Question

我有一个使用此查询的SQL视图：

SELECT dbo.FBAShipmentItems.ShipmentID, dbo.FBAShipmentItems.FNSKU, dbo.FBAShipmentItems.ASIN, dbo.FBAShipmentItems.Merchant, dbo.FBAShipments.ShipmentName, dbo.FBAShipments.Prep_Type, dbo.FBAShipmentItems.Quantity FROM dbo.FBAShipmentItems INNER JOIN dbo.FBAShipments ON dbo.FBAShipmentItems.ShipmentID = dbo.FBAShipments.ShipmentID

问题是，当我在FBAShipmentItems中接近900个项目而在FBAShipments中有51个项目时，它只显示56个结果。如何在我的观点中获得所有900个结果

Answer 1

使用LEFT JOIN代替INNER JOIN：

SELECT
    items.ShipmentID,
    items.FNSKU,
    items.ASIN,
    items.Merchant,
    shipments.ShipmentName,
    shipments.Prep_Type,
    items.Quantity
FROM dbo.FBAShipmentItems AS items
LEFT JOIN dbo.FBAShipments AS shipments
ON items.ShipmentID = shipments.ShipmentID

这将返回FBAShipmentItems中的所有行以及来自FBAShipments的匹配行（如果有），否则返回NULL表示该表中的所有值。

选择仅显示某些结果的视图

1 个答案: