如何存储ajax调用的结果将json返回到变量中?

时间:2011-11-03 20:35:49

标签: jquery json

如何替换此json代码:

var contacts = [
    { firstName: 'Mohammed', lastName: 'Shurrab', phone: '0599000000' },
    { firstName: 'Osama', lastName: 'Abu Kmail', phone: '0599111111' },
    { firstName: 'Alaa', lastName: 'Saqer', phone: '0599666666' }
];

从jquery ajax调用(getJson)到以下返回json的url的结果:

amerenaya.com/CI/index.php/hello/example5

并将结果存储在变量联系人中?

在javascript代码中使用?

1 个答案:

答案 0 :(得分:0)

var contacts;

$.getJSON('http://amerenaya.com/CI/index.php/hello/example5').success(function(data) {
    contacts = eval(data);
});