我刚刚使用Facebook JavaScript在我的网站上实施了Facebook身份验证。
如果用户第一次从我的网站登录Facebook，然后需要将数据插入users表（mysql） - 可能是一个名为fb_userid的字段和电子邮件？
我已经阅读了JavaScript SDK上的文档，我可以获得Facebook用户ID但是如何将其传递给PHP以便我可以插入到users表中？
Facebook Javascript看起来像这样：
<script>
window.fbAsyncInit = function() {
FB.init({
appId : 'xxxxxxxx', // App ID
status : true, // check login status
cookie : true, // enable cookies to allow the server to access the session
oauth : true, // enable OAuth 2.0
xfbml : true // parse XFBML
});
(function(d){
var js, id = 'facebook-jssdk'; if (d.getElementById(id)) {return;}
js = d.createElement('script'); js.id = id; js.async = true;
js.src = "//connect.facebook.net/en_US/all.js";
d.getElementsByTagName('head')[0].appendChild(js);
}(document));
在登录页面上：
<fb:login-button scope="email" autologoutlink="true"></fb:login-button>
是否可以使用PHP SDK获取Facebook用户ID？
在使用PHP SDK之前是否需要加载Facebook JavaScript文件？
答案 0 :(得分：1)
此代码获取用户数据并将其序列化，并抛出到数据库，我知道它不完美但看看。当我获得一些空闲时间时，我将编辑这个，然后我建议将用户数据编码为JSON，而不是base64序列化，因为将来查询搜索会更容易。
<?php
require 'facebook.php'; // USE FACEBOOK PHP SDK
// Create our Application instance (replace this with your appId and secret).
$facebook = new Facebook(array(
'appId' => 'APPID',
'secret' => 'APPSECRET',
));
// ----------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------
// Get User ID
$user = $facebook->getUser();
/* We may or may not have this data based on whether the user is logged in.
If we have a $user id here, it means we know the user is logged into
Facebook, but we don't know if the access token is valid. An access
token is invalid if the user logged out of Facebook. */
if ($user) {
try {
// Proceed knowing you have a logged in user who's authenticated.
$dt = $facebook->api('/me');
$lk = $facebook->api('/me/likes');
} catch (FacebookApiException $e) {
error_log($e);
$user = null;
}
}
// ----------------------------------------------------------------------------------------
// ----------------------------------------------------------------------------------------
// Handler for Login Status
if ($user) {
$logoutUrl = $facebook->getLogoutUrl();
} else {
$loginUrl = $facebook->getLoginUrl(array("scope" => "email,user_birthday,user_likes,user_work_history,user_location,user_education_history"));
}
// ----------------------------------------------------------------------------------------
?>
<?php if (!$user): header ('Location:'.$loginUrl.''); //CHECKS IF USER IS LOGGED IN
else:
$con = mysql_connect("DATABASE IP","USERNAME","PASS");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
else{
$id = base64_encode(serialize($dt['id']));
$work = base64_encode(serialize($dt['work']));
$location = base64_encode(serialize($dt['location']));
$education = base64_encode(serialize($dt['education']));
$f_n = $dt['first_name'];
$l_n = $dt['last_name'];
$link = $dt['link'];
$u_n = $dt['username'];
$bd = $dt['birthday'];
$gdr = $dt['gender'];
$em = $dt['email'];
$sportsS = base64_encode(serialize($dt['sports']));
$languagedt = $dt['languages'];
foreach($languagedt as $item){
$language[] = $item;
}
$languageS = base64_encode(serialize($language));
$lk_dt = $lk['data'];
foreach($lk_dt as $value)
{
if ($value['category'] == "Musician/band" || $value['category'] == "Song" ){
$fav_music[] = $value;
}
if($value['category'] == "Tv show"){
$fav_tvshow[] = $value;
}
if($value['category'] == "Book"){
$fav_book[] = $value;
}
if($value['category'] == "Movie"){
$fav_movie[] = $value;
}
if($value['category'] == "Games/toys"){
$fav_games[] = $value;
}
if($value['category'] == "Interest"){
$interest[] = $value;
}
if($value['category'] == "Professional sports team"){
$sport_team[] = $value;
}
// next is likes
if ($value['category'] != "Movie" && $value['category'] != "Musician/band" && $value['category'] != "Book" && $value['category'] != "Games/toys" && $value['category'] != "Tv show" && $value['category'] != "Professional sports team" && $value['category'] != "Interest" && $value['category'] != "Tv show" && $value['category'] != "Professional sports team" && $value['category'] != "Song") {
$likes[] = $value;
}
}
$fav_musicS = base64_encode(serialize($fav_music));
$fav_movieS = base64_encode(serialize($fav_movie));
$fav_bookS = base64_encode(serialize($fav_book));
$fav_tvshowS = base64_encode(serialize($fav_tvshow));
$sport_teamS = base64_encode(serialize($sport_team));
$fav_gamesS = base64_encode(serialize($fav_games));
$interestS = base64_encode(serialize($interest));
$likesS = base64_encode(serialize($likes));
mysql_select_db("database", $con);
$result = mysql_query("SELECT id, firstdone FROM users WHERE id='$id'");
$row = mysql_fetch_array($result);
$f_dn = $row['firstdone'];
$ctrl = $row['id'];
if (!$ctrl){
mysql_query("INSERT INTO users (id, language, fav_sports, education, location, work, first_name, last_name, link, username, birthday, gender, email, fav_music, fav_movie, fav_books, fav_tv, fav_sport, fav_games, interest, likes)
VALUES ('$id', '$languageS', '$sportsS', '$education', '$location', '$work', '$f_n', '$l_n', '$link', '$u_n', '$bd', '$gdr', '$em', '$fav_musicS', '$fav_movieS', '$fav_bookS', '$fav_tvshowS', '$sport_teamS', '$fav_gamesS', '$interestS', '$likesS')");
if ($_SERVER['REQUEST_URI'] == '/index.php') {
header('Location: /theprofilepage');}
}
else{
mysql_query("UPDATE users SET language='$languageS', fav_sports='$sportsS', first_name='$f_n', last_name='$l_n', link='$link', username='$u_n', birthday='$bd', gender='$gdr', email='$em', fav_music='$fav_musicS', fav_movie='$fav_movieS', fav_books='$fav_bookS', fav_tv='$fav_tvshowS', fav_sport='$sport_teamS', fav_games='$fav_gamesS', interest='$interestS', likes='$likesS', work='$work', location='$location', education='$education' WHERE id='$id'");
}
mysql_close($con);
}endif
?>
你可以用JavaScript获得你想要的值，然后通过“位置”函数将它们作为标题传递，然后php会用$ _GET获取这些信息，我建议使用PHP SDK来做认真的东西。但你选择。你也可以一起使用它们。
答案 1 :(得分：-1)
在我看来，最好的办法是使用Javascript（在我的示例中使用jQuery）在后台调用PHP页面，将用户添加到数据库中。
Page head：
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.6.4/jquery.min.js"></script>
<script type="text/javascript">
function (data)
{
file = 'adddata.php?data=' + data;
$.get(file, function(content)
{
if (content == 'OK')
{
alert('Data added to the database!');
}
else
{
alert('Error adding data to the database!');
}
});
}
</script>
adddata.php 的示例：
<?php
$dblink = mysqli_connect(mysql_data_here);
$query = 'INSERT INTO users VALUES (' . $_GET['data'] . ');';
$ok = $mysqli_query($query);
if ($ok == true)
{
echo 'OK';
}
else
{
echo 'Failed';
}
?>
当然，您需要在PHP脚本中转义传入的数据并稍微更改SQL查询，但这是一般的想法。