我一直在抨击这个。
使用jquery或javascript,如何切换变量&值然后重建查询字符串?例如,我的起始网址为:
http://example.com?color=red&size=small,medium,large&shape=round
然后,如果用户点击标有“红色”的按钮,我想最终得到:
http://example.com?size=small,medium,large&shape=round //color is removed
然后,如果用户再次点击“红色”,我想最终得到:
http://example.com?size=small,medium,large&shape=round&color=red //color is added back
然后,如果用户点击标有“中等”的按钮,我想最终得到:
http://example.com?size=small,large&shape=round&color=red //medium is removed from list
然后,如果用户再次点击标有“媒介”,我想最终得到:
http://example.com?size=small,large,medium&shape=round&color=red //medium added back
变量的顺序并不重要;我刚刚把它们搞定到最后。
答案 0 :(得分:8)
function toggle(url, key, val) {
var out = [],
upd = '',
rm = "([&?])" + key + "=([^&]*?,)?" + val + "(,.*?)?(&.*?)?$",
ad = key + "=",
rmrplr = function(url, p1, p2, p3, p4) {
if (p2) {
if (p3) out.push(p1, key, '=', p2, p3.substr(1));
else out.push(p1, key, '=', p2.substr(0, p2.length - 1));
} else {
if (p3) out.push(p1, key, '=', p3.substr(1));
else out.push(p1);
}
if (p4) out.push(p4);
return out.join('').replace(/([&?])&/, '$1').replace(/[&?]$/, ''); //<!2
},
adrplr = function(s) {
return s + val + ',';
};
if ((upd = url.replace(new RegExp(rm), rmrplr)) != url) return upd;
if ((upd = url.replace(new RegExp(ad), adrplr)) != url) return upd;
return url + (/\?.+/.test(url) ? '&' : '?') + key + '=' + val; //<!1
}
params自我描述不够,希望对此有所帮助。
!1:从...? '&' : ''
更改为... ? '&' : '?'
!2:从.replace('?&','?')...
更改为.replace(/([&?]&)/,'$1')...
答案 1 :(得分:5)
我编写了一个函数,它可以有效地产生预期的行为,而不使用任何库或框架。可以在这个小提琴上找到动态演示:http://jsfiddle.net/w8D2G/1/
<强>解释强>:
显示的示例值将在下面的“使用”部分使用
- Haystack - 要搜索的字符串(默认=查询字符串。例如:?size=small,medium
)
- 针 - 搜索的关键。示例:size
- 值 - 要替换/添加的值。示例:medium
。
用法(示例:input > output
):
qs_replace(needle, value)
?size=small,medium > ?size=small
?size=small > size=small,medium
qs_replace(needle, options)
对象选项。认可的选择:
find
强> true
,否则返回false
。add
, remove
或 toggle
needle
中添加/删除给定值。如果使用remove
,并且该值是唯一值,则needle
也会被删除。如果值已存在,则不会添加该值。ignorecase
needle
,add
,remove
或{{1} })。find
separator
的值。默认为逗号(needle
)。 注意:也可以通过将其添加为第一个参数来定义字符串,
的不同值:haystack
或qs_replace(haystack, needle, value)
代码(底部的例子)。 小提琴:http://jsfiddle.net/w8D2G/1/ :
qs_replace(haystack, needle, options)
示例(小提琴:http://jsfiddle.net/w8D2G/1/ ):
function qs_replace(haystack, needle, options) {
if(!haystack || !needle) return ""; // Without a haystack or needle.. Bye
else if(typeof needle == "object") {
options = needle;
needle = haystack;
haystack = location.search;
} else if(typeof options == "undefined") {
options = needle;
needle = haystack;
haystack = location.search;
}
if(typeof options == "string" && options != "") {
options = {remove: options};
var toggle = true;
} else if(typeof options != "object" || options === null) {
return haystack;
} else {
var toggle = !!options.toggle;
if (toggle) {
options.remove = options.toggle;
options.toggle = void 0;
}
}
var find = options.find,
add = options.add,
remove = options.remove || options.del, //declare remove
sep = options.sep || options.separator || ",", //Commas, by default
flags = (options.ignorecase ? "i" :"");
needle = encodeURIComponent(needle); //URL-encoding
var pattern = regexp_special_chars(needle);
pattern = "([?&])(" + pattern + ")(=|&|$)([^&]*)(&|$)";
pattern = new RegExp(pattern, flags);
var subquery_match = haystack.match(pattern);
