Question

我使用Moq作为我的模拟框架，我需要测试一个类，当运行特定类型的异常时，它将继续尝试，直到执行完成后情况得到解决。

所以我需要的是类似的东西：

myMock = Mock<IFoo>();

myMock.Setup(m => m.Excecute()).Throws<SpecificException>();
myMock.Setup(m => m.Execute());

var classUnderTest = MyClass(myMock);
classUnderTest.DoSomething();

Assert.AreEqual(expected, classUnderTest.Result);

感谢您提供任何帮助。

Answer 1

这是一种方法，基于在每次调用时返回不同值的Moq QuickStart示例。

var mock = new Mock<IFoo>();
var calls = 0;
mock.Setup(foo => foo.GetCountThing())
    .Returns(() => calls)
    .Callback(() =>
     {
        calls++;
        if (calls == 1)
        {
            throw new InvalidOperationException("foo");
        }
     });

try
{
    Console.WriteLine(mock.Object.GetCountThing());
}
catch (InvalidOperationException)
{
    Console.WriteLine("Got exception");
}

Console.WriteLine(mock.Object.GetCountThing());

如果方法返回void，请使用：

var myMock = new Mock<IFoo>();
bool firstTimeExecuteCalled = true;

myMock.Setup(m => m.Execute())
      .Callback(() =>
       {
            if (firstTimeExecuteCalled)
            {
                firstTimeExecuteCalled = false;
                throw new SpecificException();
            }
       });

try
{
    myMock.Object.Execute();
}
catch (SpecificException)
{
    // Would really want to call Assert.Throws instead of try..catch.
    Console.WriteLine("Got exception");
}

myMock.Object.Execute();
Console.WriteLine("OK!");

Answer 2

为什么不编写自己的测试对象呢？如果它只是用于测试，例如：

public class Mock : IFoo
{
     private int _calls;

     public Mock()
     {
         _calls = 0;
     }

     public int Execute()
     {
         _calls++;

         if (_calls == 1)
             throw new Exception();

         return value;

     }

}

如何使模拟首次抛出异常并返回第二个值

2 个答案: