Question

我写了一个简单的图片库，用于检查文件夹并显示我有代码的文件夹中的所有图像以删除。和..但它不工作，我不明白为什么任何帮助将是伟大的，因为我是PHP的dir函数的新手。我有链接围绕链接的灯箱标签因此额外的回声代码如下：

<?
// USER OPTIONS DEDFINED HERE

$dir = "img/";      //folder with images
$height ="196px";   //image height on page its displayed in full in lightbox
$width ="320px";    //image width on page its displayed in full in lightbox
?>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"     "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head> 
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> 
<title>Gallery</title> 
<link href="css/css.css" rel="stylesheet" type="text/css" />
<script type="text/javascript" src="js/prototype.js"></script>
<script type="text/javascript" src="js/scriptaculous.js?load=effects,builder"></script>
<script type="text/javascript" src="js/lightbox.js"></script>
</head>

<?

//open directory
if ($opendir = opendir($dir));

{

//read dir
while (FALSE !== ($file = readdir($opendir)))
{   
    if ($file!="."&&$file!="..")
        echo "<div class='imgwraper'>";
        echo"<a href='$dir$file' rel='lightbox[gallery]' title='$filename'>";
        echo "<img src='$dir$file' alt='' width='$width' height='$height'/>";
        echo"</a>";
        echo "<div class='name_box'>";
        echo current(explode('.', $file));
        echo "</div>";
        echo "</div>";

}
closedir($opendir); 
}

?>

先谢谢

路易斯

Answer 1

if ($file!="."&&$file!="..")后您没有大括号，if语句仅适用于echo "<div class='imgwraper'>";的第一行。

将所有内容包裹在大括号中：

while (FALSE !== ($file = readdir($opendir)))
{   
    if ($file!="."&&$file!="..") {
        echo "<div class='imgwraper'>";
        echo"<a href='$dir$file' rel='lightbox[gallery]' title='$filename'>";
        echo "<img src='$dir$file' alt='' width='$width' height='$height'/>";
        echo"</a>";
        echo "<div class='name_box'>";
        echo current(explode('.', $file));
        echo "</div>";
        echo "</div>";
    }
}

顺便说一下，您可以考虑使用glob来简化代码。

Answer 2

不要忘记用if括号括起if语句。

while (FALSE !== ($file = readdir($opendir)))
{   
if ($file!="."&&$file!=".."){
    echo "<div class='imgwraper'>";
    echo"<a href='$dir$file' rel='lightbox[gallery]' title='$filename'>";
    echo "<img src='$dir$file' alt='' width='$width' height='$height'/>";
    echo"</a>";
    echo "<div class='name_box'>";
    echo current(explode('.', $file));
    echo "</div>";
    echo "</div>";
}
}

晒。

PHP readdir点不断显示

2 个答案: