Question

我有一个像这样的字符串变量：'1111/222/333'或'1111/222/333/444'

我希望得到一个像这样的数组：

111-222-3333
111-222-
111-

OR

1111-222-333-444
1111-222-333-
1111-222-
1111-

我尝试了$pieces = explode("/", $str);

和

$str = '1111/222/333/444';
$pieces = explode("/", $str);
for($i=0; $i<count($pieces); $i++) {

    $var .= $pieces[$i]."-".$pieces[$i+1];
    echo $i." - ".$var."<br>";  

}

但我没有得到正确的结果！

任何帮助？

Answer 1

$str = '1111/222/333/444' ;
$pieces = explode("/", $str);
$num = count($pieces);
for($i=0;$i<$num;$i++) {
        print implode('-',$pieces).($i?'-':'')."\n";
        array_pop($pieces);
}

See it work

Answer 2

这个怎么样：

$str = '1111/222/333/444';
$pieces = explode("/", $str);
$newArray = array();
$s = '';
foreach ($pieces as $piece)
{
    $s .= $piece.'-'
    $newArray[] = $s;
}
rsort($newArray);

Answer 3

我的第一次尝试是：

$str = '1111/222/333/444';
$pieces = explode("/", $str);
$countPieces = count($pieces);
echo $countPieces;
while ($countPieces > 0) {
    $var = $pieces[0];
        for($i = 1; $i < $countPieces; $i++) {
            $var =  $var . "-" . $pieces[$i];
        }
    echo $var . "\n";  
    $countPieces--;
}

PHP递减循环

3 个答案: