如何让android模拟器报告特定的屏幕大小

时间:2011-10-27 18:40:19

标签: android android-emulator android-screen android-screen-support

我正在尝试模仿HTC Flyer,为了做到这一点,我需要模拟器自我报告为“大”屏幕大小。我已经指定了分辨率和正确的dpi,但它报告为“xlarge”。 android文档(http://developer.android.com/guide/practices/screens_support.html#range)指定它应该是“xlarge”,但HTC Flyer设备说它“大”。这是一些带有一些数字的调试输出:

flyer device 

DisplayMetrics{density=1.0, width=600, height=1024, scaledDensity=1.0, xdpi=169.99738, ydpi=169.33333}, densityDpi, 160, density, 1.0, screen size, large,

flyer emulator

DisplayMetrics{density=1.0, width=600, height=1024, scaledDensity=1.0, xdpi=160.0, ydpi=160.0}, densityDpi, 160, density, 1.0, screen size, xlarge,

注意“屏幕尺寸”。其他一切都是相同的,但设备报告“大”和模拟器“xlarge”。有没有办法让模拟器报告“大”?

这是给我输出的java:

 DisplayMetrics metrics = new DisplayMetrics();
    getWindowManager().getDefaultDisplay().getMetrics(metrics);
    int screenLayout = getResources().getConfiguration().screenLayout & Configuration.SCREENLAYOUT_SIZE_MASK;
    String screenLayoutStr;
    switch (screenLayout){
        case Configuration.SCREENLAYOUT_SIZE_SMALL:
            screenLayoutStr = "small";
            break;
        case Configuration.SCREENLAYOUT_SIZE_NORMAL:
            screenLayoutStr = "normal";
            break;
        case Configuration.SCREENLAYOUT_SIZE_LARGE:
            screenLayoutStr = "large";
            break;
        case 4:
            screenLayoutStr = "xlarge";
            break;
        default:
            screenLayoutStr = "unknown: " + screenLayout;
    }
    LogIt.d(this,metrics,"densityDpi",metrics.densityDpi,"density",metrics.density,"screen size",screenLayoutStr);

0 个答案:

没有答案