Question

假设对象是$ Item。当我使用var_dump（$ Item）转储它时给出：

object(ProductVariation_OrderItem)[29]
  protected '_productVariationID' => string '6114' (length=4)
  protected '_productVariationVersion' => string '4' (length=1)
  protected '_productID' => string '4220' (length=4)
  protected '_productVersion' => string '72' (length=2)
  protected '_id' => null
  protected '_quantity' => string '1' (length=1)
  protected '_custom_text' => string 'erger ~~ gerger' (length=15)
  protected '_custom_text_id' => string 'b266dfceb5db66c01f08d97c45ebccf1' (length=32)
  public 'destroyed' => boolean false
  protected 'record' => 
    array
      'ID' => int 0
      'ClassName' => string 'ProductVariation_OrderItem' (length=26)
      'RecordClassName' => string 'ProductVariation_OrderItem' (length=26)
  protected 'changed' => 
    array
      empty
  protected 'original' => 
    array
      'ID' => int 0
      'ClassName' => string 'ProductVariation_OrderItem' (length=26)
      'RecordClassName' => string 'ProductVariation_OrderItem' (length=26)
  protected 'components' => null
  protected 'brokenOnWrite' => boolean false
  protected 'brokenOnDelete' => boolean false
  protected 'componentCache' => null
  protected 'iteratorPos' => int 0
  protected 'iteratorTotalItems' => int 1
  protected 'failover' => null
  protected '_object_cache' => 
    array
      empty
  protected '_xml_cache' => 
    array
      empty
  protected '_natural_cache' => 
    array
      empty
  protected 'customisedObj' => null
  protected 'parent' => null
  protected 'namedAs' => null
  public 'class' => string 'ProductVariation_OrderItem' (length=26)
  protected 'extension_instances' => 
    array
      empty

当我使用var_dump（$ Item-＆gt; productVariationID）时它返回6114 ..但是当我使用var_dump（$ Item-＆gt; custom_text）时，它返回null ..我不明白这里有什么问题。请有人解释一下。

Answer 1

您的对象中没有$Item->custom_text或$Item->productVariationID

当我尝试从PHP对象中检索值时，它返回null

1 个答案: