Question

我在mvc3中返回消息弹出窗口时有些麻烦抛出一些异常。
我正在使用PostSharp作为全球AOP 用于捕获异常并处理它们构建文本的框架弹出窗口。
我已将ActionResult扩展为自定义对象在ExecuteResult中实现了RenderViewToString方法为messagePopup创建正确的html代码。
MessagePopup显示在页面上，但Action继续自行执行。

如何阻止它继续执行？

当它失败时，我会在

namespace Aop
{
/// <summary>
/// Handles Aspect Object Programming in all the projects .
/// The attribute is being injected through Shared AssemblyInfo.cs to all the 
/// relevant Assemblies in the project.
/// The code of the class is being added to project in compilation time
/// and by that improves the response time quality
/// </summary>
[Serializable]
[AttributeUsage(AttributeTargets.Assembly | AttributeTargets.Class |
             AttributeTargets.Method | AttributeTargets.Constructor,
             AllowMultiple = true, Inherited = false)]
[MulticastAttributeUsage(MulticastTargets.Method, AllowMultiple = true,
                         AllowExternalAssemblies = true)]
public sealed class TraceAttribute : OnMethodBoundaryAspect
{
    [Inject]
    public IReportBLImpl _reportBL { get; set; }

    public TraceAttribute() { }

    #region Runtime semantics

    /// <summary>
    /// Handles all exception in all the project Ness.DoarKamuti exceptions
    /// </summary>
    /// <param name="eventArgs"></param>
    public override void OnException(MethodExecutionEventArgs eventArgs)
    {
    …
     DefActionResult res = DefActionResult.Create("~/Views/Shared/MessagePopup.ascx",_report , DefConstants.MessageDesign.PopUp, "messagePopupBody");

            eventArgs.ReturnValue = res;
 }

     }

在处理消息内容

public class DefActionResult：ActionResult {

    public override void ExecuteResult(ControllerContext context)
    {
        DefJsonResult model = this.ActionModel;


        /* If a view name has been specified, render it */
        if (!string.IsNullOrEmpty(model.ViewName))
            model.ViewHTML = controller.RenderViewToString(model.ViewName, model.ViewModel);

        JsonResult res = new JsonResult() { Data = model, JsonRequestBehavior = JsonRequestBehavior.AllowGet };
        res.ExecuteResult(context);
    }
}

然后我正在构建响应

public static class MVCExtensions
{

    public static string RenderViewToString(this Controller controller, string viewName, object viewData)
    {
        //Create memory writer
        var sb = new StringBuilder();
        var memWriter = new StringWriter(sb);

        //Create fake http context to render the view
        var fakeResponse = new HttpResponse(memWriter);

        var fakeContext = new HttpContext(HttpContext.Current.Request, fakeResponse);
        var fakeControllerContext = new ControllerContext(
            new HttpContextWrapper(fakeContext),
            controller.ControllerContext.RouteData,
            controller.ControllerContext.Controller);

        var oldContext = HttpContext.Current;
        HttpContext.Current = fakeContext;

        //Use HtmlHelper to render partial view to fake context
        var html = new HtmlHelper(new ViewContext(fakeControllerContext,
            new FakeView(), controller.ViewData, controller.TempData, memWriter),
            new ViewPage());

        html.ViewDataContainer.ViewData = controller.ViewData;

        html.RenderPartial(viewName, viewData);

        //Restore context
        //HttpContext.Current = oldContext;

        //Flush memory and return output
        memWriter.Flush();
        return sb.ToString();
    }

按照原样返回我的Message Popup后，它会继续执行原始操作，就好像它没有粉碎一样，当然还是因为数据源没有被初始化而崩溃。

我不想使用HandleErrorAttribute处理错误，因为它不像PostSharp那样动态。

如何停止原始请求的遗骸？ （注意，我正在使用Telerik网格为mvc显示数据。）

Answer 1

要停止方法继续正常使用args.FlowBehavior.Return。除非有一些使用try / catch的其他机制，否则该方法应该已经执行此操作，但您的方面应该将自身应用为最外层的try / catch。你真的需要使用ILSpy来查看你的程序集的结尾IL（没有其他的反编译器会在这个时间点看到postharp修改）然后你将能够看到发生了什么。如果你有一个动作属性，那么我敢打赌它与它有关，因为postharp将修改方法但动作属性不会因此它仍然是流量的最外层控制器。首先尝试FlowBehavior。

消息Popup Mvc3与PostSharp OnException处理问题

1 个答案: