我有一个搜索脚本,我在网上找到的工作正常,但分页似乎有问题。当我点击'下一步'链接没有任何反应,但我收到此错误'未定义的变量:PHP_SELF'。我究竟做错了什么?请帮忙。代码如下:
<head>
<title>Search pegination</title>
<meta name="author" content="Steve R, http://www.designplace.org/">
</head>
<body>
<form name="form" action="search.php" method="get">
<input type="text" name="q" />
<input type="submit" name="Submit" value="Search" />
</form>
<?php
// Get the search variable from URL
$var = @$_GET['q'] ;
$trimmed = trim($var); //trim whitespace from the stored variable
$trimmed = mysql_real_escape_string( $trimmed );
// rows to return
$limit=3;
// check for an empty string and display a message.
if ($trimmed == "")
{
echo "<p>Please enter a search...</p>";
exit;
}
// check for a search parameter
if (!isset($var))
{
echo "<p>We dont seem to have a search parameter!</p>";
exit;
}
//connect to your database ** EDIT REQUIRED HERE **
mysql_connect("localhost","root",""); //(host, username, password)
//specify database ** EDIT REQUIRED HERE **
mysql_select_db("archivesys") or die("Unable to select database"); //select which database we're using
// Build SQL Query
$query = "select * from archdetaills_tbl where archivedate like \"%$trimmed%\"
order by archiveid"; // EDIT HERE and specify your table and field names for the SQL query
$numresults=mysql_query($query);
$numrows=mysql_num_rows($numresults);
// next determine if s has been passed to script, if not use 0
if (empty($s)) {
$s=0;
}
// get results
$query .= " limit $s,$limit";
$result = mysql_query($query) or die("Couldn't execute query");
// display what the person searched for
echo "<p>You searched for: "" . $var . ""</p>";
// begin to show results set
echo "Results";
$count = 1 + $s ;
// now you can display the results returned
while ($row= mysql_fetch_array($result)) {
$title = $row["archiveeemail"];
echo "$count.) $title" ;
$count++ ;
}
$currPage = (($s/$limit) + 1);
//break before paging
echo "<br />";
// next we need to do the links to other results
if ($s>=1) { // bypass PREV link if s is 0
$prevs=($s-$limit);
print " <a href=\"".$_SERVER['PHP_SELF']."?s=$prevs&q=$var\"><<
Prev 10</a>  ";
}
// calculate number of pages needing links
$pages=intval($numrows/$limit);
// $pages now contains int of pages needed unless there is a remainder from division
if ($numrows%$limit) {
// has remainder so add one page
$pages++;
}
// check to see if last page
if (!((($s+$limit)/$limit)==$pages) && $pages!=1) {
// not last page so give NEXT link
$news=$s+$limit;
echo " <a href=\"".$_SERVER['PHP_SELF']."?s=$news&q=$var\">Next 10 >></a>";
}
$a = $s + ($limit) ;
if ($a > $numrows) { $a = $numrows ; }
$b = $s + 1 ;
echo "<p>Showing results $b to $a of $numrows</p>";
?>
<!-- © http://www.designplace.org/ -->
</body>
</html>
答案 0 :(得分:1)
将$PHP_SELF
更改为$_SERVER['PHP_SELF']
:
print " <a href=\"".$_SERVER['PHP_SELF']."?s=$prevs&q=$var\"><< Prev 10</a>  ";
您的代码中还存在几个问题:
$trimmed
应该被转义,因为它是一个潜在的SQL注入:
$trimmed = mysql_real_escape_string( $trimmed );
$query = "select * from archdetaills_tbl where archivedate like \"%$trimmed%\" order by archiveid";
此代码可以缩短:
$var = @$_GET['q'] ;
$trimmed = trim($var);
分为:
$trimmed = isset( $_GET['q'] ) ? trim( $_GET['q'] ) : '';
答案 1 :(得分:0)
$ _ SERVER ['PHP_SELF']是正确的方法