Question

我需要使用用户提供的值更新xml节点;但我似乎无法修改simplexml对象。任何想法？

xml结构：

<xm>
   <unit>
        <building></building>
   </unit>
   <unit>
        <building></building>
   </unit>
   <unit>
        <building></building>
   </unit>
   <unit>
        <building></building>
   </unit>
</xm>

我试图这样做：

$original_xml = @simplexml_load_file("../test.xml");
$original_xml[$_POST['row_id']-1]->building = $_POST['building_txt'];

Answer 1

做这样的事情：

$units = @simplexml_load_file("../test.xml");
$i = 1;
foreach($units->unit as $unit)
{
    if($i == $_POST['row_id'])
    {
        $unit->building = $_POST['building_txt'];
    }
    $i++;
}

echo $units->asXML();

Answer 2

以下工作（您需要引用unit结构来指示您要检索的行：

$xml = simplexml_load_string('<xm>
   <unit>
        <building></building>
   </unit>
   <unit>
        <building></building>
   </unit>
   <unit>
        <building></building>
   </unit>
   <unit>
        <building></building>
   </unit>
</xm>');

$row = $_POST['row_id'] - 1;
$xml->unit[$row]->building = 'Test';

var_dump($xml->asXML());

如何修改php simplexml中的元素？

2 个答案: