我有一张类型为map[string]interface{}
最后,我开始创建类似的东西(在使用goyaml从yml文件反序列化之后)
mymap = map[foo:map[first: 1] boo: map[second: 2]]
如何迭代这张地图?我尝试了以下方法:
for k, v := range mymap{
...
}
但是我收到了一个错误:
cannot range over mymap
typechecking loop involving for loop
请帮忙。
答案 0 :(得分:76)
例如,
package main
import "fmt"
func main() {
type Map1 map[string]interface{}
type Map2 map[string]int
m := Map1{"foo": Map2{"first": 1}, "boo": Map2{"second": 2}}
//m = map[foo:map[first: 1] boo: map[second: 2]]
fmt.Println("m:", m)
for k, v := range m {
fmt.Println("k:", k, "v:", v)
}
}
输出:
m: map[boo:map[second:2] foo:map[first:1]]
k: boo v: map[second:2]
k: foo v: map[first:1]
答案 1 :(得分:5)
你可以用一行来制作它:
mymap := map[string]interface{}{"foo": map[string]interface{}{"first": 1}, "boo": map[string]interface{}{"second": 2}}
for k, v := range mymap {
fmt.Println("k:", k, "v:", v)
}
输出是:
k: foo v: map[first:1]
k: boo v: map[second:2]
答案 2 :(得分:0)
您可以像这样在多行中写出来,
$ cat dict.go
package main
import "fmt"
func main() {
items := map[string]interface{}{
"foo": map[string]int{
"strength": 10,
"age": 2000,
},
"bar": map[string]int{
"strength": 20,
"age": 1000,
},
}
for key, value := range items {
fmt.Println("[", key, "] has items:")
for k,v := range value.(map[string]int) {
fmt.Println("\t-->", k, ":", v)
}
}
}
输出:
$ go run dict.go
[ foo ] has items:
--> strength : 10
--> age : 2000
[ bar ] has items:
--> strength : 20
--> age : 1000