我正在使用以下代码来获取维基百科文章中的第一段。这是result of my code。我只需要这一段。可能吗?还是有更好的选择吗?
'''Papori'''({{lang-as |'''?????''}})是一种[[阿萨姆语]]功能 由[[Jahnu Barua]]执导的电影。电影明星Gopi Desai,[[Biju Phukan]], Sushil Goswami,Chetana Das和Dulal Roy。这部电影于1986年上映。
这是我的代码:
#!/usr/bin/python
from lxml import etree
import urllib
from BeautifulSoup import BeautifulSoup
class AppURLopener(urllib.FancyURLopener):
version = "WikiDownloader"
urllib._urlopener = AppURLopener()
query = 'http://en.wikipedia.org/w/api.php?action=query&prop=revisions&rvprop=content&format=xml&titles=papori&rvsection=0'
#data = { 'catname':'', 'wpDownload':1, 'pages':"\n".join(pages)}
#data = urllib.urlencode(data)
f = urllib.urlopen(query)
s = f.read()
#doc = etree.parse(f)
#print(s)
soup = BeautifulSoup(s)
secondPTag = soup.findAll('rev')
print secondPTag
代码已更新:任何人都可以帮我删除{{ }}
之间的文字。因为没有必要。感谢
答案 0 :(得分:1)
要删除从{{
到'''Papori'''
的所有内容:
import re
regex = re.compile(r"""{{.*?}}\s*('''Papori''')""", re.DOTALL)
print regex.sub(r"\1", rev_data)
要删除从第一个“{{”到匹配“}}”的所有内容:
prefix, sep, rest = rev_data.partition("{{")
if sep: # found the first "{{"
rest = sep + rest # put it back
while rest.startswith("{{"):
# remove nested "{{expr}}" one by one until there is none
rest, n = re.subn(r"{{(?:[^{]|(?<!{){)*?}}", "", rest, 1)
if n == 0:
break # the first "{{" is unmatched; can't remove it
else: # deletion is successful
rev_data = prefix + rest
print(rev_data)
要删除从第一个“{{”到匹配“}}”的所有内容,而不使用正则表达式:
prefix, sep, rest = rev_data.partition("{{")
if sep: # found the first "{{"
depth = 1
prevc = None
for i, c in enumerate(rest):
if c == "{" and prevc == c: # found "{{"
depth += 1
prevc = None # match "{{{ " only once
elif c == "}" and prevc == c: # found "}}"
depth -= 1
if depth == 0: # found matching "}}"
rev_data = prefix + rest[i+1:] # after matching "}}"
break
prevc = None # match "}}} " only once
else:
prevc = c
print(rev_data)
#!/usr/bin/env python
import urllib, urllib2
import xml.etree.cElementTree as etree
# download & parse xml, find rev data
params = dict(action="query", prop="revisions", rvprop="content",
format="xml", titles="papori", rvsection=0)
request = urllib2.Request(
"http://en.wikipedia.org/w/api.php?" + urllib.urlencode(params),
headers={"User-Agent": "WikiDownloader/1.0",
"Referer": "http://stackoverflow.com/q/7937855"})
tree = etree.parse(urllib2.urlopen(request))
rev_data = tree.findtext('.//rev')
# remove everything from the first "{{" to matching "}}"
prefix, sep, rest = rev_data.partition("{{")
if sep: # found the first "{{"
depth = 1
prevc = None
for i, c in enumerate(rest):
if c == "{" and prevc == c: # found "{{"
depth += 1
prevc = None # match "{{{ " only once
elif c == "}" and prevc == c: # found "}}"
depth -= 1
if depth == 0: # found matching "}}"
rev_data = prefix + rest[i+1:] # after matching "}}"
break
prevc = None # match "}}} " only once
else:
prevc = c
print rev_data
'''Papori''' ({{lang-as|'''পাপৰী'''}}) is an [[Assamese
language]] feature film directed by [[Jahnu Barua]]. The film
stars Gopi Desai, [[Biju Phukan]], Sushil Goswami, Chetana Das
and Dulal Roy. The film was released in 1986.<ref name="ab">{{cite
web|url=http://www.chaosmag.in/barua.html|title=Papori – 1986 –
Assamese film|publisher=Chaosmag|accessdate=4 February
2010}}</ref>
答案 1 :(得分:0)
是的,有可能。您可以使用HTMLParser之类的HTML解析器,但我建议使用Beautiful Soup
使用正则表达式删除子字符串,如下所示:
>>> email = "tony@tiremove_thisger.net"
>>> m = re.search("remove_this", email)
>>> email[:m.start()] + email[m.end():]
'tony@tiger.net'