切换查询字符串变量

时间:2011-10-29 06:38:24

标签: javascript jquery query-string

我一直在抨击这个。

使用jquery或javascript,如何切换变量&值然后重建查询字符串?例如,我的起始网址为:

http://example.com?color=red&size=small,medium,large&shape=round

然后,如果用户点击标有“红色”的按钮,我想最终得到:

http://example.com?size=small,medium,large&shape=round //color is removed

然后,如果用户再次点击“红色”,我想最终得到:

http://example.com?size=small,medium,large&shape=round&color=red //color is added back

然后,如果用户点击标有“中等”的按钮,我想最终得到:

http://example.com?size=small,large&shape=round&color=red //medium is removed from list

然后,如果用户再次点击标有“媒介”,我想最终得到:

http://example.com?size=small,large,medium&shape=round&color=red //medium added back

变量的顺序并不重要;我刚刚把它们搞定到最后。

5 个答案:

答案 0 :(得分:8)

function toggle(url, key, val) {
    var out = [],
        upd = '',
        rm = "([&?])" + key + "=([^&]*?,)?" + val + "(,.*?)?(&.*?)?$",
        ad = key + "=",
        rmrplr = function(url, p1, p2, p3, p4) {
            if (p2) {
                if (p3) out.push(p1, key, '=', p2, p3.substr(1));
                else out.push(p1, key, '=', p2.substr(0, p2.length - 1));
            } else {
                if (p3) out.push(p1, key, '=', p3.substr(1));
                else out.push(p1);
            }
            if (p4) out.push(p4);
            return out.join('').replace(/([&?])&/, '$1').replace(/[&?]$/, ''); //<!2
        },
        adrplr = function(s) {
            return s + val + ',';
        };
    if ((upd = url.replace(new RegExp(rm), rmrplr)) != url) return upd;
    if ((upd = url.replace(new RegExp(ad), adrplr)) != url) return upd;
    return url + (/\?.+/.test(url) ? '&' : '?') + key + '=' + val; //<!1
}
params自我描述不够,希望对此有所帮助。

!1:从...? '&' : ''更改为... ? '&' : '?'

!2:从.replace('?&','?')...更改为.replace(/([&?]&)/,'$1')...

http://jsfiddle.net/ycw7788/Abxj8/

答案 1 :(得分:5)

我编写了一个函数,它可以有效地产生预期的行为,而不使用任何库或框架。可以在这个小提琴上找到动态演示:http://jsfiddle.net/w8D2G/1/

文档

<强>解释
显示的示例值将在下面的“使用”部分使用 - Haystack - 要搜索的字符串(默认=查询字符串。例如:?size=small,medium
- 针 - 搜索的关键。示例:size
- 值 - 要替换​​/添加的值。示例:medium

用法(示例:input > output):

  1. qs_replace(needle, value)
    如果存在值,请移除:?size=small,medium > ?size=small
    如果值不存在,请添加:?size=small > size=small,medium
  2. qs_replace(needle, options)对象选项。认可的选择:
    • find
      字符串。如果值存在,则返回true,否则返回false
    • add remove toggle
      字符串。在/ needle中添加/删除给定值。如果使用remove,并且该值是唯一值,则needle也会被删除。如果值已存在,则不会添加该值。
    • ignorecase
      在查找搜索字词时忽略大小写(needleaddremove或{{1} })。
    • find
      指定分隔符以分隔separator的值。默认为逗号(needle)。
  3. 注意:也可以通过将其添加为第一个参数来定义字符串,的不同值:haystackqs_replace(haystack, needle, value)

    代码(底部的例子)。 小提琴:http://jsfiddle.net/w8D2G/1/

    qs_replace(haystack, needle, options)

    示例(小提琴:http://jsfiddle.net/w8D2G/1/ ):

    function qs_replace(haystack, needle, options) {
        if(!haystack || !needle) return ""; // Without a haystack or needle.. Bye
        else if(typeof needle == "object") {
            options = needle;
            needle = haystack;
            haystack = location.search;
        } else if(typeof options == "undefined") {
            options = needle;
            needle = haystack;
            haystack = location.search;
        }
    
        if(typeof options == "string" && options != "") {
            options = {remove: options};
            var toggle = true;
        } else if(typeof options != "object" || options === null) {
            return haystack;
        } else {
            var toggle = !!options.toggle;
            if (toggle) {
                options.remove = options.toggle;
                options.toggle = void 0;
            }
        }
    
        var find = options.find,
            add = options.add,
            remove = options.remove || options.del, //declare remove
            sep = options.sep || options.separator || ",", //Commas, by default
    
            flags = (options.ignorecase ? "i" :"");
    
        needle = encodeURIComponent(needle); //URL-encoding
        var pattern = regexp_special_chars(needle);
        pattern = "([?&])(" + pattern + ")(=|&|$)([^&]*)(&|$)";
        pattern = new RegExp(pattern, flags);
        var subquery_match = haystack.match(pattern);
    
        var before = /\?/.test(haystack) ? "&" : "?"; //Use ? if not existent, otherwise &
        var re_sep = regexp_special_chars(sep);
    
        if (!add || find) { //add is not defined, or find is used
            var original_remove = remove;
            if (subquery_match) {
                remove = encodeURIComponent(remove);
                remove = regexp_special_chars(remove);
                remove = "(^|" + re_sep + ")(" + remove + ")(" + re_sep + "|$)";
                remove = new RegExp(remove, flags);
                var fail = subquery_match[4].match(remove);
            } else {
                var fail = false;
            }
            if (!add && !fail && toggle) add = original_remove;
        }
        if(find) return !!subquery_match || fail;
        if (add) { //add is a string, defined previously
            add = encodeURIComponent(add);
            if(subquery_match) {
                var re_add = regexp_special_chars(add);
                re_add = "(^|" + re_sep + ")(" + re_add + ")(?=" + re_sep + "|$)";
                re_add = new RegExp(re_add, flags);
                if (subquery_match && re_add.test(subquery_match[4])) {
                    return haystack;
                }
                if (subquery_match[3] != "=") {
                    subquery_match = "$1$2=" + add + "$4$5";
                } else {
                    subquery_match = "$1$2=$4" + sep + add + "$5";
                }
                return haystack.replace(pattern, subquery_match);
            } else {
                return haystack + before + needle + "=" + add;
            }
        } else if(subquery_match){ // Remove part. We can only remove if a needle exist
            if(subquery_match[3] != "="){
                return haystack;
            } else {
                return haystack.replace(pattern, function(match, prefix, key, separator, value, trailing_sep){
                    // The whole match, example: &foo=bar,doo
                    // will be replaced by the return value of this function
                    var newValue = value.replace(remove, function(m, pre, bye, post){
                        return pre == sep && post == sep ? sep : pre == "?" ? "?" : "";
                    });
                    if(newValue) { //If the value has any content
                        return prefix + key + separator + newValue + trailing_sep;
                    } else {
                        return prefix == "?" ? "?" : trailing_sep; //No value, also remove needle
                    }
                }); //End of haystack.replace
            } //End of else if
        } else {
            return haystack;
        }
    
        // Convert string to RegExp-safe string
        function regexp_special_chars(s){
            return s.replace(/([[^$.|?*+(){}\\])/g, '\\$1');
        }
    }
    

答案 2 :(得分:2)

这是您的任务的解决方案:http://jsfiddle.net/mikhailov/QpjZ3/12/

var url = 'http://example.com?size=small,medium,large&shape=round';
var params = $.deparam.querystring(url);
var paramsResult = {};

var click1 = { size: 'small' };
var click2 = { size: 'xlarge' };
var click3 = { shape: 'round' };
var click4 = { shape: 'square' };

var clickNow = click4;

for (i in params) {
    var clickKey = _.keys(clickNow)[0];
    var clickVal = _.values(clickNow)[0];

    if (i == clickKey) {
       var ar = params[i].split(',');

       if (_.include(ar, clickVal)) {
           var newAr = _.difference(ar, [clickVal]);
       } else {
           var newAr = ar;
           newAr.push(clickVal);
       }
       paramsResult[i] = newAr.join(',');
    } else {
       paramsResult[i] = params[i];
    }

}

alert($.param(paramsResult)) // results see below

Init params string

{ size="small, medium,large", shape="round"} // size=small,medium,large&shape=round

<强>结果

{ size="small"}   => { size="medium,large", shape="round"} //size=medium%2Clarge&shape=round

{ size="xlarge"}  => { size="small,medium,large,xlarge", shape="round"} // size=small%2Cmedium%2Clarge%2Cxlarge&shape=round

