Question

我想从下面的文本中创建javascript的regexp匹配字符串数组。

.root
 this is root
..child 1
 this is child 1
 this is also child 1's content.
...child 1-1
 this is child 1-1

..child 2
 this is child 2
...child 2-1
 this is child 2-1
.root 2
 this is root 2

，所需的数组在

之下

array[0] = ".root
 this is root"

array[1] = "..child 1
 this is child 1
 this is also child 1's content"

array[2] = "...child 1-1
 this is child 1-1
"

array[3] = "..child 2
 this is child 2"

array[4] = "...child 2-1
 this is child 2-1"

array[5] = ".root 2
 this is root 2"

在Java中，我可以像^\..*?(?=(^\.|\Z))那样，但在Javascript中没有\Z，.与换行符不匹配，$匹配换行符（不只是字符串的结尾。）

如何实现此阵列？
我使用这个站点（http://www.gethifi.com/tools/regex）来测试regexp。

Answer 1

text.split(/\r?\n^(?=\.)/gm)生成相同的数组。

text.match(/^\..*(\r?\n[^.].*)*/gm)丑陋，但仍然。

Answer 2

这是一个正则表达式：

var re = /^[.][\s\S]*?(?:(?=\r?\n[.])|(?![\s\S]))/gm
var match
var matches = []
while (match = re.exec(text)) {
  matches.push(match[0])
}
console.log(matches)

输出：

[
  ".root\nthis is root",
  "..child 1\n this is child 1\n this is also child 1's content.",
  "...child 1-1\n this is child 1-1\n",
  "..child 2\n this is child 2",
  "...child 2-1\n this is child 2-1",
  ".root 2\n this is root 2"
]

一些有用的技巧：

使用[\s\S]来匹配任何字符
use (?![\s\S]) to simulate \Z

创建正则表达式匹配数组（多行，javascript）

2 个答案: