Question

嗨我无法从我的二进制文件中特定记录。这是列出所有记录的方法。

int student :: showall(fstream &fp)
{
    student rec;
    fp.seekg(0,ios::beg);
    int i=0;
    cout<<"Position\tRoll No\t\tName\tBalance"<<endl;
    while(fp.read((char*)&rec,sizeof rec))
    {   
        cout<<i*sizeof rec<<"\t";
        rec.show();
        i++;
    }
}

在运行时，我得到了以下输出

 Position Roll No     Name    Balance 0       1
 Heartly  10 28       2       
 Heartly  20 56       3       
 Heartly  30 84       4       
 Heartly  40 112      5
 Heartly  50 140      6       
 Heartly  60 168      7       
 Heartly  70 196      8
 Heartly  80 224      9       
 Heartly  90 252      10      
 Heartly  100

现在我想搜索特定记录。我给了RecNo 5进行搜索。这是我的View方法

int student :: view(fstream &fp,int RecNum)
{
    student rec;
    std::ios::pos_type SearchPosition = RecNum*sizeof rec;
    cout<<endl<<"Position="<<SearchPosition<<endl;
    if( fp.seekg(SearchPosition) == 0 )
    {
        cout<<endl<<"Position="<<SearchPosition<<endl;
            if(fp.read((char*)&rec,sizeof rec))
                    rec.show();
        else
            cout<<endl<<"Read Error .. ! "<<endl;
        }
    else
    {
        cout<<endl<<"Record Number Not Found"<<endl;
    }   
}

运行此方法后，我得到了以下结果。

记录编号（-1取消）：5

位置= 140

未找到记录号

为什么找不到特定的记录？

printf("\nMenu : AddDummy, Add, View, Edit, List or Quit ( U, A, V, E, L or Q) : ");  switch(toupper(getchar()))  {     
     case 'U' :
        file.open("abc.cli",ios::in|ios::out|ios::binary|ios::app);
            cout<<"Creating dummy file of 1000 entries"<<endl;
            record.adddummy(file);
        file.clear();
            break;
    case 'A' :
        file.open("abc.cli",ios::in|ios::out|ios::binary|ios::app);
            record.get();
        record.add(record,file);
            cout<<"Record Added"<<endl;         
            file.clear();
            break;              
    case 'E' :      
            file.open("abc.cli",ios::in|ios::out|ios::binary|ios::ate);
            cout<<endl<<"Record number (-1 Cancels): "<<endl;
            cin>>Rec;
            if (Rec > -1){
                record.get();
         if(!record.update(record,file,Rec))
            cout<<"Record Edited"<<endl;            
             else
            cout<<"Record Edited Failed"<<endl;     
        file.clear();}
             break;
    case 'V' :      
             file.open("abc.cli",ios::in|ios::out|ios::binary|ios::ate);
             cout<<endl<<"Record number (-1 Cancels): "<<endl;
             cin>>Rec;
             if (Rec > -1)
                record.view(file,Rec);
         file.clear();
             break;
    case 'L' :
         file.open("abc.cli",ios::in|ios::out|ios::binary|ios::ate);
             record.showall(file); 
         file.clear();
             break; 
    case 'Q' :
            file.close();
        return 0;   
    default :
        cout<<" \nNot Matching\n ";     
}while(getchar() != '\n');

为什么不读取特定的记录？在这里输入代码

Answer 1

fstream::seekg返回一个fstream引用，永远不会等于0.所以你检查的条件永远不会运行。 fstream::seekg

c ++中的随机访问文件

1 个答案: