Question

Doctrine 2中是否有任何方法提示在自动生成数据库时应将列编入索引？我有一个线程实体：

Entities\Thread:
  type: entity
  table: Thread
  repositoryClass: Repositories\ThreadRepository
  id:
    id:
      type: integer
      generator:
        strategy: AUTO
  fields:
    type:
      type: enumthreadtype
    code:
      type: string
      length: 10
      nullable: true
  manyToOne:
    group:
      targetEntity: Group
      inversedBy: threads
  oneToMany:
    messages:
      targetEntity: Message
      mappedBy: thread
    attachments:
      targetEntity: ThreadAttachment
      mappedBy: thread

线程经常通过他们的“代码”搜索 - 一个10个字符的随机字符串 - 而不是他们的id。有没有办法表明应该使用yaml创建索引，还是只需要在创建表后在我的数据库中执行此操作？

Answer 1

我无法在yaml中找到相关文档，但在阅读Doctrine\ORM\Mapping\ClassMetadatainfo之后我发现它如下：

如果您想索引代码字段，您的yaml映射将是

Entities\Thread:
  type: entity
  table: Thread
  indexes:
      # _idx as suffix...
      thread_code_idx:
          columns: [ code ]
      # We can specify multiple indexes 
      another_idx
          # we can specify multiple columns for compound indexes
          columns [ type, code ] 
  repositoryClass: Repositories\ThreadRepository
  id:
    id:
      type: integer
      generator:
        strategy: AUTO
  fields:
    type:
      type: enumthreadtype
    code:
      type: string
      length: 10
      nullable: true
  manyToOne:
    group:
      targetEntity: Group
      inversedBy: threads
  oneToMany:
    messages:
      targetEntity: Message
      mappedBy: thread
    attachments:
      targetEntity: ThreadAttachment
      mappedBy: thread

如何强制或“暗示”应该在yaml中索引实体字段？

1 个答案: