Question

如标题所示，我在过滤/搜索列表视图时遇到问题。当我尝试搜索让我们说“A”时，listView显示A-31两次，A-32显示两次，依此类推。有谁知道为什么会这样？

package hpliu.grupp2;

import android.content.Intent;
import android.os.Bundle;
import android.os.Debug;
import android.text.Editable;
import android.text.TextWatcher;
import android.view.View;
import android.widget.TableRow;

import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;

import android.app.ListActivity;
import android.app.Activity;

import android.widget.EditText;
import android.widget.ListView;
import android.widget.SimpleAdapter;
import android.widget.Toast;

public class SearchRoomActivity extends ListActivity {
    private EditText filterText = null;
    SimpleAdapter menu = null;
    ListView lv = null;

    static final String[] AHalls = new String[] { "A-31", "A-32", "A-33",
            "A-34", "A-35", "A-36", "A-37" };

    String[] from = new String[] { "roomName", "buildingName" };

    /** Called when the activity is first created. */

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.search_room);

        createCampusList("Campus Valla, Linköping",
                createHashMap(AHalls, "A Huset"));

        // filterText = (EditText) findViewById(R.id.search_box);
        // filterText.addTextChangedListener(filterTextWatcher);
    }

    private TextWatcher filterTextWatcher = new TextWatcher() {

        public void afterTextChanged(Editable s) {
        }

        public void beforeTextChanged(CharSequence s, int start, int count,
                int after) {
        }

        @Override
        public void onTextChanged(CharSequence s, int start, int before,
                int count) {
            menu.getFilter().filter(s);
        }

    };

    protected void onListItemClick(ListView l, View v, int position, long id) {
        super.onListItemClick(l, v, position, id);

        try {
            @SuppressWarnings("unchecked")
            HashMap<String, String> toHash = (HashMap<String, String>) this
                    .getListAdapter().getItem(position); // {text1 = "A-31",
                                                            // text2 = "Herp"};

            Toast.makeText(
                    this,
                    "Searching for... " + " "
                            + toHash.get("roomName").toString(),
                    Toast.LENGTH_SHORT).show();
        } catch (Exception e) {
            e.printStackTrace();
        }
    }

    public List<HashMap<String, String>> createHashMap(String[] Halls,
            String Building) {
        List<HashMap<String, String>> fillMaps = new ArrayList<HashMap<String, String>>();
        for (int i = 0; i < Halls.length; i++) {
            HashMap<String, String> map = new HashMap<String, String>();
            map.put(from[0], Halls[i]);
            map.put(from[1], Building);
            fillMaps.add(map);
        }
        return fillMaps;
    }

    public List<HashMap<String, String>> createHashMap(String[] Halls,
            String[] Buildings) {
        List<HashMap<String, String>> fillMaps = new ArrayList<HashMap<String, String>>();
        for (int i = 0; i < Halls.length; i++) {
            HashMap<String, String> map = new HashMap<String, String>();
            map.put(from[0], Halls[i]);
            map.put(from[1], Buildings[i]);
            fillMaps.add(map);
        }
        return fillMaps;
    }

    public void createCampusList(String campusHeader,
            List<HashMap<String, String>> fillMaps) {

        int[] to = new int[] { R.id.roomName, R.id.buildingName };

        menu = new SimpleAdapter(this, fillMaps, R.layout.list_item, from, to);
        setListAdapter(menu);
        lv = getListView();
        lv.setTextFilterEnabled(true);
    }

    @Override
    protected void onDestroy() {
        super.onDestroy();
        filterText.removeTextChangedListener(filterTextWatcher);
    }
}

Answer 1

如果过滤每个项目中包含两个字符串的适配器，则过滤器将通过适配器两次。这就是你有倍数的原因。如果你有三个字符串，你可能会得到三个重复的项目。

我在网上找到的一个解决方案是创建一个自定义SimpleAdapter并在填充ListView之前检查重复项。

Answer 2

我的自定义列表视图面临同样的问题。

listview的超类不知道您在过滤后已更改了大小。这意味着getCount（）将返回数组的原始大小，这可以理解地大于过滤后的数组。因此，您必须覆盖getCount（）函数以返回已过滤数组的大小，而不是原始数组。之后，重复的项目消失了。

@Override    
public int getCount() {
    return filter_array.size();
    }
@Override
    public Object getItem(int position) {
    return filter_array.get(position);
    }

Android，ListView搜索/过滤 - ＆gt;重复的条目

2 个答案: