我对python的urllib很新。我需要做的是为发送到服务器的请求设置自定义标头。具体来说,我需要设置Content-type和Authorizations标头。我查看了python文档,但是我找不到它。
答案 0 :(得分:78)
使用urllib2添加HTTP标头:
来自文档:
import urllib2
req = urllib2.Request('http://www.example.com/')
req.add_header('Referer', 'http://www.python.org/')
resp = urllib2.urlopen(req)
content = resp.read()
答案 1 :(得分:71)
对于Python 3和Python 2,这都有效:
try:
from urllib.request import Request, urlopen # Python 3
except ImportError:
from urllib2 import Request, urlopen # Python 2
req = Request('http://api.company.com/items/details?country=US&language=en')
req.add_header('apikey', 'xxx')
content = urlopen(req).read()
print(content)
答案 2 :(得分:14)
使用urllib2并创建一个Request对象,然后将其移交给urlopen。 http://docs.python.org/library/urllib2.html
我不再使用“旧的”urllib了。
req = urllib2.Request("http://google.com", None, {'User-agent' : 'Mozilla/5.0 (Windows; U; Windows NT 5.1; de; rv:1.9.1.5) Gecko/20091102 Firefox/3.5.5'})
response = urllib2.urlopen(req).read()
...未经测试
答案 3 :(得分:1)
对于多个标题,请执行以下操作:
import urllib2
req = urllib2.Request('http://www.example.com/')
req.add_header('param1', '212212')
req.add_header('param2', '12345678')
req.add_header('other_param1', 'sample')
req.add_header('other_param2', 'sample1111')
req.add_header('and_any_other_parame', 'testttt')
resp = urllib2.urlopen(req)
content = resp.read()