Question

我有一个名为Data_Details的表，数据如下：

DateTimeClosed            Datesub            TimeSub
6/20/2011 18:00           5/16/2011          17:13:17
6/20/2011 18:00           5/18/2011          13:45:17
6/1/2011 19:00            5/24/2011          8:30:12

我试图在分钟内获得关闭日期和子日期之间的区别。

我写了这样的话：

SELECT  convert(int,convert(Datetime,[DateTimeClosed])-
(convert(Datetime,[Datesub])+convert(datetime,[TimeSub])))*24*60 
FROM dbo.Data_details

它给了我以下错误：

Msg 241，Level 16，State 1，Line 2 从字符串转换日期和/或时间时转换失败。

任何人都可以帮助我吗？

Answer 1

以秒为单位返回时差：

select datediff(SECOND,'5/16/2011'+' '+'17:13:17','6/20/2011 18:00')

示例脚本：

declare @test as table
(
date1 datetime,
date2 date,
date3 time
)
insert into @test 
values
('6/20/2011 18:00'         ,  '5/16/2011'        ,  '17:13:17')
select Datediff(second,cast (date2 as varchar)+' '+ cast(date3 as varchar),date1) from @test

更新 - 现在使用varchars，OP澄清它们都是varchars：

declare @test as table
(
date1 varchar(50),
date2 varchar(50),
date3 varchar(50)
)
insert into @test 
values
('6/20/2011 18:00'         ,  '5/16/2011'        ,  '17:13:17')
select Datediff(second,cast (date2 +' '+date3 as datetime),cast (date1 as datetime)) from @test

Answer 2

试试这个：

SELECT DATEDIFF(MINUTE,CONVERT(DATETIME,Datesub + ' ' + TimeSub,101),CONVERT(DATETIME,DateTimeClosed,101))
FROM yourTable

Answer 3

我认为你正在寻找DateDiff

此示例将返回分钟：

SELECT DATEDIFF(m, CONVERT(datetime, [Datesub] + ' ' + [TimeSub]), CONVERT(datetime, [DateTimeClosed]))
FROM dbo.Data_details

Answer 4

SET DATEFORMAT MDY
;with dates AS 
(
SELECT '6/20/2011 18:00' as datetimeclosed,'5/16/2011' as datesub,'17:13:17' as timesub UNION ALL
SELECT '6/20/2011 18:00','5/18/2011','13:45:17' UNION ALL
SELECT '6/1/2011 19:00','5/24/2011','8:30:12' 
)
SELECT
DATEDIFF(minute,CAST(datesub + ' ' + timesub AS DATETIME),CAST(datetimeclosed AS DATETIME)) as time_diff_in_minutes
 FROM dates

如何获取日期时间，日期和时间列之间的时差

4 个答案: