我正在尝试使用下面的CSV绘制图表:
2.364258,3.005366
2.723633,3.009784
3.083008,3.012145
3.442383,3.012705
3.801758,3.010412
4.160156,3.010703
4.518555,3.011985
4.876953,3.012547
5.235352,3.009941
5.592773,3.011252
5.951172,3.010596
6.30957,3.011951
6.667969,3.010613
7.026367,3.008634
7.384766,3.009744
7.743164,3.01062
8.101563,3.00942
8.459961,3.009438
8.818359,3.009478
9.177734,3.010827
到目前为止我所做的是我试图让一个班级做到这一点!这是我尝试绘制曲线的部分:
class Plotter
{
#region Fields and variables
private Bitmap plot;
private Graphics g;
public string PlotType {get; set;}
private int iWidth; //Width of the box
private int iHeight; //
private float xMax; //maximum range on X axis
private float yMax; //maximum range on Y axis
private PointF[] points;
#endregion
#region Constructors
/// <summary>
/// Constructor of class
/// </summary>
/// <param name="iWidth">Width of image in pixels</param>
/// <param name="iHeight">Height of image in pixels</param>
/// <param name="xMax">Maximum value of the values on X</param>
/// <param name="yMax">Maximum value of the values on Y</param>
/// <param name="pairs">Pairs of data in an array of PointF[] this is raw data!!</param>
public Plotter(int iWidth, int iHeight, float xMax, float yMax, PointF[] points)
{
this.iWidth = iWidth;
this.iHeight = iHeight;
this.xMax = xMax;
this.yMax = yMax;
this.points = points;
plot = new Bitmap(iWidth, iHeight);
}
public Bitmap DrawPlot()
{
Pen blackPen = new Pen(Color.Black, 1);
g = Graphics.FromImage(plot);
PointF[] p = new PointF[points.GetLength(0)];
//Try to scale input data to pixel coordinates
foreach (PointF point in points)
{
int i = 0;
p[i].X = point.X * iWidth;
p[1].X = point.Y * iHeight;
}
g.DrawCurve(blackPen, p, 0);
return plot;
}
我最后得到的是一条直线!我认为已经在X {0,0}和Y {0,0}上绘制了X {0,400}和Y {0,0}
你能帮我纠正错误吗?P.S:http://itools.subhashbose.com/grapher/index.php这个网站可以从我拥有的CSV数据中绘制出我需要相当不错的情节(如果你需要检查)。
谢谢!
答案 0 :(得分:3)
这似乎是你的问题:
foreach (PointF point in points)
{
int i = 0;
p[i].X = point.X * iWidth;
p[1].X = point.Y * iHeight;
}
i
始终为零,您永远不会分配Y
。 “第二个”赋值甚至不使用i
,而是使用1个索引。
无需错误检查即可快速修复:
int i = 0;
foreach (PointF point in points)
{
p[i].X = point.X * iWidth;
p[i].Y = point.Y * iHeight;
i++;
}
答案 1 :(得分:1)
你两次分配x。
p[i].X = point.X * iWidth;
p[1].X = point.Y * iHeight;
正如@LarsTech指出你需要修理计数器