Question

我的服务器上运行了一个运行我的Web服务的PHP代码。它以发送整数值处理数据。我怎么能得到它？这是我的请求网址：

  NSString *requestURL=[NSString stringWithFormat:@"%@?u=%@&  p=%@&platform=ios",url,txtUserName.text,txtPassword.text];

更新评论：我的服务器上有一个php文件。它需要3个参数并注册我的用户并返回值为1（成功，2表示重复）。我需要将请求发送到我的服务器：

url="http://smwebtech.com/Pandit/web_service/signup.php?u=Test&p=password&platform=ios"

如何将此请求发送到服务器并从服务器获取返回值？

Answer 1

您可以使用NSURLConnection。您应该使用NSURLConnectionDataDelegate协议实现并使用NSURLConnection类。

-(void) requestPage
{
    NSString *urlString = @"http://the.page.you.want.com";
    NSURL *url = [NSURL URLWithString:urlString];

    NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url cachePolicy:NSURLCacheStorageAllowed timeoutInterval:20.0f];


    responseData = [[NSMutableData alloc] init];
    connection = [[NSURLConnection connectionWithRequest:request delegate:self] retain];
    delegate = target;
}


-(void) connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response
{   
    if ([response isKindOfClass:[NSHTTPURLResponse class]])
    {
        NSHTTPURLResponse *httpResponse = (NSHTTPURLResponse*) response; 
        //If you need the response, you can use it here
    }
}

-(void) connection:(NSURLConnection *)connection didReceiveData:(NSData *)data
{
    [responseData appendData:data];
}

-(void) connection:(NSURLConnection *)connection didFailWithError:(NSError *)error
{
    [responseData release];
    [connection release];
}

-(void) connectionDidFinishLoading:(NSURLConnection *)connection
{
    if (connection == adCheckConnection)
    {
        NSString *responseString = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding];

        //You've got all the data now
        //Do something with your response string


        [responseString release];
    }

    [responseData release];
    [connection release];
}

Answer 2

如果您正在寻找一种向服务器发出HTTP请求的方法，那么有许多框架可以帮助您实现这一目标。直到最近，ASIHTTPRequest是我所青睐的，但不幸的是它已经停止。

Google's API Client Library也是一个很好的选择，以及ASIHTTPRequest创建者的number of others suggested。

应该有很多文档可以帮助你入门。

编辑：要使用ASIHTTPRequest发出特定请求，请在具有协议ASIHTTPRequestDelegate的课程中执行以下操作：

/**
 * Make a request to the server.
 */
- (void) makeRequest {
    // compile your URL string and make the request
    NSString *requestURL = [NSString stringWithFormat:@"%@?u=%@&  p=%@&platform=ios", url, txtUserName.text, txtPassword.text];

    NSURL *url = [NSURL URLWithString:requestURL];
    ASIHTTPRequest *request = [ASIHTTPRequest requestWithURL:url];
    [request setDelegate:self];
    [request startAsynchronous];
}

/**
 * Handle the response from the previous request.
 * @see ASIHTTPRequestDelegate
 */
- (void) requestFinished:(ASIHTTPRequest*)request {
    NSString *responseString = [request responseString];
    // do whatever you need with the response, i.e. 
    // convert it to a JSON object using the json-framework (https://github.com/stig/json-framework/) 
}

Answer 3

访问HTTPRequest并根据给定的说明在您的项目中设置它。
TouchJSON - 下载并将其放入您的项目中。

下面是您可以用来发送请求和获得响应的方法。

  -(void) SendAsyncReq:(NSString *)urlString 
   {


NSLog(@"URL IS: %@",urlString);
NSURL *url = [NSURL URLWithString:[urlString     stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];


ASIHTTPRequest *request1 = [ASIHTTPRequest requestWithURL:url];

[request1 setDelegate:self];


    [request1 startAsynchronous];
}

  /// THIS METHOD WILL BE CALLED IF REQUEST IS COMPLETED SUCCESSFULLY

 - (void)requestFinished:(ASIHTTPRequest *)response
{
NSData *responseData = [response responseData];

CJSONDeserializer *jsonDeserializer = [CJSONDeserializer   deserializer];

NSDictionary *resultsDictionary = [jsonDeserializer  deserializeAsDictionary:responseData error:nil];

NSLog(@"Response is: %@",resultsDictionary);


    }

 /// THIS METHOD WILL BE CALLED IF REQUEST IS FAILED DUE TO SOME REASON.

- (void)requestFailed:(ASIHTTPRequest *)response
{
NSError *error = [response error];
NSLog(@"%d", [error code]);
if([error code] !=4)
{
    NSString *errorMessage = [error localizedDescription];
    UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:@"Error"
                                                        message:errorMessage
                                                   delegate:nil
                                          cancelButtonTitle:@"OK"
                                          otherButtonTitles:nil];
    [alertView show];
    [alertView release];
}



}

你必须在你的班级中导入#import“CJSONDeserializer.h”和#import“ASIHTTPRequest.h”。我希望这会有所帮助。

发送请求并获取响应

3 个答案: