我有File1
A,B,C
和File2
D,E,F
我想要
AD, AE, AF, BD, BE, BF, CD, CE, CF
未成功
echo {`cat File1`}{`cat File2`}
给
{A,B,C}{D,E,F}
如何通过Zsh / AWK解决问题?
答案 0 :(得分:2)
我不知道zsh,这是我用bash和sed做的事情:
echo "A,B,C" >a
echo "D,E,F" >b
for i in `cat a | sed -e "s@,@\n@g"`;
do for j in `cat b | sed -e "s@,@\n@g"`;
do echo -n "$i$j, ";
done ;
done | sed -e "s@,\s\$@@"
输出是:
AD, AE, AF, BD, BE, BF, CD, CE, CF
答案 1 :(得分:2)
awk -F, '
NR==FNR {
# read lines from File1 into the array f1
f1[NR]=$0
next
}
{
# foreach line in File2
split(f1[FNR], words); # get words from corresponding line in File1
sep = ""
for (i in words) {
for (j=1; j<=NF; j++) {
printf("%s%s%s", sep, words[i], $j)
sep = ", "
}
}
print ""
}
' File1 File2
如果File1包含
A,B,C
1,2,3
和File2包含
D,E,F
4,5,6
然后awk脚本输出
AD, AE, AF, BD, BE, BF, CD, CE, CF
14, 15, 16, 24, 25, 26, 34, 35, 36