{ shape="round"}  => { size="small,medium,large", shape=""} //size=small%2Cmedium%2Clarge&shape=

{ shape="square"} => { size="small,medium,large", shape="round,square"} //size=small%2Cmedium%2Clarge&shape=round%2Csquare

答案 3 :(得分:2)

productOptions是您在此处需要修改的唯一内容,列出所有可用选项及其默认状态。您只需使用公共API函数toggleOption()来切换选项。

(function(){
    //Just keep an object with all the options with flags if they are enabled or disabled:

    var productOptions = {

        color: {
            "red": true,
            "blue": true,
            "green": false
        },

        size: {
            "small": true,
            "medium": true,
            "large": true
        },

        shape: {
            "round": true
        }
    };


    //After this constructing query becomes pretty simple even without framework functions:

    function constructQuery(){
    var key, opts, qs = [], enc = encodeURIComponent, opt,
        optAr, i;

        for( key in productOptions ) {
        opts = productOptions[key];
        optAr = [];
            for( i in opts ) {
                if( opts[i] ) {
                optAr.push( i );
                }
            }

            if( !optAr.length ) {
            continue;
            }

        qs.push( enc( key ) + "=" + enc( optAr.join( "," ) ) );
        }

    return "?"+qs.join( "&" );
    };

    //To toggle a value and construct the new query, pass what you want to toggle to this function:

    function toggleOption( optionType, option ) {

        if( optionType in productOptions && option in productOptions[optionType] ) {
        productOptions[optionType][option] = !productOptions[optionType][option];
        }

    return constructQuery();
    }

window.toggleOption = toggleOption;
})()

使用示例:

// "%2C" = url encoded version of ","

toggleOption(); //Default query returned:
"?color=red%2Cblue&size=small%2Cmedium%2Clarge&shape=round"

toggleOption( "color", "red" ); //Red color removed:
"?color=blue&size=small%2Cmedium%2Clarge&shape=round"

toggleOption( "color", "blue" ); //Blue color removed, no color options so color doesn't show up at all:
"?size=small%2Cmedium%2Clarge&shape=round"

toggleOption( "color", "blue" ); //Blue color enabled again:
"?color=blue&size=small%2Cmedium%2Clarge&shape=round"

toggleOption( "shape", "round" ); //The only shape option removed
"?color=blue&size=small%2Cmedium%2Clarge"

答案 4 :(得分:0)

我试过这个,这可能会产生欲望的结果

<script>
var url='http://example.com?color=red&size=small,medium,large&shape=round';
var mySplitResult = url.split("?");
var domain=mySplitResult[0];
var qstring=mySplitResult[1];
var proparr=new Array();
var valarr=new Array();
var mySplitArr = qstring.split("&");
for (i=0;i<mySplitArr.length;i++){ 
    var temp = mySplitArr[i].split("=");
    proparr[i]=temp[0];
    valarr[i]=temp[1].split(",");   
 }
function toggle(property,value)
{
    var index;
    var yes=0;
    for (i=0;i<proparr.length;i++){ 
    if(proparr[i]==property)
    index=i;
    }
    if(index==undefined){
    proparr[i]=property;
    index=i;
    valarr[index]=new Array();  
    }   
    for (i=0;i<valarr[index].length;i++){ 
        if(valarr[index][i]==value){
        valarr[index].splice(i,1);
        yes=1;
        }   
    }
    if(!yes)
    {
    valarr[index][i]=value;
    }
    var furl=domain +'?';
    var test=new Array();
    for(i=0;i<proparr.length;i++)
    {
    if(valarr[i].length)
    {
    test[i]=valarr[i].join(",");
    furl +=proparr[i]+"="+test[i]+"&";  
    }   
    }
    furl=furl.substr(0,furl.length-1)
    alert(furl);
}
</script>


<div>
<input id="color" type="button" value="Toggle Red" onclick="toggle('color','red')"/>
<input id="shape" type="button" value="Toggle shape" onclick="toggle('shape','round')"/>
<input id="size" type="button" value="Toggle Small" onclick="toggle('size','small')"/>
<input id="size" type="button" value="Toggle large" onclick="toggle('size','large')"/>
<input id="size" type="button" value="Toggle medium" onclick="toggle('size','medium')"/>
<input id="size" type="button" value="Toggle new" onclick="toggle('new','yes')"/>
</div>