Question

我正在尝试从url中检索xml标记名中的内容，但我的int numberOfDetails长度为0.我做错了什么？

//编辑代码

public String[] dumpTitles(String[] xmlFiles) {


        String[] elementsArray = null;
        try { 
            URL xmlContent = new URL("http://webdev4.matcmadison.edu/mab/AmazonXML/georgeEliot.xml");
            DocumentBuilder db = DocumentBuilderFactory.newInstance().newDocumentBuilder();
            Document doc = db.parse(new InputSource(xmlContent.openStream()));


            Toast.makeText(this, "xml file: " + xmlContent, 1000).show();

            NodeList detailsNodeList = doc.getElementsByTagName("Details");
            int numberOfDetails = detailsNodeList.getLength();
            String str = String.format("There are %d Details elements", numberOfDetails);
            Log.println(Log.DEBUG, TAG, str);
            Toast.makeText(this, "number of details: " + str, 1000).show();
            elementsArray = getElementByTagName("ProductName", numberOfDetails, detailsNodeList);
        }
        catch (Exception ex) {
            Log.println(Log.DEBUG, TAG, "XML Parsing failed: " + ex.getMessage());
        }

        return elementsArray;  

    }

  public String[] getElementByTagName(String detailTagName, int numberOfDetails, NodeList detailsNodeList) throws Exception {
      String[] elementsArray = null;
      ArrayList<String> elementsArrayList = new ArrayList<String>();
      Toast.makeText(this, "TEST2", 1000).show();
        for (int k = 0; k < numberOfDetails; k++) {
            Toast.makeText(this, "TEST3", 1000).show();
            Element nDetails = (Element)detailsNodeList.item(k);
            NodeList elementNodeList = ((Document) nDetails).getElementsByTagName(detailTagName);
            Node nodeName = elementNodeList.item(k);
            String nodeString = String.format("%s", nodeName);
            elementsArrayList.add(nodeString);
            elementsArray = elementsArrayList.toArray(elementsArray);
            Log.println(Log.DEBUG, TAG, nodeString);
            Toast.makeText(this, "TEST4", 1000).show();
            Toast.makeText(this, "ELEMENT" + elementsArray[0], 1000).show();

        }

        return elementsArray;
}

//原始代码 String xmlContent =“http://webdev4.matcmadison.edu/mab/AmazonXML/georgeEliot.xml”; Log.println（Log.DEBUG，TAG，“FILE NAME：”+ xmlContent）; String [] elementsArray = null; 尝试{ DocumentBuilder db = DocumentBuilderFactory.newInstance（）。newDocumentBuilder（）; Toast.makeText（this，“xml file：”+ xmlContent，1000）.show（）; Document doc = db.parse（new InputSource（new StringReader（xmlContent）））; NodeList detailsNodeList = doc.getElementsByTagName（“Details”）; int numberOfDetails = detailsNodeList.getLength（）;

Answer 1

您不应使用StringReader来读取网址。 StringReader读取您在构造函数中传递的字符串，它不会从Web下载文件。您可以改为使用URL类：

URL xmlContent = new URL("http://webdev4.matcmadison.edu/mab/AmazonXML/georgeEliot.xml");
DocumentBuilder db = DocumentBuilderFactory.newInstance().newDocumentBuilder();
Document doc = db.parse(new InputSource(xmlContent.openStream()));

另一种方式：

您可以InputSource String String pathToDocument = "http://webdev4.matcmadison.edu/mab/AmazonXML/georgeEliot.xml"; Document doc = db.parse(new InputSource(pathToDocument));使用{{1}}：

{{1}}

从URL解析Java中的XML标记名

1 个答案: