在阅读一些关于Scala的文章时,我发现了一些带有好奇语法的例子,我可能会错误地理解它
class Child[C <: Child[C]] {
some_name : C => // here, what does it mean?
var roomie : Option[C] = None
def roomWith(aChild : C)= {
roomie = Some(aChild)
aChild.roomie = Some(this)
}
}
class Boy extends Child[Boy]
我发现了类似特征的例子。
这是否意味着我在类范围内将this
对象声明为C
的类型?
答案 0 :(得分:10)
这是一种自我类型的注释。
这意味着类Child
必须是C
类型,即创建必须满足给定类的继承依赖项。
一个小例子:
scala> trait Baz
defined trait Baz
scala> class Foo {
| self:Baz =>
| }
defined class Foo
scala> val a = new Foo
<console>:9: error: class Foo cannot be instantiated because it does not conform to its self-type Foo with Baz
val a = new Foo
^
scala> val a = new Foo with Baz
a: Foo with Baz = $anon$1@199de181
scala> class Bar extends Foo with Baz
defined class Bar
在这种情况下,Foo
也必须是Baz
。
满足该要求,可以创建Foo
实例。
此外,定义一个新类(在本例中为Bar
)也需要它Baz
。
答案 1 :(得分:3)
自我类型的一个非常有用的应用是CRTP(http://en.wikipedia.org/wiki/Curiously_recurring_template_pattern)的简洁实现,例如。
abstract class Base[Sub] {
self:Sub =>
def add(s:Sub) : Sub
}
case class Vec3(x:Double,y:Double,z:Double) extends Base[Vec3] {
def add(that:Vec3) = Vec3(this.x+that.x, this.y+that.y, this.z+that.z)
}
试图“欺骗”继承是行不通的:
class Foo extends Base[Vec3] {
add(v:Vec3) = v
}
//error: illegal inheritance;
//self-type Foo does not conform to Base[Vec3]'s selftype Base[Vec3] with Vec3
// class Foo extends Base[Vec3] {
答案 2 :(得分:2)
除了JaimeJorge的响应中的继承要求之外,如果要从内部类引用外部实例,则可以使用self类型为外部实例指定名称:
scala> class Company(name: String) {
| company =>
| class Department(name: String) {
| override def toString = "Department "+ name +" of "+ company.name
| }
| }
defined class Company
scala> val c = new Company("ACME")
c: Company = Company@56a57bb2
scala> val d = new c.Department("Marketing")
d: c.Department = Department Marketing of ACME