使用交叉表函数的PostgreSQL和数据透视表

时间:2011-11-06 13:29:35

标签: sql postgresql pivot crosstab

我在使用crosstab()函数在PostgreSQL中创建数据透视表时遇到问题。它运行良好,但它为同一client_id生成多个记录。我怎么能避免这个?

这是SQL:

SELECT *
FROM crosstab('SELECT client_id
                     ,extract(year from date)
                     ,sum(amount)
               from   orders
               group  by extract(year from date)
                     ,client_id'
             ,'SELECT extract(year from date)
               FROM   orders
               GROUP  BY extract(year from date)
               order  by extract(year from date)')
AS orders(
row_name integer,
year_2001 text,
year_2002 text,
year_2003 text,
year_2004 text,
year_2005 text,
year_2006 text,
year_2007 text,
year_2008 text,
year_2009 text,
year_2010 text,
year_2011 text);

//修改

对Erwin它现在有效,但我试图在没有内置功能但没有运气的情况下这样做。有人可以就此提出建议吗?我的代码只用了两年:

SELECT DISTINCT o.client_id,
       CASE WHEN (extract(year from o.date)=2001)
            THEN sum(o.amount) ELSE 0 END,
       CASE WHEN (extract(year from o.date)=2002)
            THEN sum(o.amount) ELSE 0 END
FROM orders AS o
GROUP BY 1, extract(year from o.date)
ORDER BY 1;

1 个答案:

答案 0 :(得分:3)

您需要ORDER BY相应的第一个查询。我在这里使用了simplified syntax ORDER BY <ordinal number>

SELECT *
FROM   crosstab(
        'SELECT client_id
               ,extract(year from date)
               ,sum(amount)
         FROM   orders
         GROUP  BY 1,2
         ORDER  BY 1,2',

        'SELECT extract(year from date)
         FROM   orders
         GROUP  BY 1
         ORDER  BY 1')
AS orders(
    row_name integer,
    year_2001 text,
    year_2002 text,
    year_2003 text,
    year_2004 text,
    year_2005 text,
    year_2006 text,
    year_2007 text,
    year_2008 text,
    year_2009 text,
    year_2010 text,
    year_2011 text);

crosstab()函数未包含在标准PostgreSQL中,但附带additional module tablefunc

编辑其他请求

没有crosstab()功能的版本: 仅按client_id分组,否则每个client_id最终会有多行。

SELECT client_id
      ,sum(CASE WHEN extract(year from date) = 2001 THEN amount ELSE 0 END) AS year_2001
      ,sum(CASE WHEN extract(year from date) = 2002 THEN amount ELSE 0 END) AS year_2002
       -- ...
FROM   orders o
GROUP  BY 1
ORDER  BY 1;