Question

如何检查客户端浏览器是否通过C＃打开了弹出窗口阻止程序？

我试图像这样打开一个弹出窗口

ClientScript.RegisterStartupScript(this.GetType(), "newWindow", String.Format("<script>window.open('{0}', 'Cliente', 'toolbar=no,directories=no,status=no,menubar=no, scrollbars=yes,resizable=no', '720', '600', 'true'); </script>", url));

但如果浏览器有弹出窗口阻止程序，我需要打开警报

我该怎么做？

Answer 1

您可以这样做：

ClientScript.RegisterStartupScript(this.GetType(), "newWindow", String.Format("<script>var myPopup = window.open('{0}', 'Cliente','toolbar=no,directories=no,status=no,menubar=no, scrollbars=yes,resizable=no','720', '600', 'true');if(!myPopup)alert('a popup was blocked. please make an exception for this site in your popup blocker and try again');</script>",url));

注意：没有测试它是否编译，但这是一般的想法。

See this other similar question

编辑添加测试：

string mys="<script>var myPopup = window.open('{0}', 'Cliente','toolbar=no,directories=no,status=no,menubar=no, scrollbars=yes,resizable=no','720', '600', 'true');if(!myPopup)alert('a popup was blocked. please make an exception for this site in your popup blocker and try again');</script>";

Console.WriteLine(string.Format(mys,"page.aspx"));

制作：

<script>var myPopup = window.open('page.aspx', 'Cliente','toolbar=no,directories=no,status=no,menubar=no, scrollbars=yes,resizable=no','720', '600', 'true');if(!myPopup)alert('a popup was blocked. please make an exception for this site in your popup blocker and try again');</script>

我没有看到任何错误。现在，我的建议是删除<script></script>标记，让RegisterStarupScript通过传递true作为最后一个参数来添加它们：

ClientScript.RegisterStartupScript(this.GetType(), "newWindow", String.Format("var myPopup = window.open('{0}', 'Cliente','toolbar=no,directories=no,status=no,menubar=no, scrollbars=yes,resizable=no','720', '600', 'true');if(!myPopup)alert('a popup was blocked. please make an exception for this site in your popup blocker and try again');",url),true);

Answer 2

我猜所有现代浏览器都会阻止不是由用户的动作触发的弹出窗口，例如。点击某事。在打开窗口之前，你真的需要往服务器的往返吗？

如果不需要往返，您应该执行以下操作：

<input type="button" onclick="openWindow()" value="open window" />
<script type="text/javascript">
    function openWindow() {
        window.open('<%= Url %>', 'Cliente', 'toolbar=no,directories=no,status=no,menubar=no, scrollbars=yes,resizable=no', '720', '600', 'true');
    }
</script>

PopUp Blocker验证

2 个答案: