Question

我不知道对于我的问题addChild和removeChild方法是我真正需要的，但是当我在网上阅读时，我需要使用的技术。

这是我的Xml文件：

<projects>
   <category name = "Branding">
      <project>Logo e effekt Medias1</project>
      <project>Portali Logo1</project>
      <project>Skena  Logo1</project>
   </category>
   <category name = "Web">
      <project>Logo e effekt Medias2</project>
      <project>Portali Logo2</project>
      <project>Skena  Logo2</project>
   </category>
   <category name = "Print">
      <project>Logo e effekt Medias3</project>
      <project>Portali Logo3</project>
      <project>Skena  Logo3</project>
   </category>

从这个XML文件首先我要从类别的name属性创建一个Menu，并使用for循环创建此菜单，它看起来像这样：

品牌卷筒纸打印

之后，当我点击时，让我说品牌我创建另一个动画片段和该动画片段显示品牌下的所有项目。到这里一切都还好。

单击其他菜单时出现问题。假设我点击了Web，此时所有来自Branding的项目都会停留在舞台上，加上舞台上的所有网络显示项目。这种方式我一直点击菜单上出现的新数据。

这是最好的技术，当我点击菜单时，只有与该类别相关的数据才会出现在舞台上。

如果你想检查我的混乱，你可以在这里找到链接：LINK

Answer 1

嗯，这不是关于添加或删除孩子的。真正的问题是关于你的发展前景。

首先，你正在构建一个菜单，所以让菜单就是这样，一个发送信号的对象，告知点击了哪个按钮。

之后，您需要某种形式的容器，在收到菜单消息时会显示相关屏幕。

这个容器可以包含三个屏幕，Branding，Web＆amp;打印。

您可以将所有此屏幕的可见属性设置为false。

当容器收到菜单信息时，它会将所选屏幕的visible属性设置为true，其他屏幕设置为false。

这样，您不必继续添加或删除子项，尝试跟踪您的DisplayList结构。

使用事件调度作为菜单。

无论如何，这是一个粗略的例子，它不完整，但应该给你一个想法......

public class Menu extends Sprite 
{
    //A basic button instance
    private var button:Sprite = new Sprite();

    //The dispatcher dispatches & listen to events
    //it acts as a connector between your container 
    //and the menu
    private var dispatcher:EventDispatcher;

    //The menu will be created in the Container
    //the dispatcher will be passed as a parameter
    //this is the connection between the two classes
    //Please note that there are other ways to achieve
    //a similar result..
    public function Menu (dispatcher:EventDispatcher) 
    {
        //assign the dispatcher instantiated in the container
        //to a variable in order to manipulate it in this class
        this.dispatcher = dispatcher;

        //takes care of creating the menu
        createMenu();
    }

    private function clickHandler( event:MouseEvent):void
    {
        //each time a button is click an event is dispatched
        //that contains the name of the clicked button
        dispatcher.dispatchEvent
                ( new MenuEvent(event.currentTarget.name));
    }

    private function createMenu():void
    {
       //here you load the XML, create the buttons
       // and add the event listeners

       //this is just an example for the logic
       //it's irrelevant since the button will 
       //be created from the XML
        button.name = "Branding";
            addChild( button );
            button.addEventListener
                ( MouseEvent.CLICK , clickHandler );
    }
}


public class Container extends Sprite 
{
   private var button:Sprite = new Sprite();

   //Here we instantiate a dispatcher
   private var dispatcher:EventDispatcher = new EventDispatcher;
   private var menu:Menu;

   //a basic screen instance that could contain
   //all that has to do with Branding for instance
   private var screen1:Sprite = new Sprite();
   //etc...

   public function Container () 
   {
        //The dispatcher is set to listen to the events 
        //dispatched in the Menu class
        dispatcher.addEventListener( MenuEvent.MENU , eventListener );
        screen1.visible = false;

        //now the menu can be created
        menu = new Menu( dispatcher);
        addChild( menu );
   }

   private function eventListener( event:MenuEvent):void
   {
        //set all the screens visibility to false
        //here...

        //get the event name and react accordingly
        //here you can implement a switch

       switch(event.name)
       {
            case "Branding":
            //show Branding screen
            screen1.visible = true;
            break;

            //etc...

       }                                
   }
}

public class MenuEvent extends Event
{
    public const MENU:String = "Menu Event";
    public var name:String;

    //Check custom events for the rest of the code...
    //Do a Google search for custom events 
    //shouldn't be too difficult to find
}

Actionscript3.0 addChild removeChild XML

1 个答案: