Question

我需要使用preg_replace或其他方式替换以'Title：'开头并以'Article Body：'结尾的文本。替换的文字不会包含上面引用的单词。

例如：

名称：

示例文本1

文章正文：

示例文本2

只能输出

示例文本2

我怎么能用PHP做到这一点？

Answer 1

$str = 'Title: this is sample text Article Body: this is also sample text';

// output: this is sample text this is also sample text
echo preg_replace('~Title: (.*)Article Body: (.*)~', '$1 $2', $str);

正则表达式非常有用，您应该学习如何使用它。网上有很多文章，这个summarize也可以帮到你。

Answer 2

使用正面/负面前瞻。

$result = preg_replace('/(?<=Title:).*(?=Article Body:)/s', '\nTest\n', $subject);

以上正则表达式将取代标题内的任何内容：...文章正文：使用\ nTest \ n

说明：

"
(?<=                # Assert that the regex below can be matched, with the match ending at this position (positive lookbehind)
   Title:              # Match the characters “Title:” literally
)
.                   # Match any single character
   *                   # Between zero and unlimited times, as many times as possible, giving back as needed (greedy)
(?=                 # Assert that the regex below can be matched, starting at this position (positive lookahead)
   Article\ Body:      # Match the characters “Article Body:” literally
)
"

用php替换段落中的特定文本模式

2 个答案: