编辑:从XmlTextWriter切换到XElement
我有一个Player类,它有以下变量:
static string Name;
static int Level;
static int Cash;
我已将它们保存到带有XElement的“Profiles.xml”文件中,现在看起来像这样:
<John>
<level>3</level>
<cash>215</cash>
</John>
<Mike>
<level>7</level>
<cash>780</cash>
</Mike>
现在,如果我有名字,fe。迈克,我如何获得现金和水平?
答案 0 :(得分:1)
你去..
XDocument doc = XDocument.Parse(@"
<Players><John>
<level>3</level>
<cash>215</cash>
</John>
<Mike>
<level>7</level>
<cash>780</cash>
</Mike>
</Players>");
var players = doc.Root.Elements();
foreach (var player in players)
{
if (player.Name.ToString() == "Mike")
{
Console.WriteLine(player.Element("level"));
Console.WriteLine(player.Element("cash"));
}
}
答案 1 :(得分:0)
使用xml序列化,这一切都将消失。
一般地序列化:
public string Serialise(T someObject)
{
XmlSerializer ser = new XmlSerializer(typeof (T));
MemoryStream memStream = new MemoryStream();
XmlConfigTextWriter xmlWriter = new XmlConfigTextWriter(memStream, Encoding.UTF8);
xmlWriter.Namespaces = true;
XmlSerializerNamespaces ns = new XmlSerializerNamespaces();
ns.Add("", ""); //we don't want namespace data here.
ser.Serialize(xmlWriter, someObject, ns);
xmlWriter.Close();
memStream.Close();
string xml = Encoding.UTF8.GetString(memStream.GetBuffer());
xml = xml.Substring(xml.IndexOf(Convert.ToChar(60)));
xml = xml.Substring(0, (xml.LastIndexOf(Convert.ToChar(62)) + 1));
return xml;
}
并反序列化:
public T Deserialise(string objectXml)
{
XmlSerializer reader = new XmlSerializer(typeof (T));
StringReader stringReader = new StringReader(objectXml);
XmlTextReader xmlReader = new XmlTextReader(stringReader);
return (T) reader.Deserialize(xmlReader);
}
答案 2 :(得分:0)
创建控制台应用程序并使用LINQ to XML。
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml.Linq;
namespace ConsoleApplication8
{
public class Player
{
public string Name { get; set; }
public int level { get; set; }
public int cash { get; set; }
}
class Program
{
static void Main(string[] args)
{
// you may have several players like below
List<Player> Players = new List<Player>() {
new Player() { Name = "John", cash = 3, level = 215 },
new Player() { Name = "Mike", level = 7, cash = 780 }
};
// save them to Xml file
Save("players.xml", Players);
//when you need details of a given player "Mike"
Player PlayersMike = Load("players.xml", "Mike");
// Adding new player
AddPlayer("players.xml", new Player() { Name = "Test", level = 1, cash = 780 });
}
/// <summary>
/// Saves the specified XML file with players data
/// </summary>
/// <param name="xmlFile">The XML file.</param>
/// <param name="Players">The players.</param>
public static void Save(string xmlFile, List<Player> Players)
{
XElement xml = new XElement("Players",
from p in Players
select new XElement("Player",
new XElement("Name", p.Name),
new XElement("level", p.level),
new XElement("cash", p.cash)));
xml.Save(xmlFile);
}
/// <summary>
/// Loads the specified XML file.
/// </summary>
/// <param name="xmlFile">The XML file.</param>
/// <returns></returns>
public static Player Load(string xmlFile, string name)
{
XDocument doc = XDocument.Load(xmlFile);
var query = (from xElem in doc.Descendants("Player")
where xElem.Element("Name").Value.Equals(name)
select new Player
{
Name = xElem.Element("Name").Value,
level = int.Parse(xElem.Element("level").Value),
cash = int.Parse(xElem.Element("cash").Value),
}).FirstOrDefault();
return query;
}
/// <summary>
/// Adds the player.
/// </summary>
/// <param name="xmlFile">The XML file.</param>
/// <param name="p">The p.</param>
public static void AddPlayer( string xmlFile, Player p)
{
XDocument doc = XDocument.Load(xmlFile);
doc.Element("Players").Add(
new XElement("Player",
new XElement("Name", p.Name),
new XElement("level", p.level),
new XElement("cash", p.cash)));
doc.Save(xmlFile);
}
}
}