我有rjecnik.txt文件,看起来像这样
mate sime, jure
stipica gujo, prvi
ante mirkec
goran maja, majica
avion kuca, brod, seoce
amerika, neka, zemlja, krcma
brodarica, zgrada, zagreb
zagreb split
zadar rijeka
andaluzija azija
我需要按字母顺序排序行(而不是单词),我的程序产生的结果不正确:
andaluzija azijamate sime, jure
amerika, neka, zemlja, krcma
brodarica, zgrada, zagreb
ante mirkec
avion kuca, brod, seoce
goran maja, majica
stipica gujo, prvi
zadar rijeka
zagreb split
按[Enter]关闭终端... 当我使用像kuća这样的非ascii字符用于kuca或krčma用于krcma它会产生这个结果(都错了)
andaluzija azijamate sime, jure
amerika, neka, zemlja, krŔma
brodarica, zgrada, zagreb
ante mirkec
avion kuŠa, brod, seoce
goran maja, majica
stipica gujo, prvi
zadar rijeka
zagreb split
按[Enter]关闭终端... 这是我的代码:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{
int ch, nl = 1, min, lenght1, lenght2, lenght;//ch will hold characters, min is for selection sort, lenght holds value of strlen for determine wthat line is longer
FILE * fp;// FILE pointer
char * lines[1000];//that will dynamically hold strings for lines
char * temp;//for lines swaping
if((fp = fopen("C:\\Users\\don\\Documents\\NetBeansProjects\\proba2\\dist\\Debug\\MinGW-Windows\\rjecnik.txt", "r")) == NULL)//I had to temporarily put full path to rjecnik.txt
{
printf("Can't open file...");
exit(1);
}
while((ch = getc(fp)) != EOF)//count lines
{
if(ch == '\n')
nl++;
}
int i, j;
for (i = 0; i < nl; i++)
lines[i] = malloc(1000);//create array of string size value of nl
fseek(fp, 0L, SEEK_SET);//go to start of file
i = 0;
j = 0;
while((ch = getc(fp)) != EOF)//fill arrays of string
{
lines[i][j] = ch;
j++;
if(ch == '\n')
{
j = 0;
i++;
}
}
for(i = 0; i < nl - 1; i++)//selection sort doesn't work properly
{
min = i;//min is i
for(j = i + 1; j < nl; j++)//for number of lines(nl) times
{
lenght1 = strlen(lines[i]);//find what string is longer and lenght is smaller one
lenght2 = strlen(lines[j]);
if(lenght1 < lenght2)
lenght = lenght1;
else
lenght = lenght2;
if(strncmp(lines[i], lines[j], lenght) > 0 )//compare two strings
min = j;//if second string is alphabetically smaller min is j
}
temp = lines[i];// swapping
lines[i] = lines[min];
lines[min] = temp;
}
for(i = 0; i < nl; i++ )//printing to console
{
lenght1 = strlen(lines[i]);
for(j = 0; j < lenght1; j++ )
{
putchar(lines[i][j]);
}
}
return 0;
}
现在程序在我添加此代码时崩溃了:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{
int ch, nl = 1, min, lenght1, lenght2, lenght;//ch will hold characters, min is for selection sort, lenght holds value of strlen for determine wthat line is longer
FILE * fp;// FILE pointer
char * lines[1000];//that will dynamically hold strings for lines
char * temp;//for lines swaping
if((fp = fopen("C:\\Users\\don\\Documents\\NetBeansProjects\\proba2\\dist\\Debug\\MinGW-Windows\\rjecnik.txt", "r")) == NULL)//I had to temporarily put full path to rjecnik.txt
{
printf("Can't open file...");
exit(1);
}
while((ch = getc(fp)) != EOF)//count lines
{
if(ch == '\n')
nl++;
}
int i, j;
for (i = 0; i < nl; i++)
lines[i] = malloc(1000);//create array of string size value of nl
fseek(fp, 0L, SEEK_SET);//go to start of file
i = 0;
j = 0;
while((ch = getc(fp)) != EOF)//fill arrays of string
{
lines[i][j] = ch;
j++;
if(ch == '\n')
{
j = 0;
i++;
}
}
for(i = 0; i < nl - 1; i++)//selection sort doesn't work properly
{
min = i;//min is i
for(j = i + 1; j < nl; j++)//for number of lines(nl) times
{
lenght1 = strlen(lines[i]);//find what string is longer and lenght is smaller one
lenght2 = strlen(lines[j]);
if(lenght1 < lenght2)
lenght = lenght1;
else
lenght = lenght2;
if(strncmp(lines[min], lines[j], lenght ) > 0 )//compare two strings
min = j;//if second string is alphabetically smaller min is j
}
temp = lines[i];// swapping
lines[i] = lines[min];
lines[min] = temp;
}
for(i = 0; i < nl; i++ )//printing to console
{
lenght1 = strlen(lines[i]);
for(j = 0; j < lenght1; j++ )
{
putchar(lines[i][j]);
}
}
for (i = 0; i < 100; i++)//Program crashes here
free(lines[i]);
return 0;
}
答案 0 :(得分:2)
你总是将行[j]与行[i]进行比较,但你应该将它与行[min]进行比较。
答案 1 :(得分:2)
1.-您必须在malloc之后将行初始化为0,以便strlen正常工作。 2.-将线[j]与线[min]进行比较 3.-不要忘记免费线路
答案 2 :(得分:1)
如果你不是在学习如何排序和获取输入,那么c提供了qsort()
和fgets()
,所以你可以
int strsort(const void *a, const void *b)
{
char *const*astr=a, *const*bstr=b;
return strcmp(*astr, *bstr);
}
main()
{
FILE*f = fopen(...);
char (*arr)[1000] = malloc(1000*1000);
int x;
for(x=0;x<1000 && fgets(1000, arr[x], f);x++)
arr[x][strlen(arr[x])-2] = '\0'; //strip newlines
qsort(arr, x, 1, strsort);
int i;
for(i=0; i<x; i++)
printf("%s\n", arr[x]);
}
你用这种方式做得更清楚。
答案 3 :(得分:0)
轻微的挑剔:
lenght1 = strlen(lines[i]);
lenght2 = strlen(lines[j]);
if(lenght1 < lenght2)
lenght = lenght1;
else
lenght = lenght2;
if(strncmp(lines[i], lines[j], lenght) > 0 )
... ;
你不需要这样:strcmp()在任何一个字符串终止时停止,以先到者为准。在您的情况下,您需要比较另一个字符(NUL),如
strncmp( lines[i], lines[j], lenght+1)
,否则“apple”和“apples”将相等(因为只会比较前五个字符)。但是“正常”形式:
strcmp(lines[i], lines[j])
完全符合您的要求。