var before = /\?/.test(haystack) ? "&" : "?"; //Use ? if not existent, otherwise &
var re_sep = regexp_special_chars(sep);
if (!add || find) { //add is not defined, or find is used
var original_remove = remove;
if (subquery_match) {
remove = encodeURIComponent(remove);
remove = regexp_special_chars(remove);
remove = "(^|" + re_sep + ")(" + remove + ")(" + re_sep + "|$)";
remove = new RegExp(remove, flags);
var fail = subquery_match[4].match(remove);
} else {
var fail = false;
}
if (!add && !fail && toggle) add = original_remove;
}
if(find) return !!subquery_match || fail;
if (add) { //add is a string, defined previously
add = encodeURIComponent(add);
if(subquery_match) {
var re_add = regexp_special_chars(add);
re_add = "(^|" + re_sep + ")(" + re_add + ")(?=" + re_sep + "|$)";
re_add = new RegExp(re_add, flags);
if (subquery_match && re_add.test(subquery_match[4])) {
return haystack;
}
if (subquery_match[3] != "=") {
subquery_match = "$1$2=" + add + "$4$5";
} else {
subquery_match = "$1$2=$4" + sep + add + "$5";
}
return haystack.replace(pattern, subquery_match);
} else {
return haystack + before + needle + "=" + add;
}
} else if(subquery_match){ // Remove part. We can only remove if a needle exist
if(subquery_match[3] != "="){
return haystack;
} else {
return haystack.replace(pattern, function(match, prefix, key, separator, value, trailing_sep){
// The whole match, example: &foo=bar,doo
// will be replaced by the return value of this function
var newValue = value.replace(remove, function(m, pre, bye, post){
return pre == sep && post == sep ? sep : pre == "?" ? "?" : "";
});
if(newValue) { //If the value has any content
return prefix + key + separator + newValue + trailing_sep;
} else {
return prefix == "?" ? "?" : trailing_sep; //No value, also remove needle
}
}); //End of haystack.replace
} //End of else if
} else {
return haystack;
}
// Convert string to RegExp-safe string
function regexp_special_chars(s){
return s.replace(/([[^$.|?*+(){}\\])/g, '\\$1');
}
}
答案 2 :(得分:2)
这是您的任务的解决方案:http://jsfiddle.net/mikhailov/QpjZ3/12/
var url = 'http://example.com?size=small,medium,large&shape=round';
var params = $.deparam.querystring(url);
var paramsResult = {};
var click1 = { size: 'small' };
var click2 = { size: 'xlarge' };
var click3 = { shape: 'round' };
var click4 = { shape: 'square' };
var clickNow = click4;
for (i in params) {
var clickKey = _.keys(clickNow)[0];
var clickVal = _.values(clickNow)[0];
if (i == clickKey) {
var ar = params[i].split(',');
if (_.include(ar, clickVal)) {
var newAr = _.difference(ar, [clickVal]);
} else {
var newAr = ar;
newAr.push(clickVal);
}
paramsResult[i] = newAr.join(',');
} else {
paramsResult[i] = params[i];
}
}
alert($.param(paramsResult)) // results see below
Init params string
{ size="small, medium,large", shape="round"} // size=small,medium,large&shape=round
<强>结果
{ size="small"} => { size="medium,large", shape="round"} //size=medium%2Clarge&shape=round
{ size="xlarge"} => { size="small,medium,large,xlarge", shape="round"} // size=small%2Cmedium%2Clarge%2Cxlarge&shape=round
{ shape="round"} => { size="small,medium,large", shape=""} //size=small%2Cmedium%2Clarge&shape=
{ shape="square"} => { size="small,medium,large", shape="round,square"} //size=small%2Cmedium%2Clarge&shape=round%2Csquare
答案 3 :(得分:2)
productOptions
是您在此处需要修改的唯一内容,列出所有可用选项及其默认状态。您只需使用公共API函数toggleOption()
来切换选项。
(function(){
//Just keep an object with all the options with flags if they are enabled or disabled:
var productOptions = {
color: {
"red": true,
"blue": true,
"green": false
},
size: {
"small": true,
"medium": true,
"large": true
},
shape: {
"round": true
}
};
//After this constructing query becomes pretty simple even without framework functions:
function constructQuery(){
var key, opts, qs = [], enc = encodeURIComponent, opt,
optAr, i;
for( key in productOptions ) {
opts = productOptions[key];
optAr = [];
for( i in opts ) {
if( opts[i] ) {
optAr.push( i );
}
}
if( !optAr.length ) {
continue;
}
qs.push( enc( key ) + "=" + enc( optAr.join( "," ) ) );
}
return "?"+qs.join( "&" );
};
//To toggle a value and construct the new query, pass what you want to toggle to this function:
function toggleOption( optionType, option ) {
if( optionType in productOptions && option in productOptions[optionType] ) {
productOptions[optionType][option] = !productOptions[optionType][option];
}
return constructQuery();
}
window.toggleOption = toggleOption;
})()
使用示例:
// "%2C" = url encoded version of ","
toggleOption(); //Default query returned:
"?color=red%2Cblue&size=small%2Cmedium%2Clarge&shape=round"
toggleOption( "color", "red" ); //Red color removed:
"?color=blue&size=small%2Cmedium%2Clarge&shape=round"
toggleOption( "color", "blue" ); //Blue color removed, no color options so color doesn't show up at all:
"?size=small%2Cmedium%2Clarge&shape=round"
toggleOption( "color", "blue" ); //Blue color enabled again:
"?color=blue&size=small%2Cmedium%2Clarge&shape=round"
toggleOption( "shape", "round" ); //The only shape option removed
"?color=blue&size=small%2Cmedium%2Clarge"
答案 4 :(得分:0)
我试过这个,这可能会产生欲望的结果
<script>
var url='http://example.com?color=red&size=small,medium,large&shape=round';
var mySplitResult = url.split("?");
var domain=mySplitResult[0];
var qstring=mySplitResult[1];
var proparr=new Array();
var valarr=new Array();
var mySplitArr = qstring.split("&");
for (i=0;i<mySplitArr.length;i++){
var temp = mySplitArr[i].split("=");
proparr[i]=temp[0];
valarr[i]=temp[1].split(",");
}
function toggle(property,value)
{
var index;
var yes=0;
for (i=0;i<proparr.length;i++){
if(proparr[i]==property)
index=i;
}
if(index==undefined){
proparr[i]=property;
index=i;
valarr[index]=new Array();
}
for (i=0;i<valarr[index].length;i++){
if(valarr[index][i]==value){
valarr[index].splice(i,1);
yes=1;
}
}
if(!yes)
{
valarr[index][i]=value;
}
var furl=domain +'?';
var test=new Array();
for(i=0;i<proparr.length;i++)
{
if(valarr[i].length)
{
test[i]=valarr[i].join(",");
furl +=proparr[i]+"="+test[i]+"&";
}
}
furl=furl.substr(0,furl.length-1)
alert(furl);
}
</script>
<div>
<input id="color" type="button" value="Toggle Red" onclick="toggle('color','red')"/>
<input id="shape" type="button" value="Toggle shape" onclick="toggle('shape','round')"/>
<input id="size" type="button" value="Toggle Small" onclick="toggle('size','small')"/>
<input id="size" type="button" value="Toggle large" onclick="toggle('size','large')"/>
<input id="size" type="button" value="Toggle medium" onclick="toggle('size','medium')"/>
<input id="size" type="button" value="Toggle new" onclick="toggle('new','yes')"/>
</div>