是否有可能在运行时获得具有可变数量类型参数的泛型类的类型?
即,基于数字,我们可以得到具有这么多元素的元组类型吗?
Type type = Type.GetType("System.Tuple<,>");
答案 0 :(得分:6)
编写的方式是
Type generic = Type.GetType("System.Tuple`2");
泛型类型的格式很简单:
"Namespace.ClassName`NumberOfArguments"
`是角色96.(ALT + 96)。
但是我会避免使用字符串,它比使用typeof或更好的数组查找慢。 我会提供一个快速数千倍的静态函数...
private static readonly Type[] generictupletypes = new Type[]
{
typeof(Tuple<>),
typeof(Tuple<,>),
typeof(Tuple<,,>),
typeof(Tuple<,,,>),
typeof(Tuple<,,,,>),
typeof(Tuple<,,,,,>),
typeof(Tuple<,,,,,,>),
typeof(Tuple<,,,,,,,>)
};
public static Type GetGenericTupleType(int argumentsCount)
{
return generictupletypes[argumentsCount];
}
答案 1 :(得分:0)
试试这个:
using System;
using System.Collections.Generic;
using System.Text;
using System.Threading;
using System.Reflection;
using System.Reflection.Emit;
public class MainClass
{
public static void Main()
{
PrintTypeParams(typeof(Tuple<int, double, string>));
}
private static void PrintTypeParams(Type t)
{
Console.WriteLine("Type FullName: " + t.FullName);
Console.WriteLine("Number of arguments: " + t.GetGenericArguments().Length);
Console.WriteLine("List of arguments:");
foreach (Type ty in t.GetGenericArguments())
{
Console.WriteLine(ty.FullName);
if (ty.IsGenericParameter)
{
Console.WriteLine("Generic parameters:");
Type[] constraints = ty.GetGenericParameterConstraints();
foreach (Type c in constraints)
Console.WriteLine(c.FullName);
}
}
}
}
输出:
Type FullName: System.Tuple`3[[System.Int32, mscorlib, Version=4.0.0.0, Culture=
neutral, PublicKeyToken=b77a5c561934e089],[System.Double, mscorlib, Version=4.0.
0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089],[System.String, mscorlib,
Version=4.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089]]
Number of arguments: 3
List of arguments:
System.Int32
System.Double
System.String