我目前正在处理上传页面,用户在表格中输入值,然后点击提交。我将检查表单是否已提交,如果提交表明它们不是空的。这是我目前的代码
function validPost()
{
if(isset($_POST["title"]) && //if a post has been submitted
isset($_POST["artist"]) &&
isset($_POST["genre"]) &&
isset($_POST["url"]) &&
isset($_POST["user"]) )
{
if (strlen($_POST['title']) <= 0) {
echo 'ERROR: Please enter a title. </ br>';
return false;
}
else if (strlen($_POST['artist']) <= 0) {
echo 'ERROR: Please enter an artist. </ br>';
return false;
}
else if (strlen($_POST['genre']) <= 0) {
echo 'ERROR: Please select a genre. </ br>';
return false;
}
else if (strlen($_POST['url']) <= 0) {
echo 'ERROR: Please enter a url. </ br>';
return false;
}
else if (strlen($_POST['user']) <= 0) {
echo 'ERROR: Please enter a username to submit the song (or make one up). </ br>';
return false;
}
else
return true;
}
else //if no post was submitted
{
return false;
}
}
有更优雅的方式来检查吗?我计划将来为这些表单提交的内容添加更多检查,我觉得这是一种草率的方式。
谢谢!
答案 0 :(得分:7)
假设所有字段仅检查非零字符串长度:
$field_checks = array(
// 'fieldname' => 'errormessage'
'title' => 'Please enter a title',
'url' => 'Please enter a URL',
etc...
);
$errors = array();
foreach ($field_checks as $field => $errmsg) {
if (!isset($_POST[$field]) || ($_POST[$field] === '')) {
$errors[] = $errmsg;
}
}
if (count($errors) > 0) {
print_r($errors); // probably want a nicer error display than this
return false;
}
答案 1 :(得分:-2)
检查jQuery和validate插件