Question

我不能添加零值而不是null，这是我的sql：

 SELECT
                        S.STOCK_ID,
                        S.PRODUCT_NAME,
                        SUM(COALESCE(AMOUNT,0)) AMOUNT,
                        DATEPART(MM,INVOICE_DATE) AY
                    FROM
                        #DSN3_ALIAS#.STOCKS S
                            LEFT OUTER JOIN DAILY_PRODUCT_SALES DPS ON S.STOCK_ID = DPS.PRODUCT_ID
                    WHERE
                        MONTH(INVOICE_DATE) >= #attributes.startdate# AND 
                        MONTH(INVOICE_DATE) < #attributes.finishdate+1#
                    GROUP BY
                        DATEPART(MM,INVOICE_DATE),
                        S.STOCK_ID,
                        S.PRODUCT_NAME
                    ORDER BY
                        S.PRODUCT_NAME

和我的表：

<cfoutput query="get_sales_total" group="stock_id">
                            <tr height="20" class="color-row">
                                <td>#product_name#</td>
                                <cfoutput group="ay"><td><cfif len(amount)>#amount#<cfelse>0</cfif></td></cfoutput>
                            </tr>
                        </cfoutput>

我想要的结果： enter image description here

我得到的结果是： enter image description here

谢谢大家的帮助！

+编辑：

我使用了交叉连接技术，重写了sql：

SELECT
                        SUM(COALESCE(AMOUNT,0)) AMOUNT,S.STOCK_ID,S.PRODUCT_NAME,DPS.AY
                    FROM
                        #DSN3_ALIAS#.STOCKS S
                            CROSS JOIN (SELECT DISTINCT <cfif attributes.time_type eq 2>DATEPART(MM,INVOICE_DATE) AY<cfelse>DATEPART(DD,INVOICE_DATE) AY</cfif> 
                            FROM DAILY_PRODUCT_SALES) DPS
                            LEFT OUTER JOIN DAILY_PRODUCT_SALES DP ON S.STOCK_ID = DP.PRODUCT_ID AND 
                            <cfif attributes.time_type eq 2>DATEPART(MM,DP.INVOICE_DATE)<cfelse>DATEPART(DD,DP.INVOICE_DATE)</cfif> = DPS.AY
                    WHERE
                    <cfif attributes.time_type eq 2>
                        MONTH(INVOICE_DATE) >= #attributes.startdate# AND 
                        MONTH(INVOICE_DATE) < #attributes.finishdate+1#
                    <cfelse>
                        MONTH(INVOICE_DATE) = #attributes.startdate#
                    </cfif>
                    <cfif len(trim(attributes.product_cat)) and len(attributes.product_code)>
                        AND S.STOCK_CODE LIKE '#attributes.product_code#%'
                    </cfif>
                    GROUP BY DPS.AY,S.STOCK_ID,S.PRODUCT_NAME
                    ORDER BY DPS.AY,S.STOCK_ID,S.PRODUCT_NAME

结果是： enter image description here

Answer 1

改用CASE

SUM（如果A为空，则为0，结束时为

）

Answer 2

您可以像Lasse建议的那样在数据库中执行此操作，或者您可以将每个输出值包装在Val函数中，如下所示：

<cfoutput group="ay"><td>#Val(amount)#</td></cfoutput>

Val函数会将任何非数字值转换为0.

Answer 3

您可以使用ISNULL，即;

 SUM(ISNULL(AMOUNT,0)) AMOUNT,

编辑：好的，鉴于问题似乎是缺少值而不是空值。试试这样的事情。

首先，创建一个永久的reporting_framework表。这个基于几个月和几年，但如果你愿意，你可以把它延长到几天。



create table reporting_framework
([month] smallint, [year] smallint);
go

declare @year smallint;
declare @month smallint;

set @year=2000;
while @year<2500 
begin
  set @month=1;
  while @month<13
  begin
    insert into reporting_framework ([month], [year]) values (@month, @year);
    set @month=@month+1;
  end
  set @year=@year+1;
end

select * from reporting_framework;

create table reporting_framework ([month] smallint, [year] smallint); go declare @year smallint; declare @month smallint; set @year=2000; while @year<2500 begin set @month=1; while @month<13 begin insert into reporting_framework ([month], [year]) values (@month, @year); set @month=@month+1; end set @year=@year+1; end select * from reporting_framework; （这给你6000行，从2000到2499 - 根据口味调整！）

现在我们将制作零件表和订单表

现在这是您查询的表格，例如;

create table parts
([part_num] integer, [description] varchar(100));
go

insert into parts (part_num, [description]) values (100, 'Widget');
insert into parts (part_num, [description]) values (101, 'Sprocket');
insert into parts (part_num, [description]) values (102, 'Gizmo');
insert into parts (part_num, [description]) values (103, 'Foobar');

create table orders
([id] integer, part_num integer, cost numeric(10,2), orderdate datetime);
go

insert into orders ([id], part_num, cost, orderdate) values
(1, 100, 49.99, '2011-10-30');
insert into orders ([id], part_num, cost, orderdate) values
(2, 101, 109.99, '2011-10-31');
insert into orders ([id], part_num, cost, orderdate) values
(3, 100, 47.99, '2011-10-31');
insert into orders ([id], part_num, cost, orderdate) values
(4, 102, 429.99, '2011-11-01');
insert into orders ([id], part_num, cost, orderdate) values
(5, 101, 111.17, '2011-11-01');
insert into orders ([id], part_num, cost, orderdate) values
(6, 101, 111.17, '2011-11-01');
insert into orders ([id], part_num, cost, orderdate) values
(7, 103, 21.00, '2011-09-15');

这个例子有帮助吗？可能有很多更好的方法（hello StackOverflow），但它可能会让你开始思考你的问题是什么。不是CROSS JOIN获取所有零件/日期组合，然后是FULL OUTER JOIN以获得订单。 'where'子句只是控制你的日期范围。

总和COALESCE 0而不是null

3 个答案: