Question

我需要checkBox 3来禁用checkBox 1＆amp; 2选中时。当我在第3个复选框标记中有onClick时代码有效，但我的首席程序员需要上面JavaScript代码中的onClick。我对JS不太好，所以我不知道为什么它不起作用。这就是我到目前为止所做的：

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<meta name="Content-Script-Type" content="text/javascript">
<meta name="Content-Style-Type" content="text/css">
<title>Example</title>

<SCRIPT TYPE="text/javascript">
<!--

var field = document.getElementById("check_1157");
if (field)
{
  function update1157Box(contactMethod)
  {
    var contactMethod = document.getElementById("check_1157");

    if(contactMethod.check_1157.checked)
    {
      //enable the not to receive information
      contactMethod.check_1156.disabled =true;
      contactMethod.check_1156.checked = false;
      contactMethod.check_1158.disabled =true;
      contactMethod.check_1158.checked = false;
      return;
    }
  }

  field.onClick = update1157Box(this.form)

  //the not to receive information
  contactMethod.check_1156.checked = false;
  contactMethod.check_1156.disabled = false;
  contactMethod.check_1158.checked = false;
  contactMethod.check_1158.disabled = false;
}

//-->
</SCRIPT>

</head>
<body>

<form>
  <div class="many-from-many">
    <label style="display: block;"><input id="check_1156"
     name="answers[166][]" value="1156" type="checkbox">Check Box 1</label>
    <label style="display: block;"><input id="check_1158"
     name="answers[166][]" value="1158" type="checkbox"> Check Box 2</label>
    <label style="display: block;"><input id="check_1157"
     name="answers[166][]" value="1157" type="checkbox">Check Box 3</label>
  </div>
</form>
</body>
</html>

Answer 1

jQuery使事件处理程序变得轻而易举：

$('#check_1157').click(function() {
    if ($(this).prop('checked')) {
        $('#check_1156, #check_1158').prop({
            checked: false,
            disabled: true
        });
    } else {
        $('#check_1156, #check_1158').prop({disabled: false});
    }
});

Answer 2

由于Eric的解决方案是使用jQuery，这里有一个纯JavaScript替代方案：

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<meta name="Content-Script-Type" content="text/javascript">
<meta name="Content-Style-Type" content="text/css">
<title>Example</title>

<SCRIPT TYPE="text/javascript">
<!--

var toggle_list = ['check_1156', 'check_1158'];


function toggle(checkbox) {
    if (checkbox.disabled) {
        checkbox.removeAttribute('disabled');
    } else {
        checkbox.setAttribute('disabled', true);
    }
}

function toggleActivation() {
    for (var i=0; i<toggle_list.length; i++) {
        var id = toggle_list[i];
        var checkbox = document.getElementById(id);
        toggle(checkbox);
    }
}

//-->
</SCRIPT>

</head>
<body>

<form>
  <div class="many-from-many">
    <label style="display: block;"><input id="check_1156"
     name="answers[166][]" value="1156" type="checkbox">Check Box 1</label>
    <label style="display: block;"><input id="check_1158"
     name="answers[166][]" value="1158" type="checkbox"> Check Box 2</label>
    <label style="display: block;"><input id="check_1157"
     name="answers[166][]" value="1157" type="checkbox" onchange="toggleActivation()">Check Box 3</label>
  </div>
</form>
</body>
</html>

这可能不是IE安全，因为我目前正在运行Linux。如果它在IE中不起作用，问题将出现在切换功能中。

Answer 3

我的方法与Fabian相似，我会做一些这样的事情，因为你有一个div围绕那些被称为多对多的三个复选框，这将寻找（父<lable> }）第三个复选框的节点（父<DIV>），然后找到childNodes（复选框）

<form>
  <div class="many-from-many"><label style="display: block;"><input id="check_1156"name="answers[166][]" value="1156" type="checkbox">Check Box 1</label><label style="display: block;"><input id="check_1158"name="answers[166][]" value="1158" type="checkbox">Check Box 2</label><label style="display: block;"><input id="check_1157"name="answers[166][]" value="1157" type="checkbox" onclick="togTopTwo(this)">Check Box 3</label></div>
</form>

 function togTopTwo(c){
    var mm = c.parentNode.parentNode;
    var xx = mm.firstChild.firstChild;
    var secondOfMany = xx.parentNode.nextSibling.firstChild;

    if(c.checked){
       xx.disabled=true;
       secondOfMany.disabled = true;
   }else{
       xx.disabled=false;
       secondOfMany.disabled =false;
   }

 }

JavaScript~我需要在选中第3个复选框时禁用2个复选框

3 个答案: