Question

所以我试图改变我的sql代码（见下面的当前结果的截图+ sql）按月分组数据并总结所有的paymentSplitAmounts。每行应该是唯一的productId

所以最终的结果就像是

    productID        total        month
    1                500          11-2011
    2                650          11-2011
    3                250          11-2011
    1                100          10-2011
    2                150          10-2011
    3                750          10-2011

我似乎无法正确使用语法。我哪里错了？

http://imgur.com/UC5Si

    select  
        cpd.paymentId, cpd.paymentId, cpd.productId, cpd.paymentSplitAmount, cp.campaignId, cp.paymentDate 
    from campaign_payment_detail cpd 
    inner join 
        campaign_payment cp on cp.paymentId = cpd.paymentId 
    inner join product on cpd.productId = product.productId 
    where 
    1=1 
    and cp.campaignId = 2413

Answer 1

看起来您想分组然后对结果进行排序：

SELECT cpd.productId, SUM(cpd.paymentSplitAmount), DATE_FORMAT(cp.paymentDate, '%b-%Y')
  FROM campaign_payment_detail cpd
  JOIN campaign_payment cp ON cp.paymentId = cpd.paymentId
  JOIN product ON cpd.productId = product.productId
 WHERE cp.campaignId = 2413
 GROUP BY cpd.productId, DATE_FORMAT(cp.paymentDate, '%b-%Y')
 ORDER BY cp.paymentDate DESC, cpd.productId ASC

编辑：使用DATE_FORMAT格式化日期。

Answer 2

首先，根据您提供的查询而没有其他信息，表格产品无用..

我会这样做：

select  
        cpd.paymentId,
        SUM(cpd.paymentSplitAmount) as total, 
        cp.campaignId, 
        cp.paymentDate 
    from campaign_payment_detail cpd 
    inner join 
        campaign_payment cp on cp.paymentId = cpd.paymentId 
    where 
    cp.campaignId = 2413
GROUP BY cpd.productId, cp.paymentDate
ORDER BY cpd.paymentId ASC, cp.paymentDate DESC

Answer 3

您已经提到'分组'了。为此，您需要在查询中添加group by，按照productid和month对数据进行分组，然后添加sum以汇总paymentSplitAmount。

分组语法没有错，完全缺失。：）

select  
    cpd.productId, sum(cpd.paymentSplitAmount) as total, date_format(cp.paymentDate, '%m-%Y')
from campaign_payment_detail cpd 
inner join campaign_payment cp on cp.paymentId = cpd.paymentId 
inner join product on cpd.productId = product.productId 
where 
  cp.campaignId = 2413
group by cp.productId, date_format(cp.paymentDate, '%m-%Y')
order by date_format(cp.paymentDate, '%m-%Y') desc, cp.productId

~~这假定cp.paymentDate已包含月份。如果没有，您将必须将每个日期舍入到该月的第一天并按此分组。~~

现在按月分组。

按日期范围和productId对MySQL查询进行分组

3 个答案: