我有一个简单的c ++程序,我试图通过python脚本执行。 (我是编写脚本的新手)我无法通过管道读取输出。从我所看到的,似乎readline()在没有EOF的情况下将无法工作,但我希望能够在程序中间读取并让脚本响应输出的内容。它只是挂起而不是读取输出 python脚本:
#!/usr/bin/env python
import subprocess
def callRandomNumber():
print "Running the random guesser"
rng=subprocess.Popen("./randomNumber", stdin=subprocess.PIPE, stdout=subprocess.PIPE, shell=True)
i=50
rng.stdin.write("%d\n" % i)
output=rng.stdout.readline()
output=rng.stdout.readline()
callRandomNumber()
和c ++文件,生成1到100之间的随机数,然后检查用户猜测,直到他们猜对了
#include<iostream>
#include<cstdlib>
using namespace std;
int main(){
cout<<"This program generates a random number from 1 to 100 and asks the user to enter guesses until they succuessfully guess the number. It then tells the user how many guesses it took them"<<endl;
srand(time(NULL));
int num=rand()%100;
int guessCount=0;
int guess=-1;
cout<<"Please enter a number: ";
cin>>guess;
while(guess!=num){
if(guess>num){cout<<"That guess is too high. Please guess again: ";}
else{cout<<"That guess is too low. Please guess again: ";}
cin>>guess;
guessCount++;
}
cout<<"Congratulations! You solved it in "<<guessCount<<" guesses!"<<endl;
return 0;
}
最终的目标是让脚本通过二进制搜索来解决问题,但是现在我只想在没有文件结尾的情况下读取一行
答案 0 :(得分:3)
作为@Ron Reiter pointed out,您无法使用readline()
,因为cout
无法隐式打印换行符 - 您需要std::endl
或"\n"
。
对于交互式使用,当您无法更改子程序时,pexpect
module提供了一些便捷方法(通常为it solves for free: input/output directly from/to terminal (outside of stdin/stdout) and block-buffering issues):
#!/usr/bin/env python
import sys
if sys.version_info[:1] < (3,):
from pexpect import spawn, EOF # $ pip install pexpect
else:
from pexpect import spawnu as spawn, EOF # Python 3
child = spawn("./randomNumber") # run command
child.delaybeforesend = 0
child.logfile_read = sys.stdout # print child output to stdout for debugging
child.expect("enter a number: ") # read the first prompt
lo, hi = 0, 100
while lo <= hi:
mid = (lo + hi) // 2
child.sendline(str(mid)) # send number
index = child.expect([": ", EOF]) # read prompt
if index == 0: # got prompt
prompt = child.before
if "too high" in prompt:
hi = mid - 1 # guess > num
elif "too low" in prompt:
lo = mid + 1 # guess < num
elif index == 1: # EOF
assert "Congratulations" in child.before
child.close()
break
else:
print('not found')
child.terminate()
sys.exit(-child.signalstatus if child.signalstatus else child.exitstatus)
它有效,但它是二进制搜索(traditionally) there could be bugs。
以下是使用subprocess
模块进行比较的类似代码:
#!/usr/bin/env python
from __future__ import print_function
import sys
from subprocess import Popen, PIPE
p = Popen("./randomNumber", stdin=PIPE, stdout=PIPE,
bufsize=1, # line-buffering
universal_newlines=True) # enable text mode
p.stdout.readline() # discard welcome message: "This program gener...
readchar = lambda: p.stdout.read(1)
def read_until(char):
buf = []
for c in iter(readchar, char):
if not c: # EOF
break
buf.append(c)
else: # no EOF
buf.append(char)
return ''.join(buf).strip()
prompt = read_until(':') # read 1st prompt
lo, hi = 0, 100
while lo <= hi:
mid = (lo + hi) // 2
print(prompt, mid)
print(mid, file=p.stdin) # send number
prompt = read_until(':') # read prompt
if "Congratulations" in prompt:
print(prompt)
print(mid)
break # found
elif "too high" in prompt:
hi = mid - 1 # guess > num
elif "too low" in prompt:
lo = mid + 1 # guess < num
else:
print('not found')
p.kill()
for pipe in [p.stdin, p.stdout]:
try:
pipe.close()
except OSError:
pass
sys.exit(p.wait())
答案 1 :(得分:1)
我很确定在C ++程序中添加换行符会导致返回读取行。
答案 2 :(得分:0)
您可能必须明确关闭stdin
,因此子进程将停止挂起,我认为您的代码正在发生 - 这可以通过在终端上运行top并检查{{{ 1}}状态保持休眠状态,如果在执行所需的预期时间后使用0%CPU。
简而言之,如果您在randomnumber
电话之后立即添加rng.stdin.close()
,则可能会毫无问题地恢复。另一种选择是rng=subprocess(...)
并分别查看output=rng.communicate(stdin="%d\n" % i)
和output[0]
的{{1}}和output[1]
。您可以在stdout
here找到相关信息。