Question

我有一个SQL查询返回的这个对象数组，其中top_id是我的父ID字段：

Array (
[0] => stdClass Object ( [id] => 1 [top_id] => 0 [name] => Cat 1 )
[1] => stdClass Object ( [id] => 2 [top_id] => 0 [name] => Cat 2 ) 
[2] => stdClass Object ( [id] => 3 [top_id] => 0 [name] => Cat 3 ) 
[3] => stdClass Object ( [id] => 4 [top_id] => 2 [name] => Subcat 1 ) 
[4] => stdClass Object ( [id] => 5 [top_id] => 2 [name] => Subcat 2 ) 
[5] => stdClass Object ( [id] => 6 [top_id] => 3 [name] => Subcat 3 ) 
[6] => stdClass Object ( [id] => 7 [top_id] => 5 [name] => Subcat 4 )
)

现在我需要使用PHP获取这样的嵌套列表：

<ul>
  <li>Cat 1</li>
  <li>Cat 2
    <ul>
      <li>Subcat 1</li>
      <li>Subcat 2
        <ul>
          <il>Subcat 3
            <ul>
              <li>Subcat 4</li>
            </ul>
          </li>
        </ul>
      </li>
    </ul>
  </li>
  <li>Cat 3</li>
</ul>

有什么想法吗？感谢

Answer 1

首先将对象映射到索引为id的新哈希（数组）中：

// map the array onto hash
$hash = array();
foreach($array as $object)
{
    $hash[$object->id] = array('object' => $object);
}

然后将这个扁平哈希转换为树状结构，请参阅此answer for another code example，它在这里只是一样：

// build tree from hash
$tree = array();
foreach($hash as $id => &$node)
{
    if ($parent = $node['object']->top_id)
        $hash[$parent]['children'][] =& $node;
    else
        $tree[] =& $node;
}
unset($node, $hash);

最后，您可以将此树状结构输出为HTML。这可以使用堆栈或递归来完成。这是递归的一个变种：

// render tree
function render_tree($tree)
{
    echo '<ul>', "\n";
    foreach($tree as $node)
    {
        render_node($node);
    }
    echo '</ul>';
}

// render tree node
function render_node($node, $level = 0)
{
    $inset = str_repeat('    ', $level) . '  ';
    echo $inset, '<li>', $node['object']->name;
    if (isset($node['children']))
    {
        echo "\n", $inset, '  <ul>', "\n";
        foreach($node['children'] as $node)
        {
            render_node($node, $level+1);
        }
        echo $inset, '  </ul>', "\n", $inset;
    }
    echo '</li>', "\n";
}

// output
render_tree($tree);

输出：

<ul>
  <li>Cat 1</li>
  <li>Cat 2
    <ul>
      <li>Subcat 1</li>
      <li>Subcat 2
        <ul>
          <li>Subcat 4</li>
        </ul>
      </li>
    </ul>
  </li>
  <li>Cat 3
    <ul>
      <li>Subcat 3</li>
    </ul>
  </li>
</ul>

Full code Example + HTML Demo

如何从对象的数组记录集中获取嵌套的HTML列表？

1 个答案: