Question

我需要在表格中显示照片库，我想在每一行上放五张照片，但在每张第五张照片后找不到插入</tr><tr>的方式。这是我的代码：

<?php

// table name
$tbl_name=gallery1;
$sql="SELECT * FROM $tbl_name";
$result=mysql_query($sql);

while($rows= mysql_fetch_assoc($result)){

$id         = $rows['id'];
$path       = $rows['path'];
$image_name = $rows['image_name'];
$title      = $rows['title'];
?>


<img src="<?php echo $path."/".$image_name;?>" height="120"/>Name:<?php echo $title;?>
<?php
echo "<form action='pictry.php' enctype='multipart/form-data' method='post'>
<input name='file[]' type='hidden' value='".$image_name."' />
<input name='id' type='hidden' id='id' value='".$id."'/>
<input type='submit' name='button' id='button' value='Delete Picture' /></form>";

}
?>

Answer 1

替换

行

while($rows= mysql_fetch_assoc($result)){

带

for($i = 0; $rows= mysql_fetch_assoc($result); ++$i) {

然后你把这样的东西放到for循环中。

if($i % 5 == 0) { /* insert stuff */ }

Answer 2

未经测试的代码

<?php
  $perrow = 5;
  $i = 0;
  echo '<table>';
  echo '<tr>';
  while($rows = mysql_fetch_assoc($result)) {
    echo '<td><img src=[grapresultfromrows] /></td>';
    ++$i;
    if($i == $perrow) {
      $i = 0;
      echo '</tr>';
      echo '<tr>';
    }
  }
  // If not a multiple of $perrow you need to add extra cells
  for($i; $i < $perrow; ++$i) {
   echo '<td></td>';
  }
  echo '</tr>';
  echo '</table>';
?>

html表显示php照片库

2 个答案: