我正在尝试处理一个方法，该方法将在链接列表中的当前节点之前插入传递给它的节点。它有3个条件。对于此实现，不能有任何头节点（仅对列表中的第一个节点的引用），并且我不能再添加任何变量。
这是我的代码。
public class LinkedList
{
private Node currentNode;
private Node firstNode;
private int nodeCount;
public static void main(String[] args)
{
LinkedList test;
String dataTest;
test = new LinkedList();
dataTest = "abcdefghijklmnopqrstuvwxyz";
for(int i=0; i< dataTest.length(); i++) { test.insert(new String(new char[] { dataTest.charAt(i) })); }
System.out.println("[1] "+ test);
for(int i=0; i< dataTest.length(); i++) { test.deleteCurrentNode(); }
System.out.println("[2] "+test);
for(int i=0; i< dataTest.length(); i++)
{
test.insertBeforeCurrentNode(new String(new char[] { dataTest.charAt(i) }));
if(i%2 == 0) { test.first(); } else { test.last(); }
}
System.out.println("[3] "+test);
}
public LinkedList()
{
setListPtr(null);
setCurrent(null);
nodeCount = 0;
}
public boolean atEnd()
{
checkCurrent();
return getCurrent().getNext() == null;
}
public boolean isEmpty()
{
return getListPtr() == null;
}
public void first()
{
setCurrent(getListPtr());
}
public void next()
{
checkCurrent();
if (atEnd()) {throw new InvalidPositionInListException("You are at the end of the list. There is no next node. next().");}
setCurrent(this.currentNode.getNext());
}
public void last()
{
if (isEmpty()) {throw new ListEmptyException("The list is currently empty! last()");}
while (!atEnd())
{
setCurrent(getCurrent().getNext());
}
}
public Object getData()
{
return getCurrent().getData();
}
public void insertBeforeCurrentNode(Object bcNode) //beforeCurrentNode
{
Node current;
Node hold;
boolean done;
hold = allocateNode();
hold.setData(bcNode);
current = getListPtr();
done = false;
if (isEmpty())
{
setListPtr(hold);
setCurrent(hold);
}
else if (getCurrent() == getListPtr())
{
System.out.println("hi" + hold);
hold.setNext(getCurrent());
setListPtr(hold);
}
else //if (!isEmpty() && getCurrent() != getListPtr())
{
while (!done && current.getNext() != null)
{
System.out.println("in else if " + hold);
if (current.getNext() == getCurrent())
{
//previous.setNext(hold);
//System.out.println("hi"+ "yo" + " " + getListPtr());
hold.setNext(current.getNext());
current.setNext(hold);
done = true;
}
//previous = current;
current = current.getNext();
}
}
System.out.println(getCurrent());
}
public void insertAfterCurrentNode(Object acNode) //afterCurrentNode
{
Node hold;
hold = allocateNode();
hold.setData(acNode);
if (isEmpty())
{
setListPtr(hold);
setCurrent(hold);
//System.out.println(hold + " hi");
}
else
{
//System.out.println(hold + " hia");
hold.setNext(getCurrent().getNext());
getCurrent().setNext(hold);
}
}
public void insert(Object iNode)
{
insertAfterCurrentNode(iNode);
}
public Object deleteCurrentNode()
{
Object nData;
Node previous;
Node current;
previous = getListPtr();
current = getListPtr();
nData = getCurrent().getData();
if (isEmpty()) {throw new ListEmptyException("The list is currently empty! last()");}
else if (previous == getCurrent())
{
getListPtr().setNext(getCurrent().getNext());
setCurrent(getCurrent().getNext());
nodeCount = nodeCount - 1;
}
else
{
while (previous.getNext() != getCurrent())
{
previous = current;
current = current.getNext();
}
previous.setNext(getCurrent().getNext());
setCurrent(getCurrent().getNext());
nodeCount = nodeCount - 1;
}
return nData;
}
public Object deleteFirstNode(boolean toDelete)
{
if (toDelete)
{
setListPtr(null);
}
return getListPtr();
}
public Object deleteFirstNode()
{
Object deleteFirst;
deleteFirst = deleteFirstNode(true);
return deleteFirst;
}
public int size()
{
return this.nodeCount;
}
public String toString()
{
String nodeString;
Node sNode;
sNode = getCurrent();
//System.out.println(nodeCount);
nodeString = ("List contains " + nodeCount + " nodes");
while (sNode != null)
{
nodeString = nodeString + " " +sNode.getData();
sNode = sNode.getNext();
}
return nodeString;
}
private Node allocateNode()
{
Node newNode;
newNode = new Node();
nodeCount = nodeCount + 1;
return newNode;
}
private void deAllocateNode(Node dNode)
{
dNode.setData(null);
}
private Node getListPtr()
{
return this.firstNode;
}
private void setListPtr(Node pNode)
{
this.firstNode = pNode;
}
private Node getCurrent()
{
return this.currentNode;
}
private void setCurrent(Node cNode)
{
this.currentNode = cNode;
}
private void checkCurrent()
{
if (getCurrent() == null) {throw new InvalidPositionInListException("Current node is null and is set to an invalid position within the list! checkCurrent()");}
}
/**NODE CLASS ----------------------------------------------*/
private class Node
{
private Node next; //serves as a reference to the next node
private Object data;
public Node()
{
this.next = null;
this.data = null;
}
public Object getData()
{
return this.data;
}
public void setData(Object obj)
{
this.data = obj;
}
public Node getNext()
{
return this.next;
}
public void setNext(Node nextNode)
{
this.next = nextNode;
}
public String toString()
{
String nodeString;
Node sNode;
sNode = getCurrent();
//System.out.println(nodeCount);
nodeString = ("List contains " + nodeCount + " nodes");
while (sNode != null)
{
nodeString = nodeString + " " +sNode.getData();
sNode = sNode.getNext();
}
return nodeString;
}
}
}
我让它适用于我的[1]和[2]条件。但我的[3]（测试insertBeforeCurrentNode（））无法正常工作。我已经设置了打印语句，并且我已经确定我的电流在某个地方被重置，但我无法确定哪里可以使用某些指导或解决方案。
[1]和[2]的输出是正确的。 [3]的输出应为
[3]列表包含26个节点：z x v t r p n l j h f d b c e g m k o o s y a y a y
提前感谢您的帮助。
答案 0 :(得分：2)
在toString方法中，您开始从 currentNode 打印节点，直到列表末尾。由于您在打印结果之前致电test.last()，因此 currentNode 将指向列表的最后一个节点，而您的toString()只会打印“a”。
在toString()方法中，您可能想要更改
sNode = getCurrent();
带
sNode = getListPtr();
打印26个节点。
答案 1 :(得分：0)
对于[3]，您需要保持指向两个节点的指针：“当前”节点中的一个指针，您正在查找的节点，另一个指向“前一个”节点，即当前节点之前的指针。这样，当您找到正在查看“当前”位置的节点时，您可以在“上一个”之后和“当前”之前连接新节点。在伪代码中，并确保案例[1]和[2]之前已被涵盖：
Node previous = null;
Node current = first;
while (current != null && current.getValue() != searchedValue) {
previous = current;
current = current.getNext();
}
previous.setNext(newNode);
newNode.setNext(current);