
您可以使用“国家/地区偏移”创建将本地日期时间转换为Unix UTC的函数 Function to Unix Time Stamp In SQL server
答案 14 :(得分:1)
很简单。对于Azure SQL Server,请尝试以下操作:
SELECT YourDateTimeColumn AT TIME ZONE 'Eastern Standard Time' FROM YourTable
对于本地SQL Server:
SELECT CONVERT(datetime2, SWITCHOFFSET(CONVERT(datetimeoffset, gETDATE()), DATENAME(TzOffset, gETDATE() AT TIME ZONE 'Eastern Standard Time'))) FROM YourTable
答案 15 :(得分:1)
这可以在没有功能的情况下完成。下面的代码将把夏令时转换为UTC时间到山区时间。相应地将所有-6和-7数字调整到您的时区(即对于EST,您将分别调整为-4和-5)
--Adjust a UTC value, in the example the UTC field is identified as UTC.Field, to account for daylight savings time when converting out of UTC to Mountain time.
CASE
--When it's between March and November, it is summer time which is -6 from UTC
WHEN MONTH ( UTC.Field ) > 3 AND MONTH ( UTC.Field ) < 11
THEN DATEADD ( HOUR , -6 , UTC.Field )
--When its March and the day is greater than the 14, you know it's summer (-6)
WHEN MONTH ( UTC.Field ) = 3
AND DATEPART ( DAY , UTC.Field ) >= 14
THEN
--However, if UTC is before 9am on that Sunday, then it's before 2am Mountain which means it's still Winter daylight time.
CASE
WHEN DATEPART ( WEEKDAY , UTC.Field ) = 1
AND UTC.Field < '9:00'
--Before 2am mountain time so it's winter, -7 hours for Winter daylight time
THEN DATEADD ( HOUR , -7 , UTC.Field )
--Otherwise -6 because it'll be after 2am making it Summer daylight time
ELSE DATEADD ( HOUR , -6 , UTC.Field )
END
WHEN MONTH ( UTC.Field ) = 3
AND ( DATEPART ( WEEKDAY , UTC.Field ) + 7 ) <= DATEPART ( day , UTC.Field )
THEN
--According to the date, it's moved onto Summer daylight, but we need to account for the hours leading up to 2am if it's Sunday
CASE
WHEN DATEPART ( WEEKDAY , UTC.Field ) = 1
AND UTC.Field < '9:00'
--Before 9am UTC is before 2am Mountain so it's winter Daylight, -7 hours
THEN DATEADD ( HOUR , -7 , UTC.Field )
--Otherwise, it's summer daylight, -6 hours
ELSE DATEADD ( HOUR , -6 , UTC.Field )
END
--When it's November and the weekday is greater than the calendar date, it's still Summer so -6 from the time
WHEN MONTH ( UTC.Field ) = 11
AND DATEPART ( WEEKDAY , UTC.Field ) > DATEPART ( DAY , UTC.Field )
THEN DATEADD ( HOUR , -6 , UTC.Field )
WHEN MONTH ( UTC.Field ) = 11
AND DATEPART ( WEEKDAY , UTC.Field ) <= DATEPART ( DAY , UTC.Field )
--If the weekday is less than or equal to the calendar day it's Winter daylight but we need to account for the hours leading up to 2am.
CASE
WHEN DATEPART ( WEEKDAY , UTC.Field ) = 1
AND UTC.Field < '8:00'
--If it's before 8am UTC and it's Sunday in the logic outlined, then it's still Summer daylight, -6 hours
THEN DATEADD ( HOUR , -6 , UTC.Field )
--Otherwise, adjust for Winter daylight at -7
ELSE DATEADD ( HOUR , -7 , UTC.Field )
END
--If the date doesn't fall into any of the above logic, it's Winter daylight, -7
ELSE
DATEADD ( HOUR , -7 , UTC.Field )
END
答案 16 :(得分:1)
好吧,如果您将数据作为UTC日期存储在数据库中,则可以做些简单的事情
select
[MyUtcDate] + getdate() - getutcdate()
from [dbo].[mytable]
从服务器的角度来看,这始终是本地的,并且您不会对AT TIME ZONE 'your time zone name'
感到困惑,
如果您的数据库移至另一个时区(如客户端安装),则硬编码的时区可能会咬您。
答案 17 :(得分:1)
对于Azure SQL和@@Version
> = SQL Server 2016用户,以下是使用AT TIME ZONE
的简单功能。
CREATE FUNCTION [dbo].[Global_Convert_UTCTimeTo_LocalTime]
(
@LocalTimeZone VARCHAR(50),
@UTCDateTime DATETIME
)
RETURNS DATETIME
AS
BEGIN
DECLARE @ConvertedDateTime DATETIME
SELECT @ConvertedDateTime = @UTCDateTime AT TIME ZONE 'UTC' AT TIME ZONE @LocalTimeZone
RETURN @ConvertedDateTime
END
GO
对于@LocalTimeZone
可以采用的值类型,请转到此link或转到KEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Windows NT\CurrentVersion\Time Zones
答案 18 :(得分:0)
我发现此功能比使用单独的表或循环的其他解决方案更快。它只是一个基本的案例陈述。考虑到4月到10月之间的所有月份都有-4小时的偏差(东部时间),我们只需要为边缘日添加一些案例线。否则,偏移量为-5小时。
这特定于从UTC到东部时间的转换,但可以根据需要添加其他时区功能。
USE [YourDatabaseName]
GO
/****** Object: UserDefinedFunction [dbo].[ConvertUTCtoEastern] Script Date: 11/2/2016 5:21:52 PM ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE FUNCTION [dbo].[ConvertUTCtoEastern]
(
@dtStartDate DATETIME
)
RETURNS DATETIME
AS
BEGIN
DECLARE @Working DATETIME
DECLARE @Returned DATETIME
SET @Working = @dtStartDate
SET @Working =
case when month(@Working) between 4 and 10 then dateadd(HH,-4,@Working)
when @Working between '2017-03-12' and '2017-11-05' then dateadd(HH,-4,@Working)
when @Working between '2016-03-13' and '2016-11-06' then dateadd(HH,-4,@Working)
when @Working between '2015-03-08' and '2015-11-01' then dateadd(HH,-4,@Working)
when @Working between '2014-03-09' and '2014-11-02' then dateadd(HH,-4,@Working)
when @Working between '2013-03-10' and '2013-11-03' then dateadd(HH,-4,@Working)
when @Working between '2012-03-11' and '2012-11-04' then dateadd(HH,-4,@Working)
else dateadd(HH,-5,@Working) end
SET @Returned = @Working
RETURN @Returned
END
GO
答案 19 :(得分:0)
此功能通过DST调整将UTC时间转换为EST时间。您可以在此函数中更改设计的时区名称,或从注册表中获取它:
Create Function fnConvertUTCTimetoESTTime(
@UTCTime as datetime
)
returns datetime
as
begin
return convert(datetime, convert(varchar(23), @UTCTime AT TIME ZONE 'UTC' AT TIME ZONE 'Eastern Standard Time', 121), 121)
end
go
select dbo.fnConvertUTCTimetoESTTime ('2020-3-8 5:00:00.000')
, dbo.fnConvertUTCTimetoESTTime ('2020-3-8 6:00:00.000')
, dbo.fnConvertUTCTimetoESTTime ('2020-3-8 7:00:00.000')
, dbo.fnConvertUTCTimetoESTTime ('2020-3-8 8:00:00.000')
--returns 0:00am, 1:00am, 3:00am, 4:00am
select dbo.fnConvertUTCTimetoESTTime ('2020-11-1 4:00:00.000')
, dbo.fnConvertUTCTimetoESTTime ('2020-11-1 5:00:00.000')
, dbo.fnConvertUTCTimetoESTTime ('2020-11-1 6:00:00.000')
, dbo.fnConvertUTCTimetoESTTime ('2020-11-1 7:00:00.000')
--returns 0:00am, 1:00am, 1:00am, 2:00am
请注意,您不能只返回“ @UTCTime AT TIME ZONE'UTC'AT TIME ZONE'东部标准时间'”作为结果,因为此结果实际上是EST格式的UTC时间(当您比较此“假” EST时)时间或将其包含在order子句中,它将转换回UTC时间。
答案 20 :(得分:0)
对于仍在尝试解决此问题的任何人,下面的概念证明可在SQL Server 2017中使用
declare
@StartDate date = '2020-01-01'
;with cte_utc as
(
select
1 as i
,CONVERT(datetime, @StartDate) AS UTC
,datepart(weekday, CONVERT(datetime, @StartDate)) as Weekday
,datepart(month, CONVERT(datetime, @StartDate)) as [Month]
,datepart(YEAR, CONVERT(datetime, @StartDate)) as [Year]
union all
Select
i + 1
,dateadd(d, 1, utc)
,datepart(weekday, CONVERT(datetime, dateadd(d, 1, utc))) as Weekday
,datepart(month, CONVERT(datetime, dateadd(d, 1, utc))) as [Month]
,datepart(YEAR, CONVERT(datetime, dateadd(d, 1, utc))) as [Year]
from
cte_utc
where
(i + 1) < 32767
), cte_utc_dates as
(
select
*,
DENSE_RANK()OVER(PARTITION BY [Year], [Month], [Weekday] ORDER BY Utc) WeekDayIndex
from
cte_utc
), cte_hours as (
select 0 as [Hour]
union all
select [Hour] + 1 from cte_hours where [Hour] < 23
)
select
d.*
, DATEADD(hour, h.Hour, d.UTC) AS UtcTime
,CONVERT(datetime, DATEADD(hour, h.Hour, d.UTC) AT TIME ZONE 'UTC' AT TIME ZONE 'Central Standard Time') CST
,CONVERT(datetime, DATEADD(hour, h.Hour, d.UTC) AT TIME ZONE 'UTC' AT TIME ZONE 'Eastern Standard Time') EST
from
cte_utc_dates d, cte_hours h
where
([Month] = 3 and [Weekday] = 1 and WeekDayIndex = 2 )-- dst start
or
([Month] = 11 and [Weekday] = 1 and WeekDayIndex = 1 )-- dst end
order by
utc
OPTION (MAXRECURSION 32767)
GO
答案 21 :(得分:0)
在postgres中,这非常好用。告诉服务器保存时间'utc',然后要求它转换为特定时区,在这种情况下为'巴西/东部'
quiz_step_progresses.created_at at time zone 'utc' at time zone 'Brazil/East'
通过以下选择获取完整的时区列表;
select * from pg_timezone_names;
在此处查看详细信息。
https://popsql.com/learn-sql/postgresql/how-to-convert-utc-to-local-time-zone-in-postgresql
答案 22 :(得分:0)
我有执行UTC到本地时间和本地到UTC时间的代码,可以使用这样的代码进行转换
DECLARE @usersTimezone VARCHAR(32)='Europe/London'
DECLARE @utcDT DATETIME=GetUTCDate()
DECLARE @userDT DATETIME=[dbo].[funcUTCtoLocal](@utcDT, @usersTimezone)
和
DECLARE @usersTimezone VARCHAR(32)='Europe/London'
DECLARE @userDT DATETIME=GetDate()
DECLARE @utcDT DATETIME=[dbo].[funcLocaltoUTC](@userDT, @usersTimezone)
这些功能可以支持NodaTime提供的IANA / TZDB中的全部或部分时区-请参见https://nodatime.org/TimeZones
的完整列表请注意,我的用例意味着我只需要一个“当前”窗口,即可转换从现在起大约+/- 5年的时间。这意味着如果您需要很长的时间,我使用的方法可能不适合您,因为它会在给定日期范围内为每个时区间隔生成代码。
该项目位于GitHub:https://github.com/elliveny/SQLServerTimeConversion
这会根据this example
生成SQL函数代码答案 23 :(得分:0)
作为警告 - 如果您要使用以下内容(请注意毫秒而不是分钟数):
SELECT DATEADD(ms, DATEDIFF(ms, GETUTCDATE(), GETDATE()), MyTable.UtcColumn)
AS ColumnInLocalTime
FROM MyTable
请记住,DATEDIFF部分不会始终返回相同的数字。所以不要用它来比较DateTimes到毫秒。
答案 24 :(得分:0)
Oracle的最佳方法:
具有硬编码的日期时间:
SELECT TO_CHAR(CAST((FROM_TZ(CAST(TO_DATE('2018-10-27 21:00', 'YYYY-MM-DD HH24:MI') AS TIMESTAMP), 'UTC') AT TIME ZONE 'EET') AS DATE), 'YYYY-MM-DD HH24:MI') UTC_TO_EET FROM DUAL
Result:
2018-10-28 00:00
具有列名和表名:
SELECT TO_CHAR(CAST((FROM_TZ(CAST(COLUMN_NAME AS TIMESTAMP), 'UTC') AT TIME ZONE 'EET') AS DATE), 'YYYY-MM-DD HH24:MI') UTC_TO_EET FROM TABLE_NAME
答案 25 :(得分:0)
您必须重新格式化字符串并转换为正确的时间。在这种情况下,我需要祖鲁时间。
Declare @Date datetime;
Declare @DateString varchar(50);
set @Date = GETDATE();
declare @ZuluTime datetime;
Declare @DateFrom varchar (50);
Declare @DateTo varchar (50);
set @ZuluTime = DATEADD(second, DATEDIFF(second, GETDATE(), GETUTCDATE()), @Date);
set @DateString = FORMAT(@ZuluTime, 'yyyy-MM-ddThh:mm:ssZ', 'en-US' )
select @DateString;
答案 26 :(得分:0)
-从utc获取印度标准时间
CREATE FUNCTION dbo.getISTTime
(
@UTCDate datetime
)
RETURNS datetime
AS
BEGIN
RETURN dateadd(minute,330,@UTCDate)
END
GO
答案 27 :(得分:0)
第一个功能:配置为意大利时区(+ 1,+ 2),切换日期:3月和10月的最后一个星期日,返回当前时区和日期时间之间的差值作为参数。
Returns:
current timezone < parameter timezone ==> +1
current timezone > parameter timezone ==> -1
else 0
代码是:
CREATE FUNCTION [dbo].[UF_ADJUST_OFFSET]
(
@dt_utc datetime2(7)
)
RETURNS INT
AS
BEGIN
declare @month int,
@year int,
@current_offset int,
@offset_since int,
@offset int,
@yearmonth varchar(8),
@changeoffsetdate datetime2(7)
declare @lastweek table(giorno datetime2(7))
select @current_offset = DATEDIFF(hh, GETUTCDATE(), GETDATE())
select @month = datepart(month, @dt_utc)
if @month < 3 or @month > 10 Begin Set @offset_since = 1 Goto JMP End
if @month > 3 and @month < 10 Begin Set @offset_since = 2 Goto JMP End
--If i'm here is march or october
select @year = datepart(yyyy, @dt_utc)
if @month = 3
Begin
Set @yearmonth = cast(@year as varchar) + '-03-'
Insert Into @lastweek Values(@yearmonth + '31 03:00:00.000000'),(@yearmonth + '30 03:00:00.000000'),(@yearmonth + '29 03:00:00.000000'),(@yearmonth + '28 03:00:00.000000'),
(@yearmonth + '27 03:00:00.000000'),(@yearmonth + '26 03:00:00.000000'),(@yearmonth + '25 03:00:00.000000')
--Last week of march
Select @changeoffsetdate = giorno From @lastweek Where datepart(weekday, giorno) = 1
if @dt_utc < @changeoffsetdate
Begin
Set @offset_since = 1
End Else Begin
Set @offset_since = 2
End
End
if @month = 10
Begin
Set @yearmonth = cast(@year as varchar) + '-10-'
Insert Into @lastweek Values(@yearmonth + '31 03:00:00.000000'),(@yearmonth + '30 03:00:00.000000'),(@yearmonth + '29 03:00:00.000000'),(@yearmonth + '28 03:00:00.000000'),
(@yearmonth + '27 03:00:00.000000'),(@yearmonth + '26 03:00:00.000000'),(@yearmonth + '25 03:00:00.000000')
--Last week of october
Select @changeoffsetdate = giorno From @lastweek Where datepart(weekday, giorno) = 1
if @dt_utc > @changeoffsetdate
Begin
Set @offset_since = 1
End Else Begin
Set @offset_since = 2
End
End
JMP:
if @current_offset < @offset_since Begin
Set @offset = 1
End Else if @current_offset > @offset_since Set @offset = -1 Else Set @offset = 0
Return @offset
END
然后是转换日期的函数
CREATE FUNCTION [dbo].[UF_CONVERT]
(
@dt_utc datetime2(7)
)
RETURNS datetime
AS
BEGIN
declare @offset int
Select @offset = dbo.UF_ADJUST_OFFSET(@dt_utc)
if @dt_utc >= '9999-12-31 22:59:59.9999999'
set @dt_utc = '9999-12-31 23:59:59.9999999'
Else
set @dt_utc = (SELECT DATEADD(mi, DATEDIFF(mi, GETUTCDATE(), GETDATE()), @dt_utc) )
if @offset <> 0
Set @dt_utc = dateadd(hh, @offset, @dt_utc)
RETURN @dt_utc
END
答案 28 :(得分:0)
这应该可以通过DST获得服务器时间
declare @dt datetime
set @dt = getutcdate() -- GMT equivalent
sysdatetimeoffset将DST考虑在内
select [InputTime] = @dt
, [LocalTime2] = dateadd(mi, datediff(mi, sysdatetimeoffset(),getdate()), @dt)
答案 29 :(得分:-1)
这是一个更简单的方法,将dst纳入帐户
CREATE FUNCTION [dbo].[UtcToLocal]
(
@p_utcDatetime DATETIME
)
RETURNS DATETIME
AS
BEGIN
RETURN DATEADD(MINUTE, DATEDIFF(MINUTE, GETUTCDATE(), @p_utcDatetime), GETDATE())
END