Question

我在使用带有url_for方法的对象时遇到了问题，我认为这个想法是自动找到任何需要的parapeters吗？

The "/publish/:id/:token" route has some missing mandatory parameters (:id, :token).

的routing.yml

post_publish:
  url:     /publish/:id/:token
  options:
    model: HookupPost
    type:  object
    method_for_criteria: doSelectOneInactive
  param:   { module: post, action: show }
  requirements:
    id: \d+
    token: \w+
    sf_method: [GET]

newSuccess.php

<?php echo public_path(url_for("@post_publish", $post), true); ?>

操作传递$ post并包含最近创建的帖子！

有谁知道为什么会出现这种错误？我误解了什么吗？

谢谢，

Answer 1

你错过了sfDoctrineRoute声明：

post_publish:
  url:     /publish/:id/:token
  class:   sfDoctrineRoute
  options:
    model: HookupPost
    type:  object
    method_for_criteria: doSelectOneInactive
  param:   { module: post, action: show }
  requirements:
    id: \d+
    token: \w+
    sf_method: [GET]

然后你可以这样做：

<?php echo public_path(url_for("post_publish", $post), true); ?>

参考：http://www.symfony-project.org/jobeet/1_4/Doctrine/en/05

Answer 2

尝试：

<?php echo public_path(url_for("post_publish", 
        array( 'id' => $post->id, 'token' => $post->token )), true); ?>

或类似的内容，具体取决于您的Post课程。

PHP Symfony Route有一些缺少必需参数

2 个答案: