在foreach中改变循环

Question

我是php的新手。我正在阅读RSS源并存储在我的数据库表中。 为此，我使用

$num = count($movies->channel->item);
for ($i=0; $i<=$num-1; $i++){
    $tittle= $movies->channel->item[$i]->title."<br/>";
    $link=$movies->channel->item[$i]->link."<br/>";
    $image=$movies->channel->item[$i]->medium_image_url."<br/>";
    $des=$movies->channel->item[$i]->description."<br/>";
    $city=$movies->channel->item[$i]->city;
}

如何使用foreach循环显示所有数据？

Answer 1

您可以echo声明结果（我已根据要求将其更改为foreach）：

foreach ($movies->channel->item as $item) {
  $tittle= $item->title."<br/>";
  $link=$item->link."<br/>";
  $image=$item->medium_image_url."<br/>";
  $des=$item->description."<br/>";
  $city=$item->city;

  echo $tittle.$link.$image.$des.$city;
}

Answer 2

 foreach($movies->channel->item as $opt){
     echo $tittle= $opt->title."<br/>";
     echo $link=$opt->link."<br/>";
     echo $image=$opt->medium_image_url."<br/>";
     echo $des=$opt->description."<br/>";
     echo $city=$opt->city;
 }

Answer 3

foreach ($movies->channel->item as $item) {
  echo $item->title.'<br />';
  echo $item->link.'<br />';
  echo $item->medium_image_url.'<br />';
  echo $item->description.'<br />';
  echo $item->city;
}

我已经回应了他们，因为我认为这是你想要做的事情 - 你的代码在每次迭代时重新分配变量，但对它们没有任何作用。它们每次都被覆盖，因此它们只保留最后一次迭代的值。

修改

您可以通过执行以下操作轻松修改此操作以将行插入数据库：

foreach ($movies->channel->item as $item) {
  echo $item->title.'<br />';
  echo $item->link.'<br />';
  echo $item->medium_image_url.'<br />';
  echo $item->description.'<br />';
  echo $item->city.'<br />';

  // Build the query - change the names of your table and columns as appropriate
  $query = "INSERT INTO `tablename` 
              (`title`,`link`,`medium_image_url`,`description`,`city`)
            VALUES
              ('$item->title','$item->link','$item->medium_image_url','$item->description','$item->city')";
  // Do the query - do NOT show the output of mysql_error() in a production environment!
  if (!mysql_query($query)) echo 'Oh no! Something went wrong with the query: '.mysql_error();
}

或者，您可以将其全部转换为一个查询，以最大限度地减少数据库流量：

$rows = array();
foreach ($movies->channel->item as $item) {
  echo $item->title.'<br />';
  echo $item->link.'<br />';
  echo $item->medium_image_url.'<br />';
  echo $item->description.'<br />';
  echo $item->city.'<br />';
  // Add this entry to $rows
  $rows[] = "('$item->title','$item->link','$item->medium_image_url','$item->description','$item->city')";
}

// Build the query - change the names of your table and columns as appropriate
$query = "INSERT INTO `tablename` 
            (`title`,`link`,`medium_image_url`,`description`,`city`)
          VALUES ".implode(', ',$rows);
// Do the query - do NOT show the output of mysql_error() in a production environment!
if (!mysql_query($query)) echo 'Oh no! Something went wrong with the query: '.mysql_error();

Answer 4

这应该有效：

foreach ($movies as $movie)
    $tittle = $movie->title."<br/>";
    $link = $movies->link."<br/>";
    $image = $movie->medium_image_url."<br/>";
    $des = $movie->description."<br/>";
    $city = $movie->city;
}