Question

是否存在将unix时间戳转换为此格式的PHP库：

8 hours and 17 minutes ago

我做了我自己的剧本，这样做了，我无法追踪它，宁愿不花时间重新创建它（加上我认为它可以更有效地完成）。

我原来的代码是：

$seconds = time() - $timestamp;

$minutes = 0;
$hours = 0;
$days = 0;
$weeks = 0;
$months = 0;
$years = 0;

while($seconds >= 60)
{
    $seconds -= 60;
    $minutes ++;

    if($minutes >= 60)
    {
        $minutes -= 60;
        $hours ++;

        if($hours >= 24)
        {
            // etc
        }
    }
}

if($hours < 1) return "$minutes minute" . ($minutes == 1 ? "" : "s")) . " and $seconds seconds" . ($seconds == 1 ? "" : "s"));
if($minutes < 1) return "$seconds second" . ($seconds == 1 ? "" : "s"));

// etc

更好的是，如果有更好的方法来解决上述问题，我也会自己解决这个问题。

Answer 1

是的，请检查The DateTime class。

$datetime1= new DateTime();
$datetime2= new DateTime();
$datetime2->setTimestamp($timestamp);

$interval = $datetime2->diff($datetime1);
echo $interval->format('%a days %h hours and %i minutes ago');

Answer 2

/*
  Input parameter is the UNIX timestamp 
  of the starting date.
  The second parameter is optional -
  It's value is the ending date,
  also UNIX timestamp. If this
  parameter is not given, the 
  default date is current date.
*/
function duration($start,$end=null) {
 $end = is_null($end) ? time() : $end;

 $seconds = $end - $start;

 $days = floor($seconds/60/60/24);
 $hours = $seconds/60/60%24;
 $mins = $seconds/60%60;
 $secs = $seconds%60;

 $duration='';
 if($days>0) $duration .= "$days days ";
 if($hours>0) $duration .= "$hours hours ";
 if($mins>0) $duration .= "$mins minutes ";
 if($secs>0) $duration .= "$secs seconds ";

 //$duration = trim($duration);
 if($duration=='') $duration = '0 seconds';

 return $duration;
}

它不适合你更好地使用一些类，如下所示

http://www.phpclasses.org/browse/file/6330.html

Answer 3

function TimeAgo($datefrom,$dateto=-1)
{
// Defaults and assume if 0 is passed in that
// its an error rather than the epoch

if($datefrom<=0) { return "A long time ago"; }
if($dateto==-1) { $dateto = time(); }

// Calculate the difference in seconds betweeen
// the two timestamps

$difference = $dateto - $datefrom;

// If difference is less than 60 seconds,
// seconds is a good interval of choice

if($difference < 60)
{
$interval = "s";
}

// If difference is between 60 seconds and
// 60 minutes, minutes is a good interval
elseif($difference >= 60 && $difference<60*60)
{
$interval = "n";
}

// If difference is between 1 hour and 24 hours
// hours is a good interval
elseif($difference >= 60*60 && $difference<60*60*24)
{
$interval = "h";
}

// If difference is between 1 day and 7 days
// days is a good interval
elseif($difference >= 60*60*24 && $difference<60*60*24*7)
{
$interval = "d";
}

// If difference is between 1 week and 30 days
// weeks is a good interval
elseif($difference >= 60*60*24*7 && $difference <
60*60*24*30)
{
$interval = "ww";
}

// If difference is between 30 days and 365 days
// months is a good interval, again, the same thing
// applies, if the 29th February happens to exist
// between your 2 dates, the function will return
// the 'incorrect' value for a day
elseif($difference >= 60*60*24*30 && $difference <
60*60*24*365)
{
$interval = "m";
}

// If difference is greater than or equal to 365
// days, return year. This will be incorrect if
// for example, you call the function on the 28th April
// 2008 passing in 29th April 2007. It will return
// 1 year ago when in actual fact (yawn!) not quite
// a year has gone by
elseif($difference >= 60*60*24*365)
{
$interval = "y";
}

// Based on the interval, determine the
// number of units between the two dates
// From this point on, you would be hard
// pushed telling the difference between
// this function and DateDiff. If the $datediff
// returned is 1, be sure to return the singular
// of the unit, e.g. 'day' rather 'days'

switch($interval)
{
case "m":
$months_difference = floor($difference / 60 / 60 / 24 /
29);
while (mktime(date("H", $datefrom), date("i", $datefrom),
date("s", $datefrom), date("n", $datefrom)+($months_difference),
date("j", $dateto), date("Y", $datefrom)) < $dateto)
{
$months_difference++;
}
$datediff = $months_difference;

// We need this in here because it is possible
// to have an 'm' interval and a months
// difference of 12 because we are using 29 days
// in a month

if($datediff==12)
{
$datediff--;
}

$res = ($datediff==1) ? "$datediff month ago" : "$datediff
months ago";
break;

case "y":
$datediff = floor($difference / 60 / 60 / 24 / 365);
$res = ($datediff==1) ? "$datediff year ago" : "$datediff
years ago";
break;

case "d":
$datediff = floor($difference / 60 / 60 / 24);
$res = ($datediff==1) ? "$datediff day ago" : "$datediff
days ago";
break;

case "ww":
$datediff = floor($difference / 60 / 60 / 24 / 7);
$res = ($datediff==1) ? "$datediff week ago" : "$datediff
weeks ago";
break;

case "h":
$datediff = floor($difference / 60 / 60);
$res = ($datediff==1) ? "$datediff hour ago" : "$datediff
hours ago";
break;

case "n":
$datediff = floor($difference / 60);
$res = ($datediff==1) ? "$datediff minute ago" :
"$datediff minutes ago";
break;

case "s":
$datediff = $difference;
$res = ($datediff==1) ? "$datediff second ago" :
"$datediff seconds ago";
break;
}
return $res;
}

PHP时间转换

3 个答